Sasi Math (Revised for 1024)

Scroll:Life mathematics >> profit and loss >> saq (4310)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Imran deposits 549 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 260 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 264 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 374 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 285 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 584 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 230 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 253 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 567 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

10)

Imran deposits 434 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 549 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 13450.5

SOLUTION 1 :

Given:

P = 549

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (549 x 25 x $\frac{2)}{100}$

= $\frac{27450}{100}$

= 274.5

A = (P x n) +I

= (549 x 24) + 274.5

= 13176 + 274.5

= 13450.5

Imran deposits 260 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 6565

SOLUTION 1 :

Given:

P = 260

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (260 x 25 x $\frac{5)}{100}$

= $\frac{32500}{100}$

= 325

A = (P x n) +I

= (260 x 24) + 325

= 6240 + 325

= 6565

Imran deposits 264 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 6600

SOLUTION 1 :

Given:

P = 264

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (264 x 25 x $\frac{4)}{100}$

= $\frac{26400}{100}$

= 264

A = (P x n) +I

= (264 x 24) + 264

= 6336 + 264

= 6600

Imran deposits 374 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 9256.5

SOLUTION 1 :

Given:

P = 374

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (374 x 25 x $\frac{3)}{100}$

= $\frac{28050}{100}$

= 280.5

A = (P x n) +I

= (374 x 24) + 280.5

= 8976 + 280.5

= 9256.5

Imran deposits 285 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 7196.25

SOLUTION 1 :

Given:

P = 285

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (285 x 25 x $\frac{5)}{100}$

= $\frac{35625}{100}$

= 356.25

A = (P x n) +I

= (285 x 24) + 356.25

= 6840 + 356.25

= 7196.25

Imran deposits 584 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 14454

SOLUTION 1 :

Given:

P = 584

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (584 x 25 x $\frac{3)}{100}$

= $\frac{43800}{100}$

= 438

A = (P x n) +I

= (584 x 24) + 438

= 14016 + 438

= 14454

Imran deposits 230 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 5750

SOLUTION 1 :

Given:

P = 230

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (230 x 25 x $\frac{4)}{100}$

= $\frac{23000}{100}$

= 230

A = (P x n) +I

= (230 x 24) + 230

= 5520 + 230

= 5750

Imran deposits 253 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 6198.5

SOLUTION 1 :

Given:

P = 253

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (253 x 25 x $\frac{2)}{100}$

= $\frac{12650}{100}$

= 126.5

A = (P x n) +I

= (253 x 24) + 126.5

= 6072 + 126.5

= 6198.5

Imran deposits 567 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 14175

SOLUTION 1 :

Given:

P = 567

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (567 x 25 x $\frac{4)}{100}$

= $\frac{56700}{100}$

= 567

A = (P x n) +I

= (567 x 24) + 567

= 13608 + 567

= 14175

10)

Imran deposits 434 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 10633

SOLUTION 1 :

Given:

P = 434

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (434 x 25 x $\frac{2)}{100}$

= $\frac{21700}{100}$

= 217

A = (P x n) +I

= (434 x 24) + 217

= 10416 + 217

= 10633