Sasi Math (Revised for 1024)

Scroll:Sequences and series >> Arithmetric Progressions >> saq (4223)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

How many terms are there in the following Arrithmetic Progression

18, 22, 26.....130

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

9, 11, 13.....93

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

19, 23, 27.....99

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

9, 14, 19.....109

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

19, 21, 23.....61

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

20, 24, 28.....100

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

13, 17, 21.....89

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

12, 17, 22.....247

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

14, 16, 18.....110

Difference =

n =

Answer:_______________

10)

How many terms are there in the following Arrithmetic Progression

13, 16, 19.....145

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

18, 22, 26.....130

Difference = Answer: 4

n = Answer: 29

SOLUTION 1 :

Given A.P. is 18,22,26.....130

Here a = 18

d = 22 - 18

d = 4

t_n = a + (n-1)d

t_n = 130

a + (n-1)d = 130

t₂₉ = 18 + (n-1)4 = 130

= 18 + (4n- 4) = 130

= 4n + 14 = 130

= 4n = 130-14

4n = 116

n = $\frac{116}{4}$ = 29

How many terms are there in the following Arrithmetic Progression

9, 11, 13.....93

Difference = Answer: 2

n = Answer: 43

SOLUTION 1 :

Given A.P. is 9,11,13.....93

Here a = 9

d = 11 - 9

d = 2

t_n = a + (n-1)d

t_n = 93

a + (n-1)d = 93

t₄₃ = 9 + (n-1)2 = 93

= 9 + (2n- 2) = 93

= 2n + 7 = 93

= 2n = 93-7

2n = 86

n = $\frac{86}{2}$ = 43

How many terms are there in the following Arrithmetic Progression

19, 23, 27.....99

Difference = Answer: 4

n = Answer: 21

SOLUTION 1 :

Given A.P. is 19,23,27.....99

Here a = 19

d = 23 - 19

d = 4

t_n = a + (n-1)d

t_n = 99

a + (n-1)d = 99

t₂₁ = 19 + (n-1)4 = 99

= 19 + (4n- 4) = 99

= 4n + 15 = 99

= 4n = 99-15

4n = 84

n = $\frac{84}{4}$ = 21

How many terms are there in the following Arrithmetic Progression

9, 14, 19.....109

Difference = Answer: 5

n = Answer: 21

SOLUTION 1 :

Given A.P. is 9,14,19.....109

Here a = 9

d = 14 - 9

d = 5

t_n = a + (n-1)d

t_n = 109

a + (n-1)d = 109

t₂₁ = 9 + (n-1)5 = 109

= 9 + (5n- 5) = 109

= 5n + 4 = 109

= 5n = 109-4

5n = 105

n = $\frac{105}{5}$ = 21

How many terms are there in the following Arrithmetic Progression

19, 21, 23.....61

Difference = Answer: 2

n = Answer: 22

SOLUTION 1 :

Given A.P. is 19,21,23.....61

Here a = 19

d = 21 - 19

d = 2

t_n = a + (n-1)d

t_n = 61

a + (n-1)d = 61

t₂₂ = 19 + (n-1)2 = 61

= 19 + (2n- 2) = 61

= 2n + 17 = 61

= 2n = 61-17

2n = 44

n = $\frac{44}{2}$ = 22

How many terms are there in the following Arrithmetic Progression

20, 24, 28.....100

Difference = Answer: 4

n = Answer: 21

SOLUTION 1 :

Given A.P. is 20,24,28.....100

Here a = 20

d = 24 - 20

d = 4

t_n = a + (n-1)d

t_n = 100

a + (n-1)d = 100

t₂₁ = 20 + (n-1)4 = 100

= 20 + (4n- 4) = 100

= 4n + 16 = 100

= 4n = 100-16

4n = 84

n = $\frac{84}{4}$ = 21

How many terms are there in the following Arrithmetic Progression

13, 17, 21.....89

Difference = Answer: 4

n = Answer: 20

SOLUTION 1 :

Given A.P. is 13,17,21.....89

Here a = 13

d = 17 - 13

d = 4

t_n = a + (n-1)d

t_n = 89

a + (n-1)d = 89

t₂₀ = 13 + (n-1)4 = 89

= 13 + (4n- 4) = 89

= 4n + 9 = 89

= 4n = 89-9

4n = 80

n = $\frac{80}{4}$ = 20

How many terms are there in the following Arrithmetic Progression

12, 17, 22.....247

Difference = Answer: 5

n = Answer: 48

SOLUTION 1 :

Given A.P. is 12,17,22.....247

Here a = 12

d = 17 - 12

d = 5

t_n = a + (n-1)d

t_n = 247

a + (n-1)d = 247

t₄₈ = 12 + (n-1)5 = 247

= 12 + (5n- 5) = 247

= 5n + 7 = 247

= 5n = 247-7

5n = 240

n = $\frac{240}{5}$ = 48

How many terms are there in the following Arrithmetic Progression

14, 16, 18.....110

Difference = Answer: 2

n = Answer: 49

SOLUTION 1 :

Given A.P. is 14,16,18.....110

Here a = 14

d = 16 - 14

d = 2

t_n = a + (n-1)d

t_n = 110

a + (n-1)d = 110

t₄₉ = 14 + (n-1)2 = 110

= 14 + (2n- 2) = 110

= 2n + 12 = 110

= 2n = 110-12

2n = 98

n = $\frac{98}{2}$ = 49

10)

How many terms are there in the following Arrithmetic Progression

13, 16, 19.....145

Difference = Answer: 3

n = Answer: 45

SOLUTION 1 :

Given A.P. is 13,16,19.....145

Here a = 13

d = 16 - 13

d = 3

t_n = a + (n-1)d

t_n = 145

a + (n-1)d = 145

t₄₅ = 13 + (n-1)3 = 145

= 13 + (3n- 3) = 145

= 3n + 10 = 145

= 3n = 145-10

3n = 135

n = $\frac{135}{3}$ = 45