Sasi Math (Revised for 1024)

Scroll:Mensuration >> circumference of cone >> ps (4132)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

The circumference of the base of a 27m high wooden solid cone is 132m. Find the volume.

27m

2π r=132 m

___m³

Answer:_______________

The circumference of the base of a 21m high wooden solid cone is 44m. Find the volume.

21m

2π r=44 m

___m³

Answer:_______________

The circumference of the base of a 15m high wooden solid cone is 44m. Find the volume.

15m

2π r=44 m

___m³

Answer:_______________

The circumference of the base of a 27m high wooden solid cone is 88m. Find the volume.

27m

2π r=88 m

___m³

Answer:_______________

The circumference of the base of a 27m high wooden solid cone is 44m. Find the volume.

27m

2π r=44 m

___m³

Answer:_______________

The circumference of the base of a 15m high wooden solid cone is 88m. Find the volume.

15m

2π r=88 m

___m³

Answer:_______________

The circumference of the base of a 24m high wooden solid cone is 132m. Find the volume.

24m

2π r=132 m

___m³

Answer:_______________

The circumference of the base of a 21m high wooden solid cone is 132m. Find the volume.

21m

2π r=132 m

___m³

Answer:_______________

The circumference of the base of a 15m high wooden solid cone is 132m. Find the volume.

15m

2π r=132 m

___m³

Answer:_______________

10)

The circumference of the base of a 12m high wooden solid cone is 132m. Find the volume.

12m

2π r=132 m

___m³

Answer:_______________

The circumference of the base of a 27m high wooden solid cone is 132m. Find the volume.

27m

2π r=132 m

Answer: 12474m³

SOLUTION 1 :

Given:

Height (h) = 27m

Circumference of cone = 132m

⇒ 2π r = 132m ⇒ 2 x $\frac{22}{7}$ x r = 132m

⇒ r = (132x7)/(2x22) = $\frac{924}{44}$

⇒ r = 21

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 21 x 21 x 27 = 12474m³

Volume of cone = 12474m³

The circumference of the base of a 21m high wooden solid cone is 44m. Find the volume.

21m

2π r=44 m

Answer: 1078m³

SOLUTION 1 :

Given:

Height (h) = 21m

Circumference of cone = 44m

⇒ 2π r = 44m ⇒ 2 x $\frac{22}{7}$ x r = 44m

⇒ r = (44x7)/(2x22) = $\frac{308}{44}$

⇒ r = 7

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 7 x 7 x 21 = 1078m³

Volume of cone = 1078m³

The circumference of the base of a 15m high wooden solid cone is 44m. Find the volume.

15m

2π r=44 m

Answer: 770m³

SOLUTION 1 :

Given:

Height (h) = 15m

Circumference of cone = 44m

⇒ 2π r = 44m ⇒ 2 x $\frac{22}{7}$ x r = 44m

⇒ r = (44x7)/(2x22) = $\frac{308}{44}$

⇒ r = 7

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 7 x 7 x 15 = 770m³

Volume of cone = 770m³

The circumference of the base of a 27m high wooden solid cone is 88m. Find the volume.

27m

2π r=88 m

Answer: 5544m³

SOLUTION 1 :

Given:

Height (h) = 27m

Circumference of cone = 88m

⇒ 2π r = 88m ⇒ 2 x $\frac{22}{7}$ x r = 88m

⇒ r = (88x7)/(2x22) = $\frac{616}{44}$

⇒ r = 14

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 14 x 14 x 27 = 5544m³

Volume of cone = 5544m³

The circumference of the base of a 27m high wooden solid cone is 44m. Find the volume.

27m

2π r=44 m

Answer: 1386m³

SOLUTION 1 :

Given:

Height (h) = 27m

Circumference of cone = 44m

⇒ 2π r = 44m ⇒ 2 x $\frac{22}{7}$ x r = 44m

⇒ r = (44x7)/(2x22) = $\frac{308}{44}$

⇒ r = 7

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 7 x 7 x 27 = 1386m³

Volume of cone = 1386m³

The circumference of the base of a 15m high wooden solid cone is 88m. Find the volume.

15m

2π r=88 m

Answer: 3080m³

SOLUTION 1 :

Given:

Height (h) = 15m

Circumference of cone = 88m

⇒ 2π r = 88m ⇒ 2 x $\frac{22}{7}$ x r = 88m

⇒ r = (88x7)/(2x22) = $\frac{616}{44}$

⇒ r = 14

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 14 x 14 x 15 = 3080m³

Volume of cone = 3080m³

The circumference of the base of a 24m high wooden solid cone is 132m. Find the volume.

24m

2π r=132 m

Answer: 11088m³

SOLUTION 1 :

Given:

Height (h) = 24m

Circumference of cone = 132m

⇒ 2π r = 132m ⇒ 2 x $\frac{22}{7}$ x r = 132m

⇒ r = (132x7)/(2x22) = $\frac{924}{44}$

⇒ r = 21

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 21 x 21 x 24 = 11088m³

Volume of cone = 11088m³

The circumference of the base of a 21m high wooden solid cone is 132m. Find the volume.

21m

2π r=132 m

Answer: 9702m³

SOLUTION 1 :

Given:

Height (h) = 21m

Circumference of cone = 132m

⇒ 2π r = 132m ⇒ 2 x $\frac{22}{7}$ x r = 132m

⇒ r = (132x7)/(2x22) = $\frac{924}{44}$

⇒ r = 21

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 21 x 21 x 21 = 9702m³

Volume of cone = 9702m³

The circumference of the base of a 15m high wooden solid cone is 132m. Find the volume.

15m

2π r=132 m

Answer: 6930m³

SOLUTION 1 :

Given:

Height (h) = 15m

Circumference of cone = 132m

⇒ 2π r = 132m ⇒ 2 x $\frac{22}{7}$ x r = 132m

⇒ r = (132x7)/(2x22) = $\frac{924}{44}$

⇒ r = 21

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 21 x 21 x 15 = 6930m³

Volume of cone = 6930m³

10)

The circumference of the base of a 12m high wooden solid cone is 132m. Find the volume.

12m

2π r=132 m

Answer: 5544m³

SOLUTION 1 :

Given:

Height (h) = 12m

Circumference of cone = 132m

⇒ 2π r = 132m ⇒ 2 x $\frac{22}{7}$ x r = 132m

⇒ r = (132x7)/(2x22) = $\frac{924}{44}$

⇒ r = 21

Volume of cone = $\frac{1}{3}$ πr²h cubic units

= $\frac{1}{3}$ x $\frac{22}{7}$ x 21 x 21 x 12 = 5544m³

Volume of cone = 5544m³