Sasi Math (Revised for 1024)

Scroll:Mensuration >> volume of cylinder >> ps (4129)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A lead pencil is in the shape of right circular cylinder. The pencil is 21cm long and its radius is 7 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

21cm

7mm

2mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 23cm long and its radius is 6 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

23cm

6mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 21cm long and its radius is 9 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

21cm

9mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 28cm long and its radius is 8 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

28cm

8mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 28cm long and its radius is 5 mm. If the lead is of radius 3mm, then find find the volume of the wood used in the pencil.

28cm

5mm

3mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 26cm long and its radius is 5 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

26cm

5mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 20cm long and its radius is 5 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

20cm

5mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 26cm long and its radius is 8 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

26cm

8mm

2mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 21cm long and its radius is 7 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

21cm

7mm

1mm(lead)

cm3

Answer:_______________

10)

A lead pencil is in the shape of right circular cylinder. The pencil is 29cm long and its radius is 6 mm. If the lead is of radius 3mm, then find find the volume of the wood used in the pencil.

29cm

6mm

3mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 21cm long and its radius is 7 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

21cm

7mm

2mm(lead)

Answer: 29.70 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 21cm

Radius of the pencil (R) = 7mm = $\frac{7}{10}$ cm

Radius of the lead = r = 2 mm = $\frac{2}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 21 x ( $\frac{7}{10}$ + $\frac{2}{10}$ ) x ( $\frac{7}{10}$ - $\frac{2}{10}$ )

= 66.00 x ( $\frac{9}{10}$ ) x $\frac{(5}{10)}$ cm³

= 66.00X45 / 100 cm³ = 2970 / 100 = 29.70 cm³

Volume of the wood used in the pencil is 29.70 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 23cm long and its radius is 6 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

23cm

6mm

1mm(lead)

Answer: 25.30 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 23cm

Radius of the pencil (R) = 6mm = $\frac{6}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 23 x ( $\frac{6}{10}$ + $\frac{1}{10}$ ) x ( $\frac{6}{10}$ - $\frac{1}{10}$ )

= 72.29 x ( $\frac{7}{10}$ ) x $\frac{(5}{10)}$ cm³

= 72.29X35 / 100 cm³ = 2530.15 / 100 = 25.30 cm³

Volume of the wood used in the pencil is 25.30 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 21cm long and its radius is 9 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

21cm

9mm

1mm(lead)

Answer: 52.80 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 21cm

Radius of the pencil (R) = 9mm = $\frac{9}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 21 x ( $\frac{9}{10}$ + $\frac{1}{10}$ ) x ( $\frac{9}{10}$ - $\frac{1}{10}$ )

= 66.00 x ( $\frac{10}{10}$ ) x $\frac{(8}{10)}$ cm³

= 66.00X80 / 100 cm³ = 5280 / 100 = 52.80 cm³

Volume of the wood used in the pencil is 52.80 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 28cm long and its radius is 8 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

28cm

8mm

1mm(lead)

Answer: 55.44 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 28cm

Radius of the pencil (R) = 8mm = $\frac{8}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 28 x ( $\frac{8}{10}$ + $\frac{1}{10}$ ) x ( $\frac{8}{10}$ - $\frac{1}{10}$ )

= 88.00 x ( $\frac{9}{10}$ ) x $\frac{(7}{10)}$ cm³

= 88.00X63 / 100 cm³ = 5544 / 100 = 55.44 cm³

Volume of the wood used in the pencil is 55.44 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 28cm long and its radius is 5 mm. If the lead is of radius 3mm, then find find the volume of the wood used in the pencil.

28cm

5mm

3mm(lead)

Answer: 14.08 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 28cm

Radius of the pencil (R) = 5mm = $\frac{5}{10}$ cm

Radius of the lead = r = 3 mm = $\frac{3}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 28 x ( $\frac{5}{10}$ + $\frac{3}{10}$ ) x ( $\frac{5}{10}$ - $\frac{3}{10}$ )

= 88.00 x ( $\frac{8}{10}$ ) x $\frac{(2}{10)}$ cm³

= 88.00X16 / 100 cm³ = 1408 / 100 = 14.08 cm³

Volume of the wood used in the pencil is 14.08 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 26cm long and its radius is 5 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

26cm

5mm

1mm(lead)

Answer: 19.61 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 26cm

Radius of the pencil (R) = 5mm = $\frac{5}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 26 x ( $\frac{5}{10}$ + $\frac{1}{10}$ ) x ( $\frac{5}{10}$ - $\frac{1}{10}$ )

= 81.71 x ( $\frac{6}{10}$ ) x $\frac{(4}{10)}$ cm³

= 81.71X24 / 100 cm³ = 1961.04 / 100 = 19.61 cm³

Volume of the wood used in the pencil is 19.61 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 20cm long and its radius is 5 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

20cm

5mm

1mm(lead)

Answer: 15.09 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 20cm

Radius of the pencil (R) = 5mm = $\frac{5}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 20 x ( $\frac{5}{10}$ + $\frac{1}{10}$ ) x ( $\frac{5}{10}$ - $\frac{1}{10}$ )

= 62.86 x ( $\frac{6}{10}$ ) x $\frac{(4}{10)}$ cm³

= 62.86X24 / 100 cm³ = 1508.64 / 100 = 15.09 cm³

Volume of the wood used in the pencil is 15.09 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 26cm long and its radius is 8 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

26cm

8mm

2mm(lead)

Answer: 49.03 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 26cm

Radius of the pencil (R) = 8mm = $\frac{8}{10}$ cm

Radius of the lead = r = 2 mm = $\frac{2}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 26 x ( $\frac{8}{10}$ + $\frac{2}{10}$ ) x ( $\frac{8}{10}$ - $\frac{2}{10}$ )

= 81.71 x ( $\frac{10}{10}$ ) x $\frac{(6}{10)}$ cm³

= 81.71X60 / 100 cm³ = 4902.6 / 100 = 49.03 cm³

Volume of the wood used in the pencil is 49.03 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 21cm long and its radius is 7 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

21cm

7mm

1mm(lead)

Answer: 31.68 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 21cm

Radius of the pencil (R) = 7mm = $\frac{7}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 21 x ( $\frac{7}{10}$ + $\frac{1}{10}$ ) x ( $\frac{7}{10}$ - $\frac{1}{10}$ )

= 66.00 x ( $\frac{8}{10}$ ) x $\frac{(6}{10)}$ cm³

= 66.00X48 / 100 cm³ = 3168 / 100 = 31.68 cm³

Volume of the wood used in the pencil is 31.68 cm³

10)

A lead pencil is in the shape of right circular cylinder. The pencil is 29cm long and its radius is 6 mm. If the lead is of radius 3mm, then find find the volume of the wood used in the pencil.

29cm

6mm

3mm(lead)

Answer: 24.61 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 29cm

Radius of the pencil (R) = 6mm = $\frac{6}{10}$ cm

Radius of the lead = r = 3 mm = $\frac{3}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 29 x ( $\frac{6}{10}$ + $\frac{3}{10}$ ) x ( $\frac{6}{10}$ - $\frac{3}{10}$ )

= 91.14 x ( $\frac{9}{10}$ ) x ( $\frac{3}{10}$ ) cm³

= 91.14X27 / 100 cm³ = 2460.78 / 100 = 24.61 cm³

Volume of the wood used in the pencil is 24.61 cm³