Sasi Math (Revised for 1024)

Scroll:Life mathematics >> profit and loss >> saq (4310)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Imran deposits 573 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 221 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 499 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 364 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 593 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 231 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 477 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 593 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 529 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

10)

Imran deposits 347 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 573 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 14038.5

SOLUTION 1 :

Given:

P = 573

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (573 x 25 x $\frac{2)}{100}$

= $\frac{28650}{100}$

= 286.5

A = (P x n) +I

= (573 x 24) + 286.5

= 13752 + 286.5

= 14038.5

Imran deposits 221 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 5469.75

SOLUTION 1 :

Given:

P = 221

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (221 x 25 x $\frac{3)}{100}$

= $\frac{16575}{100}$

= 165.75

A = (P x n) +I

= (221 x 24) + 165.75

= 5304 + 165.75

= 5469.75

Imran deposits 499 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 12599.75

SOLUTION 1 :

Given:

P = 499

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (499 x 25 x $\frac{5)}{100}$

= $\frac{62375}{100}$

= 623.75

A = (P x n) +I

= (499 x 24) + 623.75

= 11976 + 623.75

= 12599.75

Imran deposits 364 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 9282

SOLUTION 1 :

Given:

P = 364

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (364 x 25 x $\frac{6)}{100}$

= $\frac{54600}{100}$

= 546

A = (P x n) +I

= (364 x 24) + 546

= 8736 + 546

= 9282

Imran deposits 593 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 15121.5

SOLUTION 1 :

Given:

P = 593

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (593 x 25 x $\frac{6)}{100}$

= $\frac{88950}{100}$

= 889.5

A = (P x n) +I

= (593 x 24) + 889.5

= 14232 + 889.5

= 15121.5

Imran deposits 231 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 5717.25

SOLUTION 1 :

Given:

P = 231

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (231 x 25 x $\frac{3)}{100}$

= $\frac{17325}{100}$

= 173.25

A = (P x n) +I

= (231 x 24) + 173.25

= 5544 + 173.25

= 5717.25

Imran deposits 477 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 12163.5

SOLUTION 1 :

Given:

P = 477

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (477 x 25 x $\frac{6)}{100}$

= $\frac{71550}{100}$

= 715.5

A = (P x n) +I

= (477 x 24) + 715.5

= 11448 + 715.5

= 12163.5

Imran deposits 593 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 14528.5

SOLUTION 1 :

Given:

P = 593

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (593 x 25 x $\frac{2)}{100}$

= $\frac{29650}{100}$

= 296.5

A = (P x n) +I

= (593 x 24) + 296.5

= 14232 + 296.5

= 14528.5

Imran deposits 529 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 13489.5

SOLUTION 1 :

Given:

P = 529

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (529 x 25 x $\frac{6)}{100}$

= $\frac{79350}{100}$

= 793.5

A = (P x n) +I

= (529 x 24) + 793.5

= 12696 + 793.5

= 13489.5

10)

Imran deposits 347 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 8675

SOLUTION 1 :

Given:

P = 347

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (347 x 25 x $\frac{4)}{100}$

= $\frac{34700}{100}$

= 347

A = (P x n) +I

= (347 x 24) + 347

= 8328 + 347

= 8675