Scroll:Life mathematics >> profit and loss >> saq (4273)
Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
| 1) The population of a village increases at the rate of 4% every year. If the present population is 48476,what will be the population after 3 years
Answer:_______________ |
| 2) The population of a village increases at the rate of 7% every year. If the present population is 35156,what will be the population after 4 years
Answer:_______________ |
| 3) The population of a village increases at the rate of 2% every year. If the present population is 33705,what will be the population after 4 years
Answer:_______________ |
| 4) The population of a village increases at the rate of 2% every year. If the present population is 13804,what will be the population after 2 years
Answer:_______________ |
| 5) The population of a village increases at the rate of 6% every year. If the present population is 21480,what will be the population after 4 years
Answer:_______________ |
| 6) The population of a village increases at the rate of 4% every year. If the present population is 27180,what will be the population after 4 years
Answer:_______________ |
| 7) The population of a village increases at the rate of 6% every year. If the present population is 42239,what will be the population after 3 years
Answer:_______________ |
| 8) The population of a village increases at the rate of 3% every year. If the present population is 15592,what will be the population after 2 years
Answer:_______________ |
| 9) The population of a village increases at the rate of 3% every year. If the present population is 17200,what will be the population after 2 years
Answer:_______________ |
| 10) The population of a village increases at the rate of 7% every year. If the present population is 38898,what will be the population after 4 years
Answer:_______________ |
| 1) The population of a village increases at the rate of 4% every year. If the present population is 48476,what will be the population after 3 years Answer: 54529 SOLUTION 1 : Given : Present population P = Rate of increase r = 4% Number of years n = 3 years The population after n years = P[1+(r÷100)]n = 48476[1+(4÷100)]3 = 48476[1+0.04]3 = 48476(1.04)3 = 48476 x 1.124864 = |
48476| 2) The population of a village increases at the rate of 7% every year. If the present population is 35156,what will be the population after 4 years Answer: 46082 SOLUTION 1 : Given : Present population P = Rate of increase r = 7% Number of years n = 4 years The population after n years = P[1+(r÷100)]n = 35156[1+(7÷100)]4 = 35156[1+0.07]4 = 35156(1.07)4 = 35156 x 1.31079601 = |
| 3) The population of a village increases at the rate of 2% every year. If the present population is 33705,what will be the population after 4 years Answer: 36483 SOLUTION 1 : Given : Present population P = Rate of increase r = 2% Number of years n = 4 years The population after n years = P[1+(r÷100)]n = 33705[1+(2÷100)]4 = 33705[1+0.02]4 = 33705(1.02)4 = 33705 x 1.08243216 = |
| 4) The population of a village increases at the rate of 2% every year. If the present population is 13804,what will be the population after 2 years Answer: 14362 SOLUTION 1 : Given : Present population P = Rate of increase r = 2% Number of years n = 2 years The population after n years = P[1+(r÷100)]n = 13804[1+(2÷100)]2 = 13804[1+0.02]2 = 13804(1.02)2 = 13804 x 1.0404 = |
| 5) The population of a village increases at the rate of 6% every year. If the present population is 21480,what will be the population after 4 years Answer: 27118 SOLUTION 1 : Given : Present population P = Rate of increase r = 6% Number of years n = 4 years The population after n years = P[1+(r÷100)]n = 21480[1+(6÷100)]4 = 21480[1+0.06]4 = 21480(1.06)4 = 21480 x 1.26247696 = |
| 6) The population of a village increases at the rate of 4% every year. If the present population is 27180,what will be the population after 4 years Answer: 31797 SOLUTION 1 : Given : Present population P = Rate of increase r = 4% Number of years n = 4 years The population after n years = P[1+(r÷100)]n = 27180[1+(4÷100)]4 = 27180[1+0.04]4 = 27180(1.04)4 = 27180 x 1.16985856 = |
| 7) The population of a village increases at the rate of 6% every year. If the present population is 42239,what will be the population after 3 years Answer: 50307 SOLUTION 1 : Given : Present population P = Rate of increase r = 6% Number of years n = 3 years The population after n years = P[1+(r÷100)]n = 42239[1+(6÷100)]3 = 42239[1+0.06]3 = 42239(1.06)3 = 42239 x 1.191016 = |
| 8) The population of a village increases at the rate of 3% every year. If the present population is 15592,what will be the population after 2 years Answer: 16542 SOLUTION 1 : Given : Present population P = Rate of increase r = 3% Number of years n = 2 years The population after n years = P[1+(r÷100)]n = 15592[1+(3÷100)]2 = 15592[1+0.03]2 = 15592(1.03)2 = 15592 x 1.0609 = |
| 9) The population of a village increases at the rate of 3% every year. If the present population is 17200,what will be the population after 2 years Answer: 18247 SOLUTION 1 : Given : Present population P = Rate of increase r = 3% Number of years n = 2 years The population after n years = P[1+(r÷100)]n = 17200[1+(3÷100)]2 = 17200[1+0.03]2 = 17200(1.03)2 = 17200 x 1.0609 = |
| 10) The population of a village increases at the rate of 7% every year. If the present population is 38898,what will be the population after 4 years Answer: 50987 SOLUTION 1 : Given : Present population P = Rate of increase r = 7% Number of years n = 4 years The population after n years = P[1+(r÷100)]n = 38898[1+(7÷100)]4 = 38898[1+0.07]4 = 38898(1.07)4 = 38898 x 1.31079601 = |