Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
1) Using laws of exponents, simplify in the exponential form t1xt6xt3xt3 t to the power Answer:_______________ |
2) Using laws of exponents, simplify in the exponential form y2xy2xy4xy1 y to the power Answer:_______________ |
3) Using laws of exponents, simplify in the exponential form e3xe5xe2xe1 e to the power Answer:_______________ |
4) Using laws of exponents, simplify in the exponential form b4xb4xb2xb8 b to the power Answer:_______________ |
5) Using laws of exponents, simplify in the exponential form z1xz2xz2xz3 z to the power Answer:_______________ |
6) Using laws of exponents, simplify in the exponential form h5xh2xh3xh4 h to the power Answer:_______________ |
7) Using laws of exponents, simplify in the exponential form i4xi2xi4xi0 i to the power Answer:_______________ |
8) Using laws of exponents, simplify in the exponential form v5xv3xv3xv2 v to the power Answer:_______________ |
9) Using laws of exponents, simplify in the exponential form k0xk3xk2xk5 k to the power Answer:_______________ |
10) Using laws of exponents, simplify in the exponential form l2xl2xl2xl8 l to the power Answer:_______________ |
1) Using laws of exponents, simplify in the exponential form a1xa6xa3xa3 a to the power Answer: 13 SOLUTION 1 : Soln : a1xa6xa3xa3 = a(1+6+3+3) = a13 |
2) Using laws of exponents, simplify in the exponential form u2xu2xu4xu1 u to the power Answer: 9 SOLUTION 1 : Soln : u2xu2xu4xu1 = u(2+2+4+1) = u9 |
3) Using laws of exponents, simplify in the exponential form j3xj5xj2xj1 j to the power Answer: 11 SOLUTION 1 : Soln : j3xj5xj2xj1 = j(3+5+2+1) = j11 |
4) Using laws of exponents, simplify in the exponential form v4xv4xv2xv8 v to the power Answer: 18 SOLUTION 1 : Soln : v4xv4xv2xv8 = v(4+4+2+8) = v18 |
5) Using laws of exponents, simplify in the exponential form v1xv2xv2xv3 v to the power Answer: 8 SOLUTION 1 : Soln : v1xv2xv2xv3 = v(1+2+2+3) = v8 |
6) Using laws of exponents, simplify in the exponential form k5xk2xk3xk4 k to the power Answer: 14 SOLUTION 1 : Soln : k5xk2xk3xk4 = k(5+2+3+4) = k14 |
7) Using laws of exponents, simplify in the exponential form o4xo2xo4xo0 o to the power Answer: 10 SOLUTION 1 : Soln : o4xo2xo4xo0 = o(4+2+4+0) = o10 |
8) Using laws of exponents, simplify in the exponential form x5xx3xx3xx2 x to the power Answer: 13 SOLUTION 1 : Soln : x5xx3xx3xx2 = x(5+3+3+2) = x13 |
9) Using laws of exponents, simplify in the exponential form l0xl3xl2xl5 l to the power Answer: 10 SOLUTION 1 : Soln : l0xl3xl2xl5 = l(0+3+2+5) = l10 |
10) Using laws of exponents, simplify in the exponential form s2xs2xs2xs8 s to the power Answer: 14 SOLUTION 1 : Soln : s2xs2xs2xs8 = s(2+2+2+8) = s14 |