Sasi Math (Revised for 1024)

Scroll:Probability >> probability >> ps (4494)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Piggy bank contains 240 fifty-paise coins, 70 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 100 fifty-paise coins, 70 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 270 fifty-paise coins, 50 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 180 fifty-paise coins, 70 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 240 fifty-paise coins, 70 one-rupee coins, 35 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 280 fifty-paise coins, 75 one-rupee coins, 30 two-rupee coins and 20 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 180 fifty-paise coins, 65 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 150 fifty-paise coins, 75 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 240 fifty-paise coins, 65 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

10)

Piggy bank contains 110 fifty-paise coins, 55 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 240 fifty-paise coins, 70 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{48}{71}$

Will not be a five-ruoees coin = Answer: $\frac{69}{71}$

SOLUTION 1 :

Sample space, S has 355 coins which 10 fifty-paise coins, 70 one rupee coins, 35 two rupees coins and 10 five rupee coins.

n(S) = 240 + 70 + 35 + 10

= 355.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 355.

P(A) = n(A) / n(S) = $\frac{240}{355}$ = $\frac{48}{71}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 355 - 10 = 345.

P(B) = n(B) / n(S) = $\frac{345}{355}$ = $\frac{69}{71}$ .

Piggy bank contains 100 fifty-paise coins, 70 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{10}{21}$

Will not be a five-ruoees coin = Answer: $\frac{20}{21}$

SOLUTION 1 :

Sample space, S has 210 coins which 10 fifty-paise coins, 70 one rupee coins, 30 two rupees coins and 10 five rupee coins.

n(S) = 100 + 70 + 30 + 10

= 210.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 210.

P(A) = n(A) / n(S) = $\frac{100}{210}$ = $\frac{10}{21}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 210 - 10 = 200.

P(B) = n(B) / n(S) = $\frac{200}{210}$ = $\frac{20}{21}$ .

Piggy bank contains 270 fifty-paise coins, 50 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{54}{73}$

Will not be a five-ruoees coin = Answer: $\frac{70}{73}$

SOLUTION 1 :

Sample space, S has 365 coins which 15 fifty-paise coins, 50 one rupee coins, 30 two rupees coins and 15 five rupee coins.

n(S) = 270 + 50 + 30 + 15

= 365.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 365.

P(A) = n(A) / n(S) = $\frac{270}{365}$ = $\frac{54}{73}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 15

= 365 - 15 = 350.

P(B) = n(B) / n(S) = $\frac{350}{365}$ = $\frac{70}{73}$ .

Piggy bank contains 180 fifty-paise coins, 70 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{36}{59}$

Will not be a five-ruoees coin = Answer: $\frac{56}{59}$

SOLUTION 1 :

Sample space, S has 295 coins which 15 fifty-paise coins, 70 one rupee coins, 30 two rupees coins and 15 five rupee coins.

n(S) = 180 + 70 + 30 + 15

= 295.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 295.

P(A) = n(A) / n(S) = $\frac{180}{295}$ = $\frac{36}{59}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 15

= 295 - 15 = 280.

P(B) = n(B) / n(S) = $\frac{280}{295}$ = $\frac{56}{59}$ .

Piggy bank contains 240 fifty-paise coins, 70 one-rupee coins, 35 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{2}{3}$

Will not be a five-ruoees coin = Answer: $\frac{23}{24}$

SOLUTION 1 :

Sample space, S has 360 coins which 15 fifty-paise coins, 70 one rupee coins, 35 two rupees coins and 15 five rupee coins.

n(S) = 240 + 70 + 35 + 15

= 360.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 360.

P(A) = n(A) / n(S) = $\frac{240}{360}$ = $\frac{2}{3}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 15

= 360 - 15 = 345.

P(B) = n(B) / n(S) = $\frac{345}{360}$ = $\frac{23}{24}$ .

Piggy bank contains 280 fifty-paise coins, 75 one-rupee coins, 30 two-rupee coins and 20 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{56}{81}$

Will not be a five-ruoees coin = Answer: $\frac{77}{81}$

SOLUTION 1 :

Sample space, S has 405 coins which 20 fifty-paise coins, 75 one rupee coins, 30 two rupees coins and 20 five rupee coins.

n(S) = 280 + 75 + 30 + 20

= 405.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 405.

P(A) = n(A) / n(S) = $\frac{280}{405}$ = $\frac{56}{81}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 20

= 405 - 20 = 385.

P(B) = n(B) / n(S) = $\frac{385}{405}$ = $\frac{77}{81}$ .

Piggy bank contains 180 fifty-paise coins, 65 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{18}{29}$

Will not be a five-ruoees coin = Answer: $\frac{28}{29}$

SOLUTION 1 :

Sample space, S has 290 coins which 10 fifty-paise coins, 65 one rupee coins, 35 two rupees coins and 10 five rupee coins.

n(S) = 180 + 65 + 35 + 10

= 290.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 290.

P(A) = n(A) / n(S) = $\frac{180}{290}$ = $\frac{18}{29}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 290 - 10 = 280.

P(B) = n(B) / n(S) = $\frac{280}{290}$ = $\frac{28}{29}$ .

Piggy bank contains 150 fifty-paise coins, 75 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{5}{9}$

Will not be a five-ruoees coin = Answer: $\frac{26}{27}$

SOLUTION 1 :

Sample space, S has 270 coins which 10 fifty-paise coins, 75 one rupee coins, 35 two rupees coins and 10 five rupee coins.

n(S) = 150 + 75 + 35 + 10

= 270.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 270.

P(A) = n(A) / n(S) = $\frac{150}{270}$ = $\frac{5}{9}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 270 - 10 = 260.

P(B) = n(B) / n(S) = $\frac{260}{270}$ = $\frac{26}{27}$ .

Piggy bank contains 240 fifty-paise coins, 65 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{16}{23}$

Will not be a five-ruoees coin = Answer: $\frac{67}{69}$

SOLUTION 1 :

Sample space, S has 345 coins which 10 fifty-paise coins, 65 one rupee coins, 30 two rupees coins and 10 five rupee coins.

n(S) = 240 + 65 + 30 + 10

= 345.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 345.

P(A) = n(A) / n(S) = $\frac{240}{345}$ = $\frac{16}{23}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 345 - 10 = 335.

P(B) = n(B) / n(S) = $\frac{335}{345}$ = $\frac{67}{69}$ .

10)

Piggy bank contains 110 fifty-paise coins, 55 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{22}{41}$

Will not be a five-ruoees coin = Answer: $\frac{39}{41}$

SOLUTION 1 :

Sample space, S has 205 coins which 10 fifty-paise coins, 55 one rupee coins, 30 two rupees coins and 10 five rupee coins.

n(S) = 110 + 55 + 30 + 10

= 205.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 205.

P(A) = n(A) / n(S) = $\frac{110}{205}$ = $\frac{22}{41}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 205 - 10 = 195.

P(B) = n(B) / n(S) = $\frac{195}{205}$ = $\frac{39}{41}$ .