Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
| 1) If A = {16, 24,28, 32, 36}, B = {8, 16, 24} and C = { 4, 8, 12, 16, 20, 24,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
Answer:_______________ |
| 2) Verify the commutative property or set intersection for A = {Z, G, O, A, 2,3,4, 0}, B = {2, 5, 3, -2, G, O, A, D }
Answer:_______________ |
| 3) If A = {8, 12,14, 16, 18}, B = {4, 8, 12} and C = { 2, 4, 6, 8, 10, 12,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
Answer:_______________ |
| 4) Verify the commutative property or set intersection for A = {R, J, N, I, 2,3,4, 0}, B = {2, 5, 3, -2, J, N, I, U }
Answer:_______________ |
| 5) If A = {4, 6,7, 8, 9}, B = {2, 4, 6} and C = { 1, 2, 3, 4, 5, 6,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
Answer:_______________ |
| 6) Verify the commutative property or set intersection for A = {P, Y, X, P, 4,6,8, 0}, B = {4, 10, 6, -4, Y, X, P, O }
Answer:_______________ |
| 7) If A = {12, 18,21, 24, 27}, B = {6, 12, 18} and C = { 3, 6, 9, 12, 15, 18,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
Answer:_______________ |
| 8) Verify the commutative property or set intersection for A = {S, C, I, W, 6,9,12, 0}, B = {6, 15, 9, -6, C, I, W, Q }
Answer:_______________ |
| 9) If A = {4, 6,7, 8, 9}, B = {2, 4, 6} and C = { 1, 2, 3, 4, 5, 6,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
Answer:_______________ |
| 10) Verify the commutative property or set intersection for A = {F, S, O, I, 6,9,12, 0}, B = {6, 15, 9, -6, S, O, I, A }
Answer:_______________ |
| 1) If A = {16, 24,28, 32, 36}, B = {8, 16, 24} and C = { 4, 8, 12, 16, 20, 24,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
SOLUTION 1 : Solution: (i) A ∪ ( B ∩ C) B ∩C = {8,16,24} ∪ { 4, 8, 12, 16, 20, 24} = {8,16,24} A ∪ ( B ∩ C) = {16, 24,28, 32, 36} ∪ {8,16,24} = {8, 16, 24, 28, 32, 36} (ii) A ∪ (B∪C) B ∪ C = { 8,16,24} ∪ {4, 8, 12, 16, 20,24} = { 4, 8, 12, 16, 20, 24} A ∩ (B ∪C ) = { 16, 24, 28, 32, 36 } ∩ { 4, 8, 12, 16, 20, 24} = { 16,24} (iii) /C ) B C = { 4, 8, 12, 16, 20, 24 } { 8, 16, 24 } = { 4, 12, 20 } A /(B /C ) = { 16, 24, 28, 32, 36} { 4, 12, 20 } = { 16, 24, 28, 32, 36 }
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| 2) Verify the commutative property or set intersection for A = {R, N, P, O, 2,3,4, 0}, B = {2, 5, 3, -2, N, P, O, W }
SOLUTION 1 : Solution: Now A ∩ B = = { R, N, P, O, 2, 3, 4, 0} ∩ {2, 5, 3, -2, N, P, O, W } A ∩ B = { N,P,O, 2, 3 } ............(1) Also B ∩ A = {2, 5, 3, -2, N, P, O, W } ∩ { R, N, P, O, 2, 3, 4, 0} B ∩ A = { N,P,O, 2, 3 } ..............(2) From (1) and (2) we have A ∩ B = B ∩ A for the given sets A, B. Hence the commutative property of set intersection is verified.
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| 3) If A = {8, 12,14, 16, 18}, B = {4, 8, 12} and C = { 2, 4, 6, 8, 10, 12,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
SOLUTION 1 : Solution: (i) A ∪ ( B ∩ C) B ∩C = {4,8,12} ∪ { 2, 4, 6, 8, 10, 12} = {4,8,12} A ∪ ( B ∩ C) = {8, 12,14, 16, 18} ∪ {4,8,12} = {4, 8, 12, 14, 16, 18} (ii) A ∪ (B∪C) B ∪ C = { 4,8,12} ∪ {2, 4, 6, 8, 10,12} = { 2, 4, 6, 8, 10, 12} A ∩ (B ∪C ) = { 8, 12, 14, 16, 18 } ∩ { 2, 4, 6, 8, 10, 12} = { 8,12} (iii) /C ) B C = { 2, 4, 6, 8, 10, 12 } { 4, 8, 12 } = { 2, 6, 10 } A /(B /C ) = { 8, 12, 14, 16, 18} { 2, 6, 10 } = { 8, 12, 14, 16, 18 }
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| 4) Verify the commutative property or set intersection for A = {G, O, I, K, 2,3,4, 0}, B = {2, 5, 3, -2, O, I, K, B }
SOLUTION 1 : Solution: Now A ∩ B = = { G, O, I, K, 2, 3, 4, 0} ∩ {2, 5, 3, -2, O, I, K, B } A ∩ B = { O,I,K, 2, 3 } ............(1) Also B ∩ A = {2, 5, 3, -2, O, I, K, B } ∩ { G, O, I, K, 2, 3, 4, 0} B ∩ A = { O,I,K, 2, 3 } ..............(2) From (1) and (2) we have A ∩ B = B ∩ A for the given sets A, B. Hence the commutative property of set intersection is verified.
