Sasi Math (Revised for 1024)

Scroll:Life mathematics >> profit and loss >> saq (4321)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Two taps can fill a tank in 60 min &80 minutes.Another tap can empty it in 48 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 150 min &200 minutes.Another tap can empty it in 120 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 90 min &120 minutes.Another tap can empty it in 72 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 30 min &40 minutes.Another tap can empty it in 24 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 240 min &320 minutes.Another tap can empty it in 192 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 180 min &240 minutes.Another tap can empty it in 144 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 210 min &280 minutes.Another tap can empty it in 168 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 120 min &160 minutes.Another tap can empty it in 96 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 180 min &240 minutes.Another tap can empty it in 144 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

10)

Two taps can fill a tank in 60 min &80 minutes.Another tap can empty it in 48 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

hour

Answer:_______________

Two taps can fill a tank in 60 min &80 minutes.Another tap can empty it in 48 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 2 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{60}$

Quantity of water filled by the second tap in one minute = $\frac{1}{80}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{48}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{60}$ + $\frac{1}{80}$ - $\frac{1}{48}$ (240 is LCM)

= (4 + 3 - 5) / 240

= $\frac{2}{240}$

= $\frac{1}{120}$

Time taken to fill the tank = 1/( $\frac{1}{120}$ )

= 120 min / 60

= 2 hr

Two taps can fill a tank in 150 min &200 minutes.Another tap can empty it in 120 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 5 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{150}$

Quantity of water filled by the second tap in one minute = $\frac{1}{200}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{120}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{150}$ + $\frac{1}{200}$ - $\frac{1}{120}$ (600 is LCM)

= (4 + 3 - 5) / 600

= $\frac{2}{600}$

= $\frac{1}{300}$

Time taken to fill the tank = 1/( $\frac{1}{300}$ )

= 300 min / 60

= 5 hr

Two taps can fill a tank in 90 min &120 minutes.Another tap can empty it in 72 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 3 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{90}$

Quantity of water filled by the second tap in one minute = $\frac{1}{120}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{72}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{90}$ + $\frac{1}{120}$ - $\frac{1}{72}$ (360 is LCM)

= (4 + 3 - 5) / 360

= $\frac{2}{360}$

= $\frac{1}{180}$

Time taken to fill the tank = 1/( $\frac{1}{180}$ )

= 180 min / 60

= 3 hr

Two taps can fill a tank in 30 min &40 minutes.Another tap can empty it in 24 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 1 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{30}$

Quantity of water filled by the second tap in one minute = $\frac{1}{40}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{24}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{30}$ + $\frac{1}{40}$ - $\frac{1}{24}$ (120 is LCM)

= (4 + 3 - 5) / 120

= $\frac{2}{120}$

= $\frac{1}{60}$

Time taken to fill the tank = 1/( $\frac{1}{60}$ )

= 60 min / 60

= 1 hr

Two taps can fill a tank in 240 min &320 minutes.Another tap can empty it in 192 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 8 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{240}$

Quantity of water filled by the second tap in one minute = $\frac{1}{320}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{192}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{240}$ + $\frac{1}{320}$ - $\frac{1}{192}$ (960 is LCM)

= (4 + 3 - 5) / 960

= $\frac{2}{960}$

= $\frac{1}{480}$

Time taken to fill the tank = 1/( $\frac{1}{480}$ )

= 480 min / 60

= 8 hr

Two taps can fill a tank in 180 min &240 minutes.Another tap can empty it in 144 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 6 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{180}$

Quantity of water filled by the second tap in one minute = $\frac{1}{240}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{144}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{180}$ + $\frac{1}{240}$ - $\frac{1}{144}$ (720 is LCM)

= (4 + 3 - 5) / 720

= $\frac{2}{720}$

= $\frac{1}{360}$

Time taken to fill the tank = 1/( $\frac{1}{360}$ )

= 360 min / 60

= 6 hr

Two taps can fill a tank in 210 min &280 minutes.Another tap can empty it in 168 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 7 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{210}$

Quantity of water filled by the second tap in one minute = $\frac{1}{280}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{168}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{210}$ + $\frac{1}{280}$ - $\frac{1}{168}$ (840 is LCM)

= (4 + 3 - 5) / 840

= $\frac{2}{840}$

= $\frac{1}{420}$

Time taken to fill the tank = 1/( $\frac{1}{420}$ )

= 420 min / 60

= 7 hr

Two taps can fill a tank in 120 min &160 minutes.Another tap can empty it in 96 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 4 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{120}$

Quantity of water filled by the second tap in one minute = $\frac{1}{160}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{96}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{120}$ + $\frac{1}{160}$ - $\frac{1}{96}$ (480 is LCM)

= (4 + 3 - 5) / 480

= $\frac{2}{480}$

= $\frac{1}{240}$

Time taken to fill the tank = 1/( $\frac{1}{240}$ )

= 240 min / 60

= 4 hr

Two taps can fill a tank in 180 min &240 minutes.Another tap can empty it in 144 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 6 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{180}$

Quantity of water filled by the second tap in one minute = $\frac{1}{240}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{144}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{180}$ + $\frac{1}{240}$ - $\frac{1}{144}$ (720 is LCM)

= (4 + 3 - 5) / 720

= $\frac{2}{720}$

= $\frac{1}{360}$

Time taken to fill the tank = 1/( $\frac{1}{360}$ )

= 360 min / 60

= 6 hr

10)

Two taps can fill a tank in 60 min &80 minutes.Another tap can empty it in 48 minutes. If the tank is empty & all the three taps are kept open,in how much time the tank will be filled

Answer: 2 hour

SOLUTION 1 :

Given:

Quantity of water filled by the first tap in one minute= $\frac{1}{60}$

Quantity of water filled by the second tap in one minute = $\frac{1}{80}$

Quantity of water emptied by the third tap in one minute = $\frac{1}{48}$

Quantitynof water filled in one minute , when all the 3 taps are opened = $\frac{1}{60}$ + $\frac{1}{80}$ - $\frac{1}{48}$ (240 is LCM)

= (4 + 3 - 5) / 240

= $\frac{2}{240}$

= $\frac{1}{120}$

Time taken to fill the tank = 1/( $\frac{1}{120}$ )

= 120 min / 60

= 2 hr