Sasi Math (Revised for 1024)

Scroll:Measurement >> Area & Perimeter of Composite Figure >> ps (2904)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

32 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

20 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

18 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

28 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

30 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

26 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

38 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

16 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

24 cm

cm²

Answer:_______________

10)

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

14 cm

cm²

Answer:_______________

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

32 cm

Answer: 101 cm

Answer: 402 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 32 cm

= 64.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 64.000 cm

= 50.272 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 32 cm

= 50.272 cm

Step 4: Perimeter of shaded part → 50.272 cm + 50.272 cm + 32 cm

= 100.544 cm

≈ 101 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 32 cm x 32 cm

= 804.352 cm²

Step 6 : Radius of semi circle → 32 cm ÷ 2

= 16 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 16 cm x 16 cm

= 402.176 cm²

Step 8: Area of shaded part → 804.352 cm² - 402.176 cm²

= 402.176 cm²

≈ 402 cm²

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

20 cm

Answer: 63 cm

Answer: 157 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 20 cm

= 40.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 40.000 cm

= 31.42 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 20 cm

= 31.420 cm

Step 4: Perimeter of shaded part → 31.42 cm + 31.420 cm + 20 cm

= 62.840 cm

≈ 63 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 20 cm x 20 cm

= 314.200 cm²

Step 6 : Radius of semi circle → 20 cm ÷ 2

= 10 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 10 cm x 10 cm

= 157.100 cm²

Step 8: Area of shaded part → 314.200 cm² - 157.100 cm²

= 157.100 cm²

≈ 157 cm²

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

18 cm

Answer: 57 cm

Answer: 127 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 18 cm

= 36.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 36.000 cm

= 28.278 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 18 cm

= 28.278 cm

Step 4: Perimeter of shaded part → 28.278 cm + 28.278 cm + 18 cm

= 56.556 cm

≈ 57 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 18 cm x 18 cm

= 254.502 cm²

Step 6 : Radius of semi circle → 18 cm ÷ 2

= 9 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 9 cm x 9 cm

= 127.251 cm²

Step 8: Area of shaded part → 254.502 cm² - 127.251 cm²

= 127.251 cm²

≈ 127 cm²

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

28 cm

Answer: 88 cm

Answer: 308 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 28 cm

= 56.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 56.000 cm

= 43.988 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 28 cm

= 43.988 cm

Step 4: Perimeter of shaded part → 43.988 cm + 43.988 cm + 28 cm

= 87.976 cm

≈ 88 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 28 cm x 28 cm

= 615.832 cm²

Step 6 : Radius of semi circle → 28 cm ÷ 2

= 14 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 14 cm x 14 cm

= 307.916 cm²

Step 8: Area of shaded part → 615.832 cm² - 307.916 cm²

= 307.916 cm²

≈ 308 cm²

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

30 cm

Answer: 94 cm

Answer: 353 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 30 cm

= 60.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 60.000 cm

= 47.13 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 30 cm

= 47.130 cm

Step 4: Perimeter of shaded part → 47.13 cm + 47.130 cm + 30 cm

= 94.260 cm

≈ 94 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 30 cm x 30 cm

= 706.950 cm²

Step 6 : Radius of semi circle → 30 cm ÷ 2

= 15 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 15 cm x 15 cm

= 353.475 cm²

Step 8: Area of shaded part → 706.950 cm² - 353.475 cm²

= 353.475 cm²

≈ 353 cm²

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

26 cm

Answer: 82 cm

Answer: 265 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 26 cm

= 52.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 52.000 cm

= 40.846 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 26 cm

= 40.846 cm

Step 4: Perimeter of shaded part → 40.846 cm + 40.846 cm + 26 cm

= 81.692 cm

≈ 82 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 26 cm x 26 cm

= 530.998 cm²

Step 6 : Radius of semi circle → 26 cm ÷ 2

= 13 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 13 cm x 13 cm

= 265.499 cm²

Step 8: Area of shaded part → 530.998 cm² - 265.499 cm²

= 265.499 cm²

≈ 265 cm²

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

38 cm

Answer: 119 cm

Answer: 567 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 38 cm

= 76.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 76.000 cm

= 59.698 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 38 cm

= 59.698 cm

Step 4: Perimeter of shaded part → 59.698 cm + 59.698 cm + 38 cm

= 119.396 cm

≈ 119 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 38 cm x 38 cm

= 1134.262 cm²

Step 6 : Radius of semi circle → 38 cm ÷ 2

= 19 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 19 cm x 19 cm

= 567.131 cm²

Step 8: Area of shaded part → 1134.262 cm² - 567.131 cm²

= 567.131 cm²

≈ 567 cm²

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

16 cm

Answer: 50 cm

Answer: 101 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 16 cm

= 32.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 32.000 cm

= 25.136 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 16 cm

= 25.136 cm

Step 4: Perimeter of shaded part → 25.136 cm + 25.136 cm + 16 cm

= 50.272 cm

≈ 50 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 16 cm x 16 cm

= 201.088 cm²

Step 6 : Radius of semi circle → 16 cm ÷ 2

= 8 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 8 cm x 8 cm

= 100.544 cm²

Step 8: Area of shaded part → 201.088 cm² - 100.544 cm²

= 100.544 cm²

≈ 101 cm²

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

24 cm

Answer: 75 cm

Answer: 226 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 24 cm

= 48.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 48.000 cm

= 37.704 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 24 cm

= 37.704 cm

Step 4: Perimeter of shaded part → 37.704 cm + 37.704 cm + 24 cm

= 75.408 cm

≈ 75 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 24 cm x 24 cm

= 452.448 cm²

Step 6 : Radius of semi circle → 24 cm ÷ 2

= 12 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 12 cm x 12 cm

= 226.224 cm²

Step 8: Area of shaded part → 452.448 cm² - 226.224 cm²

= 226.224 cm²

≈ 226 cm²

10)

The figure below is formed by using a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

14 cm

Answer: 44 cm

Answer: 77 cm²

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 14 cm

= 28.000 cm

Step 2: Circumference of quarter circle → $\frac{1}{4}$ x π x 28.000 cm

= 21.994 cm

Step 3: Circumference of semi circle → $\frac{1}{2}$ x π x 14 cm

= 21.994 cm

Step 4: Perimeter of shaded part → 21.994 cm + 21.994 cm + 14 cm

= 43.988 cm

≈ 44 cm

Step 5: Area of quarter cicle → $\frac{1}{4}$ x π x 14 cm x 14 cm

= 153.958 cm²

Step 6 : Radius of semi circle → 14 cm ÷ 2

= 7 cm

Step 7: Area of semi circle → $\frac{1}{2}$ x π x 7 cm x 7 cm

= 76.979 cm²

Step 8: Area of shaded part → 153.958 cm² - 76.979 cm²

= 76.979 cm²

≈ 77 cm²