Sasi Math (Revised for 1024)

Scroll:Life mathematics >> profit and loss >> saq (4271)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

10)

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:_______________

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50

10)

Find the C.I on 20000 at 15% per annum for $\frac{7}{2}$ years.

Answer:

SOLUTION 1 :

Given :

P = 20,000

r = 15%

n = 2 $\frac{1}{3}$ years

A = P[1+(r÷100)]²[1+(r÷300)]

= 20,000[1+(15÷100)]²÷300]

= 20,000[1+(3÷20)]²[1+(1÷20)]

= 20,000[(23÷20)]²[21÷20]

= 20,000 x [(23÷20) x (23÷20) x (21÷20)]

= 27,772.50