Sasi Math (Revised for 1024)

Scroll:Sequences and series >> Arithmetric Progressions >> saq (4223)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

How many terms are there in the following Arrithmetic Progression

12, 15, 18.....159

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

12, 17, 22.....202

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

14, 17, 20.....128

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

14, 17, 20.....80

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

9, 11, 13.....97

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

20, 25, 30.....150

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

16, 21, 26.....241

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

17, 19, 21.....89

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

10, 13, 16.....127

Difference =

n =

Answer:_______________

10)

How many terms are there in the following Arrithmetic Progression

11, 13, 15.....51

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

12, 15, 18.....159

Difference = Answer: 3

n = Answer: 50

SOLUTION 1 :

Given A.P. is 12,15,18.....159

Here a = 12

d = 15 - 12

d = 3

t_n = a + (n-1)d

t_n = 159

a + (n-1)d = 159

t₅₀ = 12 + (n-1)3 = 159

= 12 + (3n- 3) = 159

= 3n + 9 = 159

= 3n = 159-9

3n = 150

n = $\frac{150}{3}$ = 50

How many terms are there in the following Arrithmetic Progression

12, 17, 22.....202

Difference = Answer: 5

n = Answer: 39

SOLUTION 1 :

Given A.P. is 12,17,22.....202

Here a = 12

d = 17 - 12

d = 5

t_n = a + (n-1)d

t_n = 202

a + (n-1)d = 202

t₃₉ = 12 + (n-1)5 = 202

= 12 + (5n- 5) = 202

= 5n + 7 = 202

= 5n = 202-7

5n = 195

n = $\frac{195}{5}$ = 39

How many terms are there in the following Arrithmetic Progression

14, 17, 20.....128

Difference = Answer: 3

n = Answer: 39

SOLUTION 1 :

Given A.P. is 14,17,20.....128

Here a = 14

d = 17 - 14

d = 3

t_n = a + (n-1)d

t_n = 128

a + (n-1)d = 128

t₃₉ = 14 + (n-1)3 = 128

= 14 + (3n- 3) = 128

= 3n + 11 = 128

= 3n = 128-11

3n = 117

n = $\frac{117}{3}$ = 39

How many terms are there in the following Arrithmetic Progression

14, 17, 20.....80

Difference = Answer: 3

n = Answer: 23

SOLUTION 1 :

Given A.P. is 14,17,20.....80

Here a = 14

d = 17 - 14

d = 3

t_n = a + (n-1)d

t_n = 80

a + (n-1)d = 80

t₂₃ = 14 + (n-1)3 = 80

= 14 + (3n- 3) = 80

= 3n + 11 = 80

= 3n = 80-11

3n = 69

n = $\frac{69}{3}$ = 23

How many terms are there in the following Arrithmetic Progression

9, 11, 13.....97

Difference = Answer: 2

n = Answer: 45

SOLUTION 1 :

Given A.P. is 9,11,13.....97

Here a = 9

d = 11 - 9

d = 2

t_n = a + (n-1)d

t_n = 97

a + (n-1)d = 97

t₄₅ = 9 + (n-1)2 = 97

= 9 + (2n- 2) = 97

= 2n + 7 = 97

= 2n = 97-7

2n = 90

n = $\frac{90}{2}$ = 45

How many terms are there in the following Arrithmetic Progression

20, 25, 30.....150

Difference = Answer: 5

n = Answer: 27

SOLUTION 1 :

Given A.P. is 20,25,30.....150

Here a = 20

d = 25 - 20

d = 5

t_n = a + (n-1)d

t_n = 150

a + (n-1)d = 150

t₂₇ = 20 + (n-1)5 = 150

= 20 + (5n- 5) = 150

= 5n + 15 = 150

= 5n = 150-15

5n = 135

n = $\frac{135}{5}$ = 27

How many terms are there in the following Arrithmetic Progression

16, 21, 26.....241

Difference = Answer: 5

n = Answer: 46

SOLUTION 1 :

Given A.P. is 16,21,26.....241

Here a = 16

d = 21 - 16

d = 5

t_n = a + (n-1)d

t_n = 241

a + (n-1)d = 241

t₄₆ = 16 + (n-1)5 = 241

= 16 + (5n- 5) = 241

= 5n + 11 = 241

= 5n = 241-11

5n = 230

n = $\frac{230}{5}$ = 46

How many terms are there in the following Arrithmetic Progression

17, 19, 21.....89

Difference = Answer: 2

n = Answer: 37

SOLUTION 1 :

Given A.P. is 17,19,21.....89

Here a = 17

d = 19 - 17

d = 2

t_n = a + (n-1)d

t_n = 89

a + (n-1)d = 89

t₃₇ = 17 + (n-1)2 = 89

= 17 + (2n- 2) = 89

= 2n + 15 = 89

= 2n = 89-15

2n = 74

n = $\frac{74}{2}$ = 37

How many terms are there in the following Arrithmetic Progression

10, 13, 16.....127

Difference = Answer: 3

n = Answer: 40

SOLUTION 1 :

Given A.P. is 10,13,16.....127

Here a = 10

d = 13 - 10

d = 3

t_n = a + (n-1)d

t_n = 127

a + (n-1)d = 127

t₄₀ = 10 + (n-1)3 = 127

= 10 + (3n- 3) = 127

= 3n + 7 = 127

= 3n = 127-7

3n = 120

n = $\frac{120}{3}$ = 40

10)

How many terms are there in the following Arrithmetic Progression

11, 13, 15.....51

Difference = Answer: 2

n = Answer: 21

SOLUTION 1 :

Given A.P. is 11,13,15.....51

Here a = 11

d = 13 - 11

d = 2

t_n = a + (n-1)d

t_n = 51

a + (n-1)d = 51

t₂₁ = 11 + (n-1)2 = 51

= 11 + (2n- 2) = 51

= 2n + 9 = 51

= 2n = 51-9

2n = 42

n = $\frac{42}{2}$ = 21