Sasi Math (Revised for 1024)

Scroll:Algebra >> Multiple Choice Questions: >> mcq (4180)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

If a polynomial p(x) is divided by (ax+b), then the remainder is

1) ab) ' title="p(-

\frac{a}{b}

) "/> p(-

\frac{a}{b}

)
2) ba) ' title=" p(

\frac{b}{a}

) "/> p(

\frac{b}{a}

)
3) ba) ' title="p(-

\frac{b}{a}

) "/> p(-

\frac{b}{a}

)
4) ab) ' title="p(

\frac{a}{b}

) "/> p(

\frac{a}{b}

)

( )

The polynomial 3x-2 is a

1) linear polynomial
2) constant polynomial
3) cubic polynomial
4) quadratic polynomial

( )

The degree of the polynomial 4x²-7x³+ 6x + 1 is

1) 3
2) 1
3) 2
4) 0

( )

One of the factors of x³-2x²+2x -1 is

1) x+2
2) x-1
3) x-2
4) x+1

( )

.The coefficients of x² and x in 2x³ -3x²- 2x + 3 are respectively

1) -3,-2
2) 2,-3
3) -2,-3
4) -2,3

( )

One of the factors of x²- 3x -10 is

1) x-2
2) x-3
3) x+2
4) x-5

( )

If the polynomial x³ –ax²+2x-a is divided (x-a), then remainder is

(1)⇒ a

(2)⇒(a²)

(3) ⇒(a³)

(4) ⇒(-a)

1) 1
2) 4
3) 3
4) 2

( )

The root of the polynomial equation 3x-1 = 0 is

1) 13 ' title=" x = -

\frac{1}{3}

"/> x = -

\frac{1}{3}

2) x = 1
3) 13 ' title="x =

\frac{1}{3}

"/> x =

\frac{1}{3}

4) x = 3

( )

The roots of the polynomial equation x² +2x = 0 are

1) x = 1,2
2) X = 0,2
3) x = 1,-2
4) x =0,-2

( )

10)

The zero of the polynomial 2x-5 is

1) 52 ' title="

\frac{5}{2}

"/>

\frac{5}{2}

2) 52 ' title=" -

\frac{5}{2}

"/> -

\frac{5}{2}

3) 25 ' title="-

\frac{2}{5}

"/> -

\frac{2}{5}

4) 25 ' title="

\frac{2}{5}

"/>

\frac{2}{5}

( )

If a polynomial p(x) is divided by (ax+b), then the remainder is

1) ab) ' title="p(

\frac{a}{b}

) "/> p(

\frac{a}{b}

)
2) ba) ' title=" p(

\frac{b}{a}

) "/> p(

\frac{b}{a}

)
3) ba) ' title="p(-

\frac{b}{a}

) "/> p(-

\frac{b}{a}

)
4) ab) ' title="p(-

\frac{a}{b}

) "/> p(-

\frac{a}{b}

)

Answer: 3

SOLUTION 1 :

Ans = $\frac{p(-b}{a)}$

The polynomial 3x-2 is a

1) cubic polynomial
2) constant polynomial
3) linear polynomial
4) quadratic polynomial

Answer: 3

SOLUTION 1 :

Hint: [ The degree of 3x-2 is 1, It is a linear polynomial]

Ans = linear polynomial

The degree of the polynomial 4x²-7x³+ 6x + 1 is

1) 2
2) 0
3) 3
4) 1

Answer: 3

SOLUTION 1 :

Hint: [The term having the highest degree is -7x³, The degree is 3]

Ans =3

One of the factors of x³-2x²+2x -1 is

1) x+2
2) x-2
3) x+1
4) x-1

Answer: 4

SOLUTION 1 :

Hint:[ (x³-2x²+ 2x -1 = x³-x²-x² + x + x -1 = x²(x-1) – x(x-1) + 1(x-1) = (x-1) (x²-x + 1) ]

Ans = x - 1

.The coefficients of x² and x in 2x³ -3x²- 2x + 3 are respectively

1) -2,-3
2) -3,-2
3) 2,-3
4) -2,3

Answer: 2

SOLUTION 1 :

Hint:[The co-efficient of x² is- 3 and The co-efficient of x is -2]

Ans = -3,-2

One of the factors of x²- 3x -10 is

1) x+2
2) x-2
3) x-5
4) x-3

Answer: 3

SOLUTION 1 :

Hint : [ x²- 3x -10 = x²-5x + 2x -10 ⇒ x(x-5) + 2(x-5)

The factor of x²-3x -10 are (x-5) and (x+2) ]

Ans = x - 5

If the polynomial x³ –ax²+2x-a is divided (x-a), then remainder is

(1)⇒ a

(2)⇒(a²)

(3) ⇒(a³)

(4) ⇒(-a)

1) 2
2) 4
3) 1
4) 3

Answer: 3

SOLUTION 1 :

Hint:[ [ p(x) = x³ – ax²+ 2x- a ⇒ The zero of x - a is a

p(a) = a³-a(a)²+2(a)-a ⇒ a³ - a³ + 2a - a = 2 ]

Ans = a

The root of the polynomial equation 3x-1 = 0 is

1) 13 ' title="x =

\frac{1}{3}

"/> x =

\frac{1}{3}

2) x = 1
3) 13 ' title=" x = -

\frac{1}{3}

"/> x = -

\frac{1}{3}

4) x = 3

Answer: 1

SOLUTION 1 :

Hint: [3x -1 = 0 ⇒ 3x = 1 ⇒ x = $\frac{1}{3}$ ]

Ans = x = $\frac{1}{3}$

The roots of the polynomial equation x² +2x = 0 are

1) x =0,-2
2) x = 1,-2
3) X = 0,2
4) x = 1,2

Answer: 1

SOLUTION 1 :

Hint: [ [x² +2x = 0 ⇒ x(x+2)=0 ⇒ x = 0 (or) x + 2 = 0 ⇒ x=0 (or) x = -2 ⇒ x = 0,-2]

Ans = x = 0, -2

10)

The zero of the polynomial 2x-5 is

1) 52 ' title=" -

\frac{5}{2}

"/> -

\frac{5}{2}

2) 25 ' title="

\frac{2}{5}

"/>

\frac{2}{5}

3) 52 ' title="

\frac{5}{2}

"/>

\frac{5}{2}

4) 25 ' title="-

\frac{2}{5}

"/> -

\frac{2}{5}

Answer: 3

SOLUTION 1 :

Hint: [ p(x) = 2x -5=2 ( $\frac{x-5}{2)}$ $\frac{p(5}{2)}$ = $\frac{2(5}{2-5}$ /2)=0. Hence x= $\frac{5}{2is}$ zero of p(x)

Ans = $\frac{5}{2}$

Scroll:Algebra >> Multiple Choice Questions: >> mcq (4180)

One of the factors of x3 -2x2 +2x -1 is

One of the factors of x3 -2x2 +2x -1 is

One of the factors of x³-2x²+2x -1 is

One of the factors of x³-2x²+2x -1 is