Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
1) Find the C.I. on 13863 at 10% p.a.for 3 years compounded annually.
Answer:_______________ |
2) Find the C.I. on 12497 at 6% p.a.for 3 years compounded annually.
Answer:_______________ |
3) Find the C.I. on 12350 at 7% p.a.for 3 years compounded annually.
Answer:_______________ |
4) Find the C.I. on 14984 at 5% p.a.for 3 years compounded annually.
Answer:_______________ |
5) Find the C.I. on 13761 at 8% p.a.for 3 years compounded annually.
Answer:_______________ |
6) Find the C.I. on 13309 at 8% p.a.for 3 years compounded annually.
Answer:_______________ |
7) Find the C.I. on 12869 at 5% p.a.for 3 years compounded annually.
Answer:_______________ |
8) Find the C.I. on 13600 at 6% p.a.for 3 years compounded annually.
Answer:_______________ |
9) Find the C.I. on 13075 at 5% p.a.for 3 years compounded annually.
Answer:_______________ |
10) Find the C.I. on 14697 at 7% p.a.for 3 years compounded annually.
Answer:_______________ |
1) Find the C.I. on 13863 at 10% p.a.for 3 years compounded annually. Answer: 4575 SOLUTION 1 : Given : P = 13863 r = 10% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 13863 [(1+ 10 ÷100)]3 = 13863 [(1+0.10)]3 = 13863[(1.1)]3 = 13863x1.33 = 18437.79 Compount interest = 18437.79-13863 = 4575 |
2) Find the C.I. on 12497 at 6% p.a.for 3 years compounded annually. Answer: 2374 SOLUTION 1 : Given : P = 12497 r = 6% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 12497 [(1+ 6 ÷100)]3 = 12497 [(1+0.06)]3 = 12497[(1.06)]3 = 12497x1.19 = 14871.43 Compount interest = 14871.43-12497 = 2374 |
3) Find the C.I. on 12350 at 7% p.a.for 3 years compounded annually. Answer: 2841 SOLUTION 1 : Given : P = 12350 r = 7% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 12350 [(1+ 7 ÷100)]3 = 12350 [(1+0.07)]3 = 12350[(1.07)]3 = 12350x1.23 = 15190.5 Compount interest = 15190.5-12350 = 2841 |
4) Find the C.I. on 14984 at 5% p.a.for 3 years compounded annually. Answer: 2397 SOLUTION 1 : Given : P = 14984 r = 5% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 14984 [(1+ 5 ÷100)]3 = 14984 [(1+0.05)]3 = 14984[(1.05)]3 = 14984x1.16 = 17381.44 Compount interest = 17381.44-14984 = 2397 |
5) Find the C.I. on 13761 at 8% p.a.for 3 years compounded annually. Answer: 3578 SOLUTION 1 : Given : P = 13761 r = 8% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 13761 [(1+ 8 ÷100)]3 = 13761 [(1+0.08)]3 = 13761[(1.08)]3 = 13761x1.26 = 17338.86 Compount interest = 17338.86-13761 = 3578 |
6) Find the C.I. on 13309 at 8% p.a.for 3 years compounded annually. Answer: 3460 SOLUTION 1 : Given : P = 13309 r = 8% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 13309 [(1+ 8 ÷100)]3 = 13309 [(1+0.08)]3 = 13309[(1.08)]3 = 13309x1.26 = 16769.34 Compount interest = 16769.34-13309 = 3460 |
7) Find the C.I. on 12869 at 5% p.a.for 3 years compounded annually. Answer: 2059 SOLUTION 1 : Given : P = 12869 r = 5% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 12869 [(1+ 5 ÷100)]3 = 12869 [(1+0.05)]3 = 12869[(1.05)]3 = 12869x1.16 = 14928.04 Compount interest = 14928.04-12869 = 2059 |
8) Find the C.I. on 13600 at 6% p.a.for 3 years compounded annually. Answer: 2584 SOLUTION 1 : Given : P = 13600 r = 6% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 13600 [(1+ 6 ÷100)]3 = 13600 [(1+0.06)]3 = 13600[(1.06)]3 = 13600x1.19 = 16184 Compount interest = 16184-13600 = 2584 |
9) Find the C.I. on 13075 at 5% p.a.for 3 years compounded annually. Answer: 2092 SOLUTION 1 : Given : P = 13075 r = 5% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 13075 [(1+ 5 ÷100)]3 = 13075 [(1+0.05)]3 = 13075[(1.05)]3 = 13075x1.16 = 15167 Compount interest = 15167-13075 = 2092 |
10) Find the C.I. on 14697 at 7% p.a.for 3 years compounded annually. Answer: 3380 SOLUTION 1 : Given : P = 14697 r = 7% n = 3 years Amount after 3years = P[(1+(r÷ 100)]3 = 14697 [(1+ 7 ÷100)]3 = 14697 [(1+0.07)]3 = 14697[(1.07)]3 = 14697x1.23 = 18077.31 Compount interest = 18077.31-14697 = 3380 |