Sasi Math (Revised for 1024)

Scroll:Probability >> probability >> ps (4493)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A bag consists of 148 shirts of which 94 are good, 23 have minor defects and 9 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 130 shirts of which 83 are good, 23 have minor defects and 5 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 126 shirts of which 79 are good, 25 have minor defects and 9 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 131 shirts of which 94 are good, 16 have minor defects and 5 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 129 shirts of which 74 are good, 23 have minor defects and 9 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 130 shirts of which 72 are good, 23 have minor defects and 8 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 148 shirts of which 98 are good, 21 have minor defects and 10 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 139 shirts of which 80 are good, 23 have minor defects and 9 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 127 shirts of which 84 are good, 15 have minor defects and 11 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

10)

A bag consists of 133 shirts of which 75 are good, 25 have minor defects and 10 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A = Answer: $\frac{47}{74}$

B = Answer: $\frac{117}{148}$

SOLUTION 1 :

A bag consists of 148 shirts.

n(S) = 148.

(i) ..... A trader A will accept only good shirts

n(A) = 94.

P(A) = n(A) / a(S) = $\frac{94}{148}$ = $\frac{47}{74}$ .

A will accept only good shirts = $\frac{47}{74}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 94 + 23 ( B accepts good and minor defects shirts)

= 117.

P(B) = n(B) / n(S) = $\frac{117}{148}$ = $\frac{117}{148}$

Trader B will accept the shirts which have minor defects = $\frac{117}{148}$ .

A = Answer: $\frac{83}{130}$

B = Answer: $\frac{53}{65}$

SOLUTION 1 :

A bag consists of 130 shirts.

n(S) = 130.

(i) ..... A trader A will accept only good shirts

n(A) = 83.

P(A) = n(A) / a(S) = $\frac{83}{130}$ = $\frac{83}{130}$ .

A will accept only good shirts = $\frac{83}{130}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 83 + 23 ( B accepts good and minor defects shirts)

= 106.

P(B) = n(B) / n(S) = $\frac{106}{130}$ = $\frac{53}{65}$

Trader B will accept the shirts which have minor defects = $\frac{53}{65}$ .

A = Answer: $\frac{79}{126}$

B = Answer: $\frac{52}{63}$

SOLUTION 1 :

A bag consists of 126 shirts.

n(S) = 126.

(i) ..... A trader A will accept only good shirts

n(A) = 79.

P(A) = n(A) / a(S) = $\frac{79}{126}$ = $\frac{79}{126}$ .

A will accept only good shirts = $\frac{79}{126}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 79 + 25 ( B accepts good and minor defects shirts)

= 104.

P(B) = n(B) / n(S) = $\frac{104}{126}$ = $\frac{52}{63}$

Trader B will accept the shirts which have minor defects = $\frac{52}{63}$ .

A = Answer: $\frac{94}{131}$

B = Answer: $\frac{110}{131}$

SOLUTION 1 :

A bag consists of 131 shirts.

n(S) = 131.

(i) ..... A trader A will accept only good shirts

n(A) = 94.

P(A) = n(A) / a(S) = $\frac{94}{131}$ = $\frac{94}{131}$ .

A will accept only good shirts = $\frac{94}{131}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 94 + 16 ( B accepts good and minor defects shirts)

= 110.

P(B) = n(B) / n(S) = $\frac{110}{131}$ = $\frac{110}{131}$

Trader B will accept the shirts which have minor defects = $\frac{110}{131}$ .

A = Answer: $\frac{74}{129}$

B = Answer: $\frac{97}{129}$

SOLUTION 1 :

A bag consists of 129 shirts.

n(S) = 129.

(i) ..... A trader A will accept only good shirts

n(A) = 74.

P(A) = n(A) / a(S) = $\frac{74}{129}$ = $\frac{74}{129}$ .

A will accept only good shirts = $\frac{74}{129}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 74 + 23 ( B accepts good and minor defects shirts)

= 97.

P(B) = n(B) / n(S) = $\frac{97}{129}$ = $\frac{97}{129}$

Trader B will accept the shirts which have minor defects = $\frac{97}{129}$ .

A = Answer: $\frac{36}{65}$

B = Answer: $\frac{19}{26}$

SOLUTION 1 :

A bag consists of 130 shirts.

n(S) = 130.

(i) ..... A trader A will accept only good shirts

n(A) = 72.

P(A) = n(A) / a(S) = $\frac{72}{130}$ = $\frac{36}{65}$ .

A will accept only good shirts = $\frac{36}{65}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 72 + 23 ( B accepts good and minor defects shirts)

= 95.

P(B) = n(B) / n(S) = $\frac{95}{130}$ = $\frac{19}{26}$

Trader B will accept the shirts which have minor defects = $\frac{19}{26}$ .

A = Answer: $\frac{49}{74}$

B = Answer: $\frac{119}{148}$

SOLUTION 1 :

A bag consists of 148 shirts.

n(S) = 148.

(i) ..... A trader A will accept only good shirts

n(A) = 98.

P(A) = n(A) / a(S) = $\frac{98}{148}$ = $\frac{49}{74}$ .

A will accept only good shirts = $\frac{49}{74}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 98 + 21 ( B accepts good and minor defects shirts)

= 119.

P(B) = n(B) / n(S) = $\frac{119}{148}$ = $\frac{119}{148}$

Trader B will accept the shirts which have minor defects = $\frac{119}{148}$ .

A = Answer: $\frac{80}{139}$

B = Answer: $\frac{103}{139}$

SOLUTION 1 :

A bag consists of 139 shirts.

n(S) = 139.

(i) ..... A trader A will accept only good shirts

n(A) = 80.

P(A) = n(A) / a(S) = $\frac{80}{139}$ = $\frac{80}{139}$ .

A will accept only good shirts = $\frac{80}{139}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 80 + 23 ( B accepts good and minor defects shirts)

= 103.

P(B) = n(B) / n(S) = $\frac{103}{139}$ = $\frac{103}{139}$

Trader B will accept the shirts which have minor defects = $\frac{103}{139}$ .

A = Answer: $\frac{84}{127}$

B = Answer: $\frac{99}{127}$

SOLUTION 1 :

A bag consists of 127 shirts.

n(S) = 127.

(i) ..... A trader A will accept only good shirts

n(A) = 84.

P(A) = n(A) / a(S) = $\frac{84}{127}$ = $\frac{84}{127}$ .

A will accept only good shirts = $\frac{84}{127}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 84 + 15 ( B accepts good and minor defects shirts)

= 99.

P(B) = n(B) / n(S) = $\frac{99}{127}$ = $\frac{99}{127}$

Trader B will accept the shirts which have minor defects = $\frac{99}{127}$ .

10)

A = Answer: $\frac{75}{133}$

B = Answer: $\frac{100}{133}$

SOLUTION 1 :

A bag consists of 133 shirts.

n(S) = 133.

(i) ..... A trader A will accept only good shirts

n(A) = 75.

P(A) = n(A) / a(S) = $\frac{75}{133}$ = $\frac{75}{133}$ .

A will accept only good shirts = $\frac{75}{133}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 75 + 25 ( B accepts good and minor defects shirts)

= 100.

P(B) = n(B) / n(S) = $\frac{100}{133}$ = $\frac{100}{133}$

Trader B will accept the shirts which have minor defects = $\frac{100}{133}$ .