Sasi Math (Revised for 1024)

Scroll:Mensuration >> volume of cylinder >> ps (4129)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A lead pencil is in the shape of right circular cylinder. The pencil is 29cm long and its radius is 6 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

29cm

6mm

2mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 29cm long and its radius is 5 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

29cm

5mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 27cm long and its radius is 7 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

27cm

7mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 23cm long and its radius is 8 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

23cm

8mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 24cm long and its radius is 6 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

24cm

6mm

1mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 29cm long and its radius is 7 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

29cm

7mm

2mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 23cm long and its radius is 6 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

23cm

6mm

2mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 24cm long and its radius is 5 mm. If the lead is of radius 3mm, then find find the volume of the wood used in the pencil.

24cm

5mm

3mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 20cm long and its radius is 6 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

20cm

6mm

2mm(lead)

cm3

Answer:_______________

10)

A lead pencil is in the shape of right circular cylinder. The pencil is 25cm long and its radius is 6 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

25cm

6mm

2mm(lead)

cm3

Answer:_______________

A lead pencil is in the shape of right circular cylinder. The pencil is 29cm long and its radius is 6 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

29cm

6mm

2mm(lead)

Answer: 29.16 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 29cm

Radius of the pencil (R) = 6mm = $\frac{6}{10}$ cm

Radius of the lead = r = 2 mm = $\frac{2}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 29 x ( $\frac{6}{10}$ + $\frac{2}{10}$ ) x ( $\frac{6}{10}$ - $\frac{2}{10}$ )

= 91.14 x ( $\frac{8}{10}$ ) x $\frac{(4}{10)}$ cm³

= 91.14X32 / 100 cm³ = 2916.48 / 100 = 29.16 cm³

Volume of the wood used in the pencil is 29.16 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 29cm long and its radius is 5 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

29cm

5mm

1mm(lead)

Answer: 21.87 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 29cm

Radius of the pencil (R) = 5mm = $\frac{5}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 29 x ( $\frac{5}{10}$ + $\frac{1}{10}$ ) x ( $\frac{5}{10}$ - $\frac{1}{10}$ )

= 91.14 x ( $\frac{6}{10}$ ) x $\frac{(4}{10)}$ cm³

= 91.14X24 / 100 cm³ = 2187.36 / 100 = 21.87 cm³

Volume of the wood used in the pencil is 21.87 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 27cm long and its radius is 7 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

27cm

7mm

1mm(lead)

Answer: 40.73 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 27cm

Radius of the pencil (R) = 7mm = $\frac{7}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 27 x ( $\frac{7}{10}$ + $\frac{1}{10}$ ) x ( $\frac{7}{10}$ - $\frac{1}{10}$ )

= 84.86 x ( $\frac{8}{10}$ ) x $\frac{(6}{10)}$ cm³

= 84.86X48 / 100 cm³ = 4073.28 / 100 = 40.73 cm³

Volume of the wood used in the pencil is 40.73 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 23cm long and its radius is 8 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

23cm

8mm

1mm(lead)

Answer: 45.54 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 23cm

Radius of the pencil (R) = 8mm = $\frac{8}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 23 x ( $\frac{8}{10}$ + $\frac{1}{10}$ ) x ( $\frac{8}{10}$ - $\frac{1}{10}$ )

= 72.29 x ( $\frac{9}{10}$ ) x $\frac{(7}{10)}$ cm³

= 72.29X63 / 100 cm³ = 4554.27 / 100 = 45.54 cm³

Volume of the wood used in the pencil is 45.54 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 24cm long and its radius is 6 mm. If the lead is of radius 1mm, then find find the volume of the wood used in the pencil.

