Sasi Math (Revised for 1024)

Scroll:Algebra >> Term III Ex 1.2 >> saq (4451)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

6 times a number decreased by 6 gives 60. Find the number.

Answer:_______________

5 times a number decreased by 10 gives 25. Find the number.

Answer:_______________

2 times a number decreased by 8 gives 28. Find the number.

Answer:_______________

3 times a number decreased by 3 gives 24. Find the number.

Answer:_______________

4 times a number decreased by 8 gives 20. Find the number.

Answer:_______________

6 times a number decreased by 6 gives 30. Find the number.

Answer:_______________

5 times a number decreased by 10 gives 20. Find the number.

Answer:_______________

2 times a number decreased by 2 gives 20. Find the number.

Answer:_______________

3 times a number decreased by 6 gives 24. Find the number.

Answer:_______________

10)

4 times a number decreased by 8 gives 60. Find the number.

Answer:_______________

6 times a number decreased by 6 gives 60. Find the number.

Answer: 11

SOLUTION 1 :

Let the required number be y. ⇒ 6 times = 6y

Given:

6y - 6 = 60

⇒ 6y = 60 + 6 ( on transposing - 6 becomes + 6 )

⇒ 6y = 66

$\frac{6y}{6}$ = $\frac{66}{6}$ ( Dividing by 6, both the sides )

y = 11.

Hence, the required number is 11.

5 times a number decreased by 10 gives 25. Find the number.

Answer: 7

SOLUTION 1 :

Let the required number be x. ⇒ 5 times = 5x

Given:

5x - 10 = 25

⇒ 5x = 25 + 10 ( on transposing - 10 becomes + 10 )

⇒ 5x = 35

$\frac{5x}{5}$ = $\frac{35}{5}$ ( Dividing by 5, both the sides )

x = 7.

Hence, the required number is 7.

2 times a number decreased by 8 gives 28. Find the number.

Answer: 18

SOLUTION 1 :

Let the required number be y. ⇒ 2 times = 2y

Given:

2y - 8 = 28

⇒ 2y = 28 + 8 ( on transposing - 8 becomes + 8 )

⇒ 2y = 36

$\frac{2y}{2}$ = $\frac{36}{2}$ ( Dividing by 2, both the sides )

y = 18.

Hence, the required number is 18.

3 times a number decreased by 3 gives 24. Find the number.

Answer: 9

SOLUTION 1 :

Let the required number be x. ⇒ 3 times = 3x

Given:

3x - 3 = 24

⇒ 3x = 24 + 3 ( on transposing - 3 becomes + 3 )

⇒ 3x = 27

$\frac{3x}{3}$ = $\frac{27}{3}$ ( Dividing by 3, both the sides )

x = 9.

Hence, the required number is 9.

4 times a number decreased by 8 gives 20. Find the number.

Answer: 7

SOLUTION 1 :

Let the required number be y. ⇒ 4 times = 4y

Given:

4y - 8 = 20

⇒ 4y = 20 + 8 ( on transposing - 8 becomes + 8 )

⇒ 4y = 28

$\frac{4y}{4}$ = $\frac{28}{4}$ ( Dividing by 4, both the sides )

y = 7.

Hence, the required number is .

6 times a number decreased by 6 gives 30. Find the number.

Answer: 6

SOLUTION 1 :

Let the required number be y. ⇒ 6 times = 6y

Given:

6y - 6 = 30

⇒ 6y = 30 + 6 ( on transposing - 6 becomes + 6 )

⇒ 6y = 36

$\frac{6y}{6}$ = $\frac{36}{6}$ ( Dividing by 6, both the sides )

y = 6.

Hence, the required number is 6.

5 times a number decreased by 10 gives 20. Find the number.

Answer: 6

SOLUTION 1 :

Let the required number be x. ⇒ 5 times = 5x

Given:

5x - 10 = 20

⇒ 5x = 20 + 10 ( on transposing - 10 becomes + 10 )

⇒ 5x = 30

$\frac{5x}{5}$ = $\frac{30}{5}$ ( Dividing by 5, both the sides )

x = 6.

Hence, the required number is 6.

2 times a number decreased by 2 gives 20. Find the number.

Answer: 11

SOLUTION 1 :

Let the required number be y. ⇒ 2 times = 2y

Given:

2y - 2 = 20

⇒ 2y = 20 + 2 ( on transposing - 2 becomes + 2 )

⇒ 2y = 22

$\frac{2y}{2}$ = $\frac{22}{2}$ ( Dividing by 2, both the sides )

y = 11.

Hence, the required number is 11.

3 times a number decreased by 6 gives 24. Find the number.

Answer: 10

SOLUTION 1 :

Let the required number be y. ⇒ 3 times = 3y

Given:

3y - 6 = 24

⇒ 3y = 24 + 6 ( on transposing - 6 becomes + 6 )

⇒ 3y = 30

$\frac{3y}{3}$ = $\frac{30}{3}$ ( Dividing by 3, both the sides )

y = 10.

Hence, the required number is 10.

10)

4 times a number decreased by 8 gives 60. Find the number.

Answer: 17

SOLUTION 1 :

Let the required number be x. ⇒ 4 times = 4x

Given:

4x - 8 = 60

⇒ 4x = 60 + 8 ( on transposing - 8 becomes + 8 )

⇒ 4x = 68

$\frac{4x}{4}$ = $\frac{68}{4}$ ( Dividing by 4, both the sides )

x = 17.

Hence, the required number is .