Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
| 1) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 40° Find ∠AOC. 40° o Answer:_______________ |
| 2) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 78° Find ∠AOC. 78° o Answer:_______________ |
| 3) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 68° Find ∠AOC. 68° o Answer:_______________ |
| 4) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 70° Find ∠AOC. 70° o Answer:_______________ |
| 5) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 54° Find ∠AOC. 54° o Answer:_______________ |
| 6) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 56° Find ∠AOC. 56° o Answer:_______________ |
| 7) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 50° Find ∠AOC. 50° o Answer:_______________ |
| 8) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 62° Find ∠AOC. 62° o Answer:_______________ |
| 9) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 80° Find ∠AOC. 80° o Answer:_______________ |
| 10) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 48° Find ∠AOC. 48° o Answer:_______________ |
| 1) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 40° Find ∠AOC. 40° Answer: 140o SOLUTION 1 : Step 1: ∠BCA = (180 - 40) ÷ 2 = 70o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 20o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 20 - 20 = 140o (sum of angles in a triangle) |
| 2) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 78° Find ∠AOC. 78° Answer: 102o SOLUTION 1 : Step 1: ∠BCA = (180 - 78) ÷ 2 = 51o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 39o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 39 - 39 = 102o (sum of angles in a triangle) |
| 3) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 68° Find ∠AOC. 68° Answer: 112o SOLUTION 1 : Step 1: ∠BCA = (180 - 68) ÷ 2 = 56o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 34o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 34 - 34 = 112o (sum of angles in a triangle) |
| 4) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 70° Find ∠AOC. 70° Answer: 110o SOLUTION 1 : Step 1: ∠BCA = (180 - 70) ÷ 2 = 55o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 35o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 35 - 35 = 110o (sum of angles in a triangle) |
| 5) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 54° Find ∠AOC. 54° Answer: 126o SOLUTION 1 : Step 1: ∠BCA = (180 - 54) ÷ 2 = 63o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 27o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 27 - 27 = 126o (sum of angles in a triangle) |
| 6) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 56° Find ∠AOC. 56° Answer: 124o SOLUTION 1 : Step 1: ∠BCA = (180 - 56) ÷ 2 = 62o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 28o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 28 - 28 = 124o (sum of angles in a triangle) |
| 7) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 50° Find ∠AOC. 50° Answer: 130o SOLUTION 1 : Step 1: ∠BCA = (180 - 50) ÷ 2 = 65o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 25o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 25 - 25 = 130o (sum of angles in a triangle) |
| 8) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 62° Find ∠AOC. 62° Answer: 118o SOLUTION 1 : Step 1: ∠BCA = (180 - 62) ÷ 2 = 59o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 31o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 31 - 31 = 118o (sum of angles in a triangle) |
| 9) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 80° Find ∠AOC. 80° Answer: 100o SOLUTION 1 : Step 1: ∠BCA = (180 - 80) ÷ 2 = 50o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 40o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 40 - 40 = 100o (sum of angles in a triangle) |
| 10) In the figure below, O is the centre of circle. ∠ABC is an isosceles triangle. ∠ABC = 48° Find ∠AOC. 48° Answer: 132o SOLUTION 1 : Step 1: ∠BCA = (180 - 48) ÷ 2 = 66o (isosceles triangle) Step 2: ∠OCA = 90 - 51 = 24o Step 3: ∠OAC = ∠OCA (isosceles triangle, OA and OC are radii of circle) Step 4: ∠AOC = 180 - 24 - 24 = 132o (sum of angles in a triangle) |