Sasi Math (Revised for 1024)

Scroll:Measurements >> area >> saq (4345)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

In a right triangular ground, the sides adjacent to the right angle are 10 m and 25m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 19 m and 26m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 15 m and 27m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 20 m and 29m. Find the cost of the cementing the grount at 7 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 14 m and 30m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 20 m and 27m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 10 m and 29m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 13 m and 26m. Find the cost of the cementing the grount at 7 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 17 m and 30m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

10)

In a right triangular ground, the sides adjacent to the right angle are 20 m and 27m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 10 m and 25m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer: 375

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (10 x 25)

= $\frac{1}{2}$ x 250

= 125 m²

Cost of cementing 1 sq,m = 3

Cost of cementing 3 sq. m = 125 x 3

= 375

In a right triangular ground, the sides adjacent to the right angle are 19 m and 26m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer: 494

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (19 x 26)

= $\frac{1}{2}$ x 494

= 247 m²

Cost of cementing 1 sq,m = 2

Cost of cementing 2 sq. m = 247 x 2

= 494

In a right triangular ground, the sides adjacent to the right angle are 15 m and 27m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer: 405

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (15 x 27)

= $\frac{1}{2}$ x 405

= 202.5 m²

Cost of cementing 1 sq,m = 2

Cost of cementing 2 sq. m = 202.5 x 2

= 405

In a right triangular ground, the sides adjacent to the right angle are 20 m and 29m. Find the cost of the cementing the grount at 7 per sq,.m.

Answer: 2030

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (20 x 29)

= $\frac{1}{2}$ x 580

= 290 m²

Cost of cementing 1 sq,m = 7

Cost of cementing 7 sq. m = 290 x 7

= 2030

In a right triangular ground, the sides adjacent to the right angle are 14 m and 30m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 1050

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (14 x 30)

= $\frac{1}{2}$ x 420

= 210 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 210 x 5

= 1050

In a right triangular ground, the sides adjacent to the right angle are 20 m and 27m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 2700

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (20 x 27)

= $\frac{1}{2}$ x 540

= 270 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 270 x 10

= 2700

In a right triangular ground, the sides adjacent to the right angle are 10 m and 29m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer: 870

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (10 x 29)

= $\frac{1}{2}$ x 290

= 145 m²

Cost of cementing 1 sq,m = 6

Cost of cementing 6 sq. m = 145 x 6

= 870

In a right triangular ground, the sides adjacent to the right angle are 13 m and 26m. Find the cost of the cementing the grount at 7 per sq,.m.

Answer: 1183

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (13 x 26)

= $\frac{1}{2}$ x 338

= 169 m²

Cost of cementing 1 sq,m = 7

Cost of cementing 7 sq. m = 169 x 7

= 1183

In a right triangular ground, the sides adjacent to the right angle are 17 m and 30m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 1275

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (17 x 30)

= $\frac{1}{2}$ x 510

= 255 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 255 x 5

= 1275

10)

In a right triangular ground, the sides adjacent to the right angle are 20 m and 27m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer: 1620

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (20 x 27)

= $\frac{1}{2}$ x 540

= 270 m²

Cost of cementing 1 sq,m = 6

Cost of cementing 6 sq. m = 270 x 6

= 1620