Sasi Math (Revised for 1024)

Scroll:Life mathematics >> profit and loss >> saq (4310)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Imran deposits 592 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 242 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 314 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 209 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 241 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 486 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 547 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 401 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 596 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

10)

Imran deposits 554 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 592 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 14652

SOLUTION 1 :

Given:

P = 592

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (592 x 25 x $\frac{3)}{100}$

= $\frac{44400}{100}$

= 444

A = (P x n) +I

= (592 x 24) + 444

= 14208 + 444

= 14652

Imran deposits 242 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 6050

SOLUTION 1 :

Given:

P = 242

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (242 x 25 x $\frac{4)}{100}$

= $\frac{24200}{100}$

= 242

A = (P x n) +I

= (242 x 24) + 242

= 5808 + 242

= 6050

Imran deposits 314 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 7693

SOLUTION 1 :

Given:

P = 314

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (314 x 25 x $\frac{2)}{100}$

= $\frac{15700}{100}$

= 157

A = (P x n) +I

= (314 x 24) + 157

= 7536 + 157

= 7693

Imran deposits 209 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 5329.5

SOLUTION 1 :

Given:

P = 209

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (209 x 25 x $\frac{6)}{100}$

= $\frac{31350}{100}$

= 313.5

A = (P x n) +I

= (209 x 24) + 313.5

= 5016 + 313.5

= 5329.5

Imran deposits 241 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 6025

SOLUTION 1 :

Given:

P = 241

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (241 x 25 x $\frac{4)}{100}$

= $\frac{24100}{100}$

= 241

A = (P x n) +I

= (241 x 24) + 241

= 5784 + 241

= 6025

Imran deposits 486 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 12393

SOLUTION 1 :

Given:

P = 486

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (486 x 25 x $\frac{6)}{100}$

= $\frac{72900}{100}$

= 729

A = (P x n) +I

= (486 x 24) + 729

= 11664 + 729

= 12393

Imran deposits 547 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 13675

SOLUTION 1 :

Given:

P = 547

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (547 x 25 x $\frac{4)}{100}$

= $\frac{54700}{100}$

= 547

A = (P x n) +I

= (547 x 24) + 547

= 13128 + 547

= 13675

Imran deposits 401 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 9924.75

SOLUTION 1 :

Given:

P = 401

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (401 x 25 x $\frac{3)}{100}$

= $\frac{30075}{100}$

= 300.75

A = (P x n) +I

= (401 x 24) + 300.75

= 9624 + 300.75

= 9924.75

Imran deposits 596 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 15049

SOLUTION 1 :

Given:

P = 596

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (596 x 25 x $\frac{5)}{100}$

= $\frac{74500}{100}$

= 745

A = (P x n) +I

= (596 x 24) + 745

= 14304 + 745

= 15049

10)

Imran deposits 554 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 13850

SOLUTION 1 :

Given:

P = 554

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (554 x 25 x $\frac{4)}{100}$

= $\frac{55400}{100}$

= 554

A = (P x n) +I

= (554 x 24) + 554

= 13296 + 554

= 13850