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| 5) If A = {4, 6,7, 8, 9}, B = {2, 4, 6} and C = { 1, 2, 3, 4, 5, 6,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
SOLUTION 1 : Solution: (i) A ∪ ( B ∩ C) B ∩C = {2,4,6} ∪ { 1, 2, 3, 4, 5, 6} = {2,4,6} A ∪ ( B ∩ C) = {4, 6,7, 8, 9} ∪ {2,4,6} = {2, 4, 6, 7, 8, 9} (ii) A ∪ (B∪C) B ∪ C = { 2,4,6} ∪ {1, 2, 3, 4, 5,6} = { 1, 2, 3, 4, 5, 6} A ∩ (B ∪C ) = { 4, 6, 7, 8, 9 } ∩ { 1, 2, 3, 4, 5, 6} = { 4,6} (iii) /C ) B C = { 1, 2, 3, 4, 5, 6 } { 2, 4, 6 } = { 1, 3, 5 } A /(B /C ) = { 4, 6, 7, 8, 9} { 1, 3, 5 } = { 4, 6, 7, 8, 9 }
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| 6) Verify the commutative property or set intersection for A = {O, M, D, N, 4,6,8, 0}, B = {4, 10, 6, -4, M, D, N, L }
SOLUTION 1 : Solution: Now A ∩ B = = { O, M, D, N, 4, 6, 8, 0} ∩ {4, 10, 6, -4, M, D, N, L } A ∩ B = { M,D,N, 4, 6 } ............(1) Also B ∩ A = {4, 10, 6, -4, M, D, N, L } ∩ { O, M, D, N, 4, 6, 8, 0} B ∩ A = { M,D,N, 4, 6 } ..............(2) From (1) and (2) we have A ∩ B = B ∩ A for the given sets A, B. Hence the commutative property of set intersection is verified.
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| 7) If A = {12, 18,21, 24, 27}, B = {6, 12, 18} and C = { 3, 6, 9, 12, 15, 18,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
SOLUTION 1 : Solution: (i) A ∪ ( B ∩ C) B ∩C = {6,12,18} ∪ { 3, 6, 9, 12, 15, 18} = {6,12,18} A ∪ ( B ∩ C) = {12, 18,21, 24, 27} ∪ {6,12,18} = {6, 12, 18, 21, 24, 27} (ii) A ∪ (B∪C) B ∪ C = { 6,12,18} ∪ {3, 6, 9, 12, 15,18} = { 3, 6, 9, 12, 15, 18} A ∩ (B ∪C ) = { 12, 18, 21, 24, 27 } ∩ { 3, 6, 9, 12, 15, 18} = { 12,18} (iii) /C ) B C = { 3, 6, 9, 12, 15, 18 } { 6, 12, 18 } = { 3, 9, 15 } A /(B /C ) = { 12, 18, 21, 24, 27} { 3, 9, 15 } = { 12, 18, 21, 24, 27 }
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| 8) Verify the commutative property or set intersection for A = {X, R, G, V, 6,9,12, 0}, B = {6, 15, 9, -6, R, G, V, Z }
SOLUTION 1 : Solution: Now A ∩ B = = { X, R, G, V, 6, 9, 12, 0} ∩ {6, 15, 9, -6, R, G, V, Z } A ∩ B = { R,G,V, 6, 9 } ............(1) Also B ∩ A = {6, 15, 9, -6, R, G, V, Z } ∩ { X, R, G, V, 6, 9, 12, 0} B ∩ A = { R,G,V, 6, 9 } ..............(2) From (1) and (2) we have A ∩ B = B ∩ A for the given sets A, B. Hence the commutative property of set intersection is verified.
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| 9) If A = {4, 6,7, 8, 9}, B = {2, 4, 6} and C = { 1, 2, 3, 4, 5, 6,} then find (i) A∪(B ∩ C) (ii) A∪(B∪C) (iii) A\(C\B )
SOLUTION 1 : Solution: (i) A ∪ ( B ∩ C) B ∩C = {2,4,6} ∪ { 1, 2, 3, 4, 5, 6} = {2,4,6} A ∪ ( B ∩ C) = {4, 6,7, 8, 9} ∪ {2,4,6} = {2, 4, 6, 7, 8, 9} (ii) A ∪ (B∪C) B ∪ C = { 2,4,6} ∪ {1, 2, 3, 4, 5,6} = { 1, 2, 3, 4, 5, 6} A ∩ (B ∪C ) = { 4, 6, 7, 8, 9 } ∩ { 1, 2, 3, 4, 5, 6} = { 4,6} (iii) /C ) B C = { 1, 2, 3, 4, 5, 6 } { 2, 4, 6 } = { 1, 3, 5 } A /(B /C ) = { 4, 6, 7, 8, 9} { 1, 3, 5 } = { 4, 6, 7, 8, 9 }
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| 10) Verify the commutative property or set intersection for A = {E, Q, T, Z, 6,9,12, 0}, B = {6, 15, 9, -6, Q, T, Z, P }
SOLUTION 1 : Solution: Now A ∩ B = = { E, Q, T, Z, 6, 9, 12, 0} ∩ {6, 15, 9, -6, Q, T, Z, P } A ∩ B = { Q,T,Z, 6, 9 } ............(1) Also B ∩ A = {6, 15, 9, -6, Q, T, Z, P } ∩ { E, Q, T, Z, 6, 9, 12, 0} B ∩ A = { Q,T,Z, 6, 9 } ..............(2) From (1) and (2) we have A ∩ B = B ∩ A for the given sets A, B. Hence the commutative property of set intersection is verified.
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