Sasi Math (Revised for 1024)

Scroll:Measurements >> area >> saq (4345)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

In a right triangular ground, the sides adjacent to the right angle are 19 m and 29m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 14 m and 25m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 15 m and 26m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 27m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 13 m and 28m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 19 m and 26m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 25m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 16 m and 29m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 14 m and 26m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer:_______________

10)

In a right triangular ground, the sides adjacent to the right angle are 13 m and 29m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 19 m and 29m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer: 1102

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (19 x 29)

= $\frac{1}{2}$ x 551

= 275.5 m²

Cost of cementing 1 sq,m = 4

Cost of cementing 4 sq. m = 275.5 x 4

= 1102

In a right triangular ground, the sides adjacent to the right angle are 14 m and 25m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer: 700

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (14 x 25)

= $\frac{1}{2}$ x 350

= 175 m²

Cost of cementing 1 sq,m = 4

Cost of cementing 4 sq. m = 175 x 4

= 700

In a right triangular ground, the sides adjacent to the right angle are 15 m and 26m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer: 390

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (15 x 26)

= $\frac{1}{2}$ x 390

= 195 m²

Cost of cementing 1 sq,m = 2

Cost of cementing 2 sq. m = 195 x 2

= 390

In a right triangular ground, the sides adjacent to the right angle are 12 m and 27m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer: 972

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 27)

= $\frac{1}{2}$ x 324

= 162 m²

Cost of cementing 1 sq,m = 6

Cost of cementing 6 sq. m = 162 x 6

= 972

In a right triangular ground, the sides adjacent to the right angle are 13 m and 28m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer: 546

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (13 x 28)

= $\frac{1}{2}$ x 364

= 182 m²

Cost of cementing 1 sq,m = 3

Cost of cementing 3 sq. m = 182 x 3

= 546

In a right triangular ground, the sides adjacent to the right angle are 19 m and 26m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer: 1482

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (19 x 26)

= $\frac{1}{2}$ x 494

= 247 m²

Cost of cementing 1 sq,m = 6

Cost of cementing 6 sq. m = 247 x 6

= 1482

In a right triangular ground, the sides adjacent to the right angle are 12 m and 25m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer: 1350

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 25)

= $\frac{1}{2}$ x 300

= 150 m²

Cost of cementing 1 sq,m = 9

Cost of cementing 9 sq. m = 150 x 9

= 1350

In a right triangular ground, the sides adjacent to the right angle are 16 m and 29m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 1160

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (16 x 29)

= $\frac{1}{2}$ x 464

= 232 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 232 x 5

= 1160

In a right triangular ground, the sides adjacent to the right angle are 14 m and 26m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer: 1638

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (14 x 26)

= $\frac{1}{2}$ x 364

= 182 m²

Cost of cementing 1 sq,m = 9

Cost of cementing 9 sq. m = 182 x 9

= 1638

10)

In a right triangular ground, the sides adjacent to the right angle are 13 m and 29m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer: 1508

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (13 x 29)

= $\frac{1}{2}$ x 377

= 188.5 m²

Cost of cementing 1 sq,m = 8

Cost of cementing 8 sq. m = 188.5 x 8

= 1508