24cm

6mm

1mm(lead)

Answer: 26.40 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 24cm

Radius of the pencil (R) = 6mm = $\frac{6}{10}$ cm

Radius of the lead = r = 1 mm = $\frac{1}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 24 x ( $\frac{6}{10}$ + $\frac{1}{10}$ ) x ( $\frac{6}{10}$ - $\frac{1}{10}$ )

= 75.43 x ( $\frac{7}{10}$ ) x $\frac{(5}{10)}$ cm³

= 75.43X35 / 100 cm³ = 2640.05 / 100 = 26.40 cm³

Volume of the wood used in the pencil is 26.40 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 29cm long and its radius is 7 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

29cm

7mm

2mm(lead)

Answer: 41.01 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 29cm

Radius of the pencil (R) = 7mm = $\frac{7}{10}$ cm

Radius of the lead = r = 2 mm = $\frac{2}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 29 x ( $\frac{7}{10}$ + $\frac{2}{10}$ ) x ( $\frac{7}{10}$ - $\frac{2}{10}$ )

= 91.14 x ( $\frac{9}{10}$ ) x $\frac{(5}{10)}$ cm³

= 91.14X45 / 100 cm³ = 4101.3 / 100 = 41.01 cm³

Volume of the wood used in the pencil is 41.01 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 23cm long and its radius is 6 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

23cm

6mm

2mm(lead)

Answer: 23.13 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 23cm

Radius of the pencil (R) = 6mm = $\frac{6}{10}$ cm

Radius of the lead = r = 2 mm = $\frac{2}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 23 x ( $\frac{6}{10}$ + $\frac{2}{10}$ ) x ( $\frac{6}{10}$ - $\frac{2}{10}$ )

= 72.29 x ( $\frac{8}{10}$ ) x $\frac{(4}{10)}$ cm³

= 72.29X32 / 100 cm³ = 2313.28 / 100 = 23.13 cm³

Volume of the wood used in the pencil is 23.13 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 24cm long and its radius is 5 mm. If the lead is of radius 3mm, then find find the volume of the wood used in the pencil.

24cm

5mm

3mm(lead)

Answer: 12.07 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 24cm

Radius of the pencil (R) = 5mm = $\frac{5}{10}$ cm

Radius of the lead = r = 3 mm = $\frac{3}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 24 x ( $\frac{5}{10}$ + $\frac{3}{10}$ ) x ( $\frac{5}{10}$ - $\frac{3}{10}$ )

= 75.43 x ( $\frac{8}{10}$ ) x $\frac{(2}{10)}$ cm³

= 75.43X16 / 100 cm³ = 1206.88 / 100 = 12.07 cm³

Volume of the wood used in the pencil is 12.07 cm³

A lead pencil is in the shape of right circular cylinder. The pencil is 20cm long and its radius is 6 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

20cm

6mm

2mm(lead)

Answer: 20.12 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 20cm

Radius of the pencil (R) = 6mm = $\frac{6}{10}$ cm

Radius of the lead = r = 2 mm = $\frac{2}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 20 x ( $\frac{6}{10}$ + $\frac{2}{10}$ ) x ( $\frac{6}{10}$ - $\frac{2}{10}$ )

= 62.86 x ( $\frac{8}{10}$ ) x $\frac{(4}{10)}$ cm³

= 62.86X32 / 100 cm³ = 2011.52 / 100 = 20.12 cm³

Volume of the wood used in the pencil is 20.12 cm³

10)

A lead pencil is in the shape of right circular cylinder. The pencil is 25cm long and its radius is 6 mm. If the lead is of radius 2mm, then find find the volume of the wood used in the pencil.

25cm

6mm

2mm(lead)

Answer: 25.14 cm3

SOLUTION 1 :

Given:

Length of pencil (h) = 25cm

Radius of the pencil (R) = 6mm = $\frac{6}{10}$ cm

Radius of the lead = r = 2 mm = $\frac{2}{10}$ cm

To find : Volume of the wood used in the pencil

Solution : Volume of Hollow cylinder = πh(R + r)(R - r)

Volume of the wood in the pencil

= $\frac{22}{7}$ x 25 x ( $\frac{6}{10}$ + $\frac{2}{10}$ ) x ( $\frac{6}{10}$ - $\frac{2}{10}$ )

= 78.57 x ( $\frac{8}{10}$ ) x $\frac{(4}{10)}$ cm³

= 78.57X32 / 100 cm³ = 2514.24 / 100 = 25.14 cm³

Volume of the wood used in the pencil is 25.14 cm³