Scroll:Life mathematics >> profit and loss >> saq (4270)


Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.



 

1)  

 At what rate per annum will 264 amount to 780 in 2 years , when interest is being compounted annually

%


Answer:_______________




2)  

 At what rate per annum will 433 amount to 720 in 2 years , when interest is being compounted annually

%


Answer:_______________




3)  

 At what rate per annum will 393 amount to 763 in 2 years , when interest is being compounted annually

%


Answer:_______________




4)  

 At what rate per annum will 245 amount to 739 in 2 years , when interest is being compounted annually

%


Answer:_______________




5)  

 At what rate per annum will 401 amount to 685 in 2 years , when interest is being compounted annually

%


Answer:_______________




6)  

 At what rate per annum will 394 amount to 781 in 2 years , when interest is being compounted annually

%


Answer:_______________




7)  

 At what rate per annum will 287 amount to 796 in 2 years , when interest is being compounted annually

%


Answer:_______________




8)  

 At what rate per annum will 476 amount to 634 in 2 years , when interest is being compounted annually

%


Answer:_______________




9)  

 At what rate per annum will 490 amount to 783 in 2 years , when interest is being compounted annually

%


Answer:_______________




10)  

 At what rate per annum will 204 amount to 714 in 2 years , when interest is being compounted annually

%


Answer:_______________




 

1)  

 At what rate per annum will 264 amount to 780 in 2 years , when interest is being compounted annually

Answer: 195 %


SOLUTION 1 :

Given :

  Given  

        P   =   264

        A   =   780

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   780   =   264[1+(r÷100)]2    

780÷ 264 =  [1+(r÷100)]2  

2.95454545455                = [1+(r÷100)]2

(2.95454545455)½ = 1+(r÷100)

2.95454545455            =   1+(r÷100)

(2.95454545455)-1        =    r÷100

1.95454545455 x 100  = r

195 %     =  r

 



2)  

 At what rate per annum will 433 amount to 720 in 2 years , when interest is being compounted annually

Answer: 66 %


SOLUTION 1 :

Given :

  Given  

        P   =   433

        A   =   720

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   720   =   433[1+(r÷100)]2    

720÷ 433 =  [1+(r÷100)]2  

1.66281755196                = [1+(r÷100)]2

(1.66281755196)½ = 1+(r÷100)

1.66281755196            =   1+(r÷100)

(1.66281755196)-1        =    r÷100

0.662817551963 x 100  = r

66 %     =  r

 



3)  

 At what rate per annum will 393 amount to 763 in 2 years , when interest is being compounted annually

Answer: 94 %


SOLUTION 1 :

Given :

  Given  

        P   =   393

        A   =   763

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   763   =   393[1+(r÷100)]2    

763÷ 393 =  [1+(r÷100)]2  

1.94147582697                = [1+(r÷100)]2

(1.94147582697)½ = 1+(r÷100)

1.94147582697            =   1+(r÷100)

(1.94147582697)-1        =    r÷100

0.941475826972 x 100  = r

94 %     =  r

 



4)  

 At what rate per annum will 245 amount to 739 in 2 years , when interest is being compounted annually

Answer: 202 %


SOLUTION 1 :

Given :

  Given  

        P   =   245

        A   =   739

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   739   =   245[1+(r÷100)]2    

739÷ 245 =  [1+(r÷100)]2  

3.01632653061                = [1+(r÷100)]2

(3.01632653061)½ = 1+(r÷100)

3.01632653061            =   1+(r÷100)

(3.01632653061)-1        =    r÷100

2.01632653061 x 100  = r

202 %     =  r

 



5)  

 At what rate per annum will 401 amount to 685 in 2 years , when interest is being compounted annually

Answer: 71 %


SOLUTION 1 :

Given :

  Given  

        P   =   401

        A   =   685

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   685   =   401[1+(r÷100)]2    

685÷ 401 =  [1+(r÷100)]2  

1.70822942643                = [1+(r÷100)]2

(1.70822942643)½ = 1+(r÷100)

1.70822942643            =   1+(r÷100)

(1.70822942643)-1        =    r÷100

0.708229426434 x 100  = r

71 %     =  r

 



6)  

 At what rate per annum will 394 amount to 781 in 2 years , when interest is being compounted annually

Answer: 98 %


SOLUTION 1 :

Given :

  Given  

        P   =   394

        A   =   781

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   781   =   394[1+(r÷100)]2    

781÷ 394 =  [1+(r÷100)]2  

1.98223350254                = [1+(r÷100)]2

(1.98223350254)½ = 1+(r÷100)

1.98223350254            =   1+(r÷100)

(1.98223350254)-1        =    r÷100

0.982233502538 x 100  = r

98 %     =  r

 



7)  

 At what rate per annum will 287 amount to 796 in 2 years , when interest is being compounted annually

Answer: 177 %


SOLUTION 1 :

Given :

  Given  

        P   =   287

        A   =   796

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   796   =   287[1+(r÷100)]2    

796÷ 287 =  [1+(r÷100)]2  

2.77351916376                = [1+(r÷100)]2

(2.77351916376)½ = 1+(r÷100)

2.77351916376            =   1+(r÷100)

(2.77351916376)-1        =    r÷100

1.77351916376 x 100  = r

177 %     =  r

 



8)  

 At what rate per annum will 476 amount to 634 in 2 years , when interest is being compounted annually

Answer: 33 %


SOLUTION 1 :

Given :

  Given  

        P   =   476

        A   =   634

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   634   =   476[1+(r÷100)]2    

634÷ 476 =  [1+(r÷100)]2  

1.33193277311                = [1+(r÷100)]2

(1.33193277311)½ = 1+(r÷100)

1.33193277311            =   1+(r÷100)

(1.33193277311)-1        =    r÷100

0.331932773109 x 100  = r

33 %     =  r

 



9)  

 At what rate per annum will 490 amount to 783 in 2 years , when interest is being compounted annually

Answer: 60 %


SOLUTION 1 :

Given :

  Given  

        P   =   490

        A   =   783

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   783   =   490[1+(r÷100)]2    

783÷ 490 =  [1+(r÷100)]2  

1.59795918367                = [1+(r÷100)]2

(1.59795918367)½ = 1+(r÷100)

1.59795918367            =   1+(r÷100)

(1.59795918367)-1        =    r÷100

0.597959183673 x 100  = r

60 %     =  r

 



10)  

 At what rate per annum will 204 amount to 714 in 2 years , when interest is being compounted annually

Answer: 250 %


SOLUTION 1 :

Given :

  Given  

        P   =   204

        A   =   714

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   714   =   204[1+(r÷100)]2    

714÷ 204 =  [1+(r÷100)]2  

3.5                = [1+(r÷100)]2

(3.5)½ = 1+(r÷100)

3.5            =   1+(r÷100)

(3.5)-1        =    r÷100

2.5 x 100  = r

250 %     =  r