Sasi Math (Revised for 1024)

Scroll:Measurements >> area >> saq (4345)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

In a right triangular ground, the sides adjacent to the right angle are 17 m and 28m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 29m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 17 m and 30m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 27m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 18 m and 29m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 16 m and 27m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 15 m and 28m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 11 m and 30m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 14 m and 30m. Find the cost of the cementing the grount at 7 per sq,.m.

Answer:_______________

10)

In a right triangular ground, the sides adjacent to the right angle are 15 m and 28m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 17 m and 28m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 1190

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (17 x 28)

= $\frac{1}{2}$ x 476

= 238 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 238 x 5

= 1190

In a right triangular ground, the sides adjacent to the right angle are 12 m and 29m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer: 522

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 29)

= $\frac{1}{2}$ x 348

= 174 m²

Cost of cementing 1 sq,m = 3

Cost of cementing 3 sq. m = 174 x 3

= 522

In a right triangular ground, the sides adjacent to the right angle are 17 m and 30m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 1275

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (17 x 30)

= $\frac{1}{2}$ x 510

= 255 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 255 x 5

= 1275

In a right triangular ground, the sides adjacent to the right angle are 12 m and 27m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer: 972

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 27)

= $\frac{1}{2}$ x 324

= 162 m²

Cost of cementing 1 sq,m = 6

Cost of cementing 6 sq. m = 162 x 6

= 972

In a right triangular ground, the sides adjacent to the right angle are 18 m and 29m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer: 2088

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 29)

= $\frac{1}{2}$ x 522

= 261 m²

Cost of cementing 1 sq,m = 8

Cost of cementing 8 sq. m = 261 x 8

= 2088

In a right triangular ground, the sides adjacent to the right angle are 16 m and 27m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 2160

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (16 x 27)

= $\frac{1}{2}$ x 432

= 216 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 216 x 10

= 2160

In a right triangular ground, the sides adjacent to the right angle are 15 m and 28m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer: 1890

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (15 x 28)

= $\frac{1}{2}$ x 420

= 210 m²

Cost of cementing 1 sq,m = 9

Cost of cementing 9 sq. m = 210 x 9

= 1890

In a right triangular ground, the sides adjacent to the right angle are 11 m and 30m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer: 1485

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (11 x 30)

= $\frac{1}{2}$ x 330

= 165 m²

Cost of cementing 1 sq,m = 9

Cost of cementing 9 sq. m = 165 x 9

= 1485

In a right triangular ground, the sides adjacent to the right angle are 14 m and 30m. Find the cost of the cementing the grount at 7 per sq,.m.

Answer: 1470

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (14 x 30)

= $\frac{1}{2}$ x 420

= 210 m²

Cost of cementing 1 sq,m = 7

Cost of cementing 7 sq. m = 210 x 7

= 1470

10)

In a right triangular ground, the sides adjacent to the right angle are 15 m and 28m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer: 840

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (15 x 28)

= $\frac{1}{2}$ x 420

= 210 m²

Cost of cementing 1 sq,m = 4

Cost of cementing 4 sq. m = 210 x 4

= 840