Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
1) At what rate per annum will 299 amount to 773 in 2 years , when interest is being compounted annually % Answer:_______________ |
2) At what rate per annum will 268 amount to 690 in 2 years , when interest is being compounted annually % Answer:_______________ |
3) At what rate per annum will 239 amount to 629 in 2 years , when interest is being compounted annually % Answer:_______________ |
4) At what rate per annum will 417 amount to 705 in 2 years , when interest is being compounted annually % Answer:_______________ |
5) At what rate per annum will 432 amount to 603 in 2 years , when interest is being compounted annually % Answer:_______________ |
6) At what rate per annum will 456 amount to 611 in 2 years , when interest is being compounted annually % Answer:_______________ |
7) At what rate per annum will 410 amount to 652 in 2 years , when interest is being compounted annually % Answer:_______________ |
8) At what rate per annum will 383 amount to 608 in 2 years , when interest is being compounted annually % Answer:_______________ |
9) At what rate per annum will 437 amount to 797 in 2 years , when interest is being compounted annually % Answer:_______________ |
10) At what rate per annum will 373 amount to 796 in 2 years , when interest is being compounted annually % Answer:_______________ |
1) At what rate per annum will 299 amount to 773 in 2 years , when interest is being compounted annually Answer: 159 % SOLUTION 1 : Given : Given P = 299 A = 773 n = 2 years r = A = P[1+(r÷100)]n 773 = 299[1+(r÷100)]2 773÷ 299 = [1+(r÷100)]2 2.58528428094 = [1+(r÷100)]2 (2.58528428094)½ = 1+(r÷100) 2.58528428094 = 1+(r÷100) (2.58528428094)-1 = r÷100 1.58528428094 x 100 = r 159 % = r
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2) At what rate per annum will 268 amount to 690 in 2 years , when interest is being compounted annually Answer: 157 % SOLUTION 1 : Given : Given P = 268 A = 690 n = 2 years r = A = P[1+(r÷100)]n 690 = 268[1+(r÷100)]2 690÷ 268 = [1+(r÷100)]2 2.57462686567 = [1+(r÷100)]2 (2.57462686567)½ = 1+(r÷100) 2.57462686567 = 1+(r÷100) (2.57462686567)-1 = r÷100 1.57462686567 x 100 = r 157 % = r
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3) At what rate per annum will 239 amount to 629 in 2 years , when interest is being compounted annually Answer: 163 % SOLUTION 1 : Given : Given P = 239 A = 629 n = 2 years r = A = P[1+(r÷100)]n 629 = 239[1+(r÷100)]2 629÷ 239 = [1+(r÷100)]2 2.63179916318 = [1+(r÷100)]2 (2.63179916318)½ = 1+(r÷100) 2.63179916318 = 1+(r÷100) (2.63179916318)-1 = r÷100 1.63179916318 x 100 = r 163 % = r
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4) At what rate per annum will 417 amount to 705 in 2 years , when interest is being compounted annually Answer: 69 % SOLUTION 1 : Given : Given P = 417 A = 705 n = 2 years r = A = P[1+(r÷100)]n 705 = 417[1+(r÷100)]2 705÷ 417 = [1+(r÷100)]2 1.69064748201 = [1+(r÷100)]2 (1.69064748201)½ = 1+(r÷100) 1.69064748201 = 1+(r÷100) (1.69064748201)-1 = r÷100 0.690647482014 x 100 = r 69 % = r
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5) At what rate per annum will 432 amount to 603 in 2 years , when interest is being compounted annually Answer: 40 % SOLUTION 1 : Given : Given P = 432 A = 603 n = 2 years r = A = P[1+(r÷100)]n 603 = 432[1+(r÷100)]2 603÷ 432 = [1+(r÷100)]2 1.39583333333 = [1+(r÷100)]2 (1.39583333333)½ = 1+(r÷100) 1.39583333333 = 1+(r÷100) (1.39583333333)-1 = r÷100 0.395833333333 x 100 = r 40 % = r
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6) At what rate per annum will 456 amount to 611 in 2 years , when interest is being compounted annually Answer: 34 % SOLUTION 1 : Given : Given P = 456 A = 611 n = 2 years r = A = P[1+(r÷100)]n 611 = 456[1+(r÷100)]2 611÷ 456 = [1+(r÷100)]2 1.3399122807 = [1+(r÷100)]2 (1.3399122807)½ = 1+(r÷100) 1.3399122807 = 1+(r÷100) (1.3399122807)-1 = r÷100 0.339912280702 x 100 = r 34 % = r
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7) At what rate per annum will 410 amount to 652 in 2 years , when interest is being compounted annually Answer: 59 % SOLUTION 1 : Given : Given P = 410 A = 652 n = 2 years r = A = P[1+(r÷100)]n 652 = 410[1+(r÷100)]2 652÷ 410 = [1+(r÷100)]2 1.59024390244 = [1+(r÷100)]2 (1.59024390244)½ = 1+(r÷100) 1.59024390244 = 1+(r÷100) (1.59024390244)-1 = r÷100 0.590243902439 x 100 = r 59 % = r
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8) At what rate per annum will 383 amount to 608 in 2 years , when interest is being compounted annually Answer: 59 % SOLUTION 1 : Given : Given P = 383 A = 608 n = 2 years r = A = P[1+(r÷100)]n 608 = 383[1+(r÷100)]2 608÷ 383 = [1+(r÷100)]2 1.58746736292 = [1+(r÷100)]2 (1.58746736292)½ = 1+(r÷100) 1.58746736292 = 1+(r÷100) (1.58746736292)-1 = r÷100 0.587467362924 x 100 = r 59 % = r
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9) At what rate per annum will 437 amount to 797 in 2 years , when interest is being compounted annually Answer: 82 % SOLUTION 1 : Given : Given P = 437 A = 797 n = 2 years r = A = P[1+(r÷100)]n 797 = 437[1+(r÷100)]2 797÷ 437 = [1+(r÷100)]2 1.823798627 = [1+(r÷100)]2 (1.823798627)½ = 1+(r÷100) 1.823798627 = 1+(r÷100) (1.823798627)-1 = r÷100 0.823798627002 x 100 = r 82 % = r
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10) At what rate per annum will 373 amount to 796 in 2 years , when interest is being compounted annually Answer: 113 % SOLUTION 1 : Given : Given P = 373 A = 796 n = 2 years r = A = P[1+(r÷100)]n 796 = 373[1+(r÷100)]2 796÷ 373 = [1+(r÷100)]2 2.13404825737 = [1+(r÷100)]2 (2.13404825737)½ = 1+(r÷100) 2.13404825737 = 1+(r÷100) (2.13404825737)-1 = r÷100 1.13404825737 x 100 = r 113 % = r
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