Scroll:Life mathematics >> profit and loss >> saq (4270)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.


 

1)  

 At what rate per annum will 412 amount to 768 in 2 years , when interest is being compounted annually

%


Answer:_______________




2)  

 At what rate per annum will 249 amount to 625 in 2 years , when interest is being compounted annually

%


Answer:_______________




3)  

 At what rate per annum will 211 amount to 768 in 2 years , when interest is being compounted annually

%


Answer:_______________




4)  

 At what rate per annum will 212 amount to 742 in 2 years , when interest is being compounted annually

%


Answer:_______________




5)  

 At what rate per annum will 398 amount to 749 in 2 years , when interest is being compounted annually

%


Answer:_______________




6)  

 At what rate per annum will 432 amount to 738 in 2 years , when interest is being compounted annually

%


Answer:_______________




7)  

 At what rate per annum will 335 amount to 727 in 2 years , when interest is being compounted annually

%


Answer:_______________




8)  

 At what rate per annum will 368 amount to 761 in 2 years , when interest is being compounted annually

%


Answer:_______________




9)  

 At what rate per annum will 312 amount to 768 in 2 years , when interest is being compounted annually

%


Answer:_______________




10)  

 At what rate per annum will 210 amount to 775 in 2 years , when interest is being compounted annually

%


Answer:_______________




 

1)  

 At what rate per annum will 412 amount to 768 in 2 years , when interest is being compounted annually

Answer: 86 %


SOLUTION 1 :

Given :

  Given  

        P   =   412

        A   =   768

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   768   =   412[1+(r÷100)]2    

768÷ 412 =  [1+(r÷100)]2  

1.8640776699                = [1+(r÷100)]2

(1.8640776699)½ = 1+(r÷100)

1.8640776699            =   1+(r÷100)

(1.8640776699)-1        =    r÷100

0.864077669903 x 100  = r

86 %     =  r

 



2)  

 At what rate per annum will 249 amount to 625 in 2 years , when interest is being compounted annually

Answer: 151 %


SOLUTION 1 :

Given :

  Given  

        P   =   249

        A   =   625

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   625   =   249[1+(r÷100)]2    

625÷ 249 =  [1+(r÷100)]2  

2.51004016064                = [1+(r÷100)]2

(2.51004016064)½ = 1+(r÷100)

2.51004016064            =   1+(r÷100)

(2.51004016064)-1        =    r÷100

1.51004016064 x 100  = r

151 %     =  r

 



3)  

 At what rate per annum will 211 amount to 768 in 2 years , when interest is being compounted annually

Answer: 264 %


SOLUTION 1 :

Given :

  Given  

        P   =   211

        A   =   768

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   768   =   211[1+(r÷100)]2    

768÷ 211 =  [1+(r÷100)]2  

3.63981042654                = [1+(r÷100)]2

(3.63981042654)½ = 1+(r÷100)

3.63981042654            =   1+(r÷100)

(3.63981042654)-1        =    r÷100

2.63981042654 x 100  = r

264 %     =  r

 



4)  

 At what rate per annum will 212 amount to 742 in 2 years , when interest is being compounted annually

Answer: 250 %


SOLUTION 1 :

Given :

  Given  

        P   =   212

        A   =   742

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   742   =   212[1+(r÷100)]2    

742÷ 212 =  [1+(r÷100)]2  

3.5                = [1+(r÷100)]2

(3.5)½ = 1+(r÷100)

3.5            =   1+(r÷100)

(3.5)-1        =    r÷100

2.5 x 100  = r

250 %     =  r

 



5)  

 At what rate per annum will 398 amount to 749 in 2 years , when interest is being compounted annually

Answer: 88 %


SOLUTION 1 :

Given :

  Given  

        P   =   398

        A   =   749

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   749   =   398[1+(r÷100)]2    

749÷ 398 =  [1+(r÷100)]2  

1.88190954774                = [1+(r÷100)]2

(1.88190954774)½ = 1+(r÷100)

1.88190954774            =   1+(r÷100)

(1.88190954774)-1        =    r÷100

0.881909547739 x 100  = r

88 %     =  r

 



6)  

 At what rate per annum will 432 amount to 738 in 2 years , when interest is being compounted annually

Answer: 71 %


SOLUTION 1 :

Given :

  Given  

        P   =   432

        A   =   738

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   738   =   432[1+(r÷100)]2    

738÷ 432 =  [1+(r÷100)]2  

1.70833333333                = [1+(r÷100)]2

(1.70833333333)½ = 1+(r÷100)

1.70833333333            =   1+(r÷100)

(1.70833333333)-1        =    r÷100

0.708333333333 x 100  = r

71 %     =  r

 



7)  

 At what rate per annum will 335 amount to 727 in 2 years , when interest is being compounted annually

Answer: 117 %


SOLUTION 1 :

Given :

  Given  

        P   =   335

        A   =   727

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   727   =   335[1+(r÷100)]2    

727÷ 335 =  [1+(r÷100)]2  

2.17014925373                = [1+(r÷100)]2

(2.17014925373)½ = 1+(r÷100)

2.17014925373            =   1+(r÷100)

(2.17014925373)-1        =    r÷100

1.17014925373 x 100  = r

117 %     =  r

 



8)  

 At what rate per annum will 368 amount to 761 in 2 years , when interest is being compounted annually

Answer: 107 %


SOLUTION 1 :

Given :

  Given  

        P   =   368

        A   =   761

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   761   =   368[1+(r÷100)]2    

761÷ 368 =  [1+(r÷100)]2  

2.06793478261                = [1+(r÷100)]2

(2.06793478261)½ = 1+(r÷100)

2.06793478261            =   1+(r÷100)

(2.06793478261)-1        =    r÷100

1.06793478261 x 100  = r

107 %     =  r

 



9)  

 At what rate per annum will 312 amount to 768 in 2 years , when interest is being compounted annually

Answer: 146 %


SOLUTION 1 :

Given :

  Given  

        P   =   312

        A   =   768

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   768   =   312[1+(r÷100)]2    

768÷ 312 =  [1+(r÷100)]2  

2.46153846154                = [1+(r÷100)]2

(2.46153846154)½ = 1+(r÷100)

2.46153846154            =   1+(r÷100)

(2.46153846154)-1        =    r÷100

1.46153846154 x 100  = r

146 %     =  r

 



10)  

 At what rate per annum will 210 amount to 775 in 2 years , when interest is being compounted annually

Answer: 269 %


SOLUTION 1 :

Given :

  Given  

        P   =   210

        A   =   775

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   775   =   210[1+(r÷100)]2    

775÷ 210 =  [1+(r÷100)]2  

3.69047619048                = [1+(r÷100)]2

(3.69047619048)½ = 1+(r÷100)

3.69047619048            =   1+(r÷100)

(3.69047619048)-1        =    r÷100

2.69047619048 x 100  = r

269 %     =  r