Sasi Math (Revised for 1024)

Scroll:Percentage >> Percentage >> saq (2896)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A bag consists of a number of 20-cent and 50-cent coins. There are 55% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 360 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 75 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 60% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 760 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 510 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 345 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 55% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 495 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 550 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 60% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 440 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 450 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

10)

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 75 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

Answer: $488

SOLUTION 1 :

Step 1:	20-cent coins	→ 55%
	50-cent coins	→ 100%
	Difference	→ 100% - 55%
		= 45%
Step 2:	45%	→ 360	(difference)
	1%	→ $\frac{360}{45%}$
	55%	→ $\frac{360}{45%}$ x $\frac{55%}{1}$	(number of 20-cent coins)
		= 440
	100%	→ $\frac{360}{45%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 800
Step 3:	Amount of money in the bag	→ (440 x $0.20) + (800 x $0.50)
		= $488

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 75 more 50-cent coins than 20-cent coins

Answer: $195

SOLUTION 1 :

Step 1:	20-cent coins	→ 75%
	50-cent coins	→ 100%
	Difference	→ 100% - 75%
		= 25%
Step 2:	25%	→ 75	(difference)
	1%	→ $\frac{75}{25%}$
	75%	→ $\frac{75}{25%}$ x $\frac{75%}{1}$	(number of 20-cent coins)
		= 225
	100%	→ $\frac{75}{25%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 300
Step 3:	Amount of money in the bag	→ (225 x $0.20) + (300 x $0.50)
		= $195

Answer: $1178

SOLUTION 1 :

Step 1:	20-cent coins	→ 60%
	50-cent coins	→ 100%
	Difference	→ 100% - 60%
		= 40%
Step 2:	40%	→ 760	(difference)
	1%	→ $\frac{760}{40%}$
	60%	→ $\frac{760}{40%}$ x $\frac{60%}{1}$	(number of 20-cent coins)
		= 1140
	100%	→ $\frac{760}{40%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1900
Step 3:	Amount of money in the bag	→ (1140 x $0.20) + (1900 x $0.50)
		= $1178

Answer: $1088

SOLUTION 1 :

Step 1:	20-cent coins	→ 70%
	50-cent coins	→ 100%
	Difference	→ 100% - 70%
		= 30%
Step 2:	30%	→ 510	(difference)
	1%	→ $\frac{510}{30%}$
	70%	→ $\frac{510}{30%}$ x $\frac{70%}{1}$	(number of 20-cent coins)
		= 1190
	100%	→ $\frac{510}{30%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1700
Step 3:	Amount of money in the bag	→ (1190 x $0.20) + (1700 x $0.50)
		= $1088

Answer: $1541

SOLUTION 1 :

Step 1:	20-cent coins	→ 85%
	50-cent coins	→ 100%
	Difference	→ 100% - 85%
		= 15%
Step 2:	15%	→ 345	(difference)
	1%	→ $\frac{345}{15%}$
	85%	→ $\frac{345}{15%}$ x $\frac{85%}{1}$	(number of 20-cent coins)
		= 1955
	100%	→ $\frac{345}{15%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 2300
Step 3:	Amount of money in the bag	→ (1955 x $0.20) + (2300 x $0.50)
		= $1541

Answer: $671

SOLUTION 1 :

Step 1:	20-cent coins	→ 55%
	50-cent coins	→ 100%
	Difference	→ 100% - 55%
		= 45%
Step 2:	45%	→ 495	(difference)
	1%	→ $\frac{495}{45%}$
	55%	→ $\frac{495}{45%}$ x $\frac{55%}{1}$	(number of 20-cent coins)
		= 605
	100%	→ $\frac{495}{45%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1100
Step 3:	Amount of money in the bag	→ (605 x $0.20) + (1100 x $0.50)
		= $671

Answer: $1430

SOLUTION 1 :

Step 1:	20-cent coins	→ 75%
	50-cent coins	→ 100%
	Difference	→ 100% - 75%
		= 25%
Step 2:	25%	→ 550	(difference)
	1%	→ $\frac{550}{25%}$
	75%	→ $\frac{550}{25%}$ x $\frac{75%}{1}$	(number of 20-cent coins)
		= 1650
	100%	→ $\frac{550}{25%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 2200
Step 3:	Amount of money in the bag	→ (1650 x $0.20) + (2200 x $0.50)
		= $1430

Answer: $682

SOLUTION 1 :

Step 1:	20-cent coins	→ 60%
	50-cent coins	→ 100%
	Difference	→ 100% - 60%
		= 40%
Step 2:	40%	→ 440	(difference)
	1%	→ $\frac{440}{40%}$
	60%	→ $\frac{440}{40%}$ x $\frac{60%}{1}$	(number of 20-cent coins)
		= 660
	100%	→ $\frac{440}{40%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1100
Step 3:	Amount of money in the bag	→ (660 x $0.20) + (1100 x $0.50)
		= $682

Answer: $960

SOLUTION 1 :

Step 1:	20-cent coins	→ 70%
	50-cent coins	→ 100%
	Difference	→ 100% - 70%
		= 30%
Step 2:	30%	→ 450	(difference)
	1%	→ $\frac{450}{30%}$
	70%	→ $\frac{450}{30%}$ x $\frac{70%}{1}$	(number of 20-cent coins)
		= 1050
	100%	→ $\frac{450}{30%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1500
Step 3:	Amount of money in the bag	→ (1050 x $0.20) + (1500 x $0.50)
		= $960

10)

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 75 more 50-cent coins than 20-cent coins

Answer: $335

SOLUTION 1 :

Step 1:	20-cent coins	→ 85%
	50-cent coins	→ 100%
	Difference	→ 100% - 85%
		= 15%
Step 2:	15%	→ 75	(difference)
	1%	→ $\frac{75}{15%}$
	85%	→ $\frac{75}{15%}$ x $\frac{85%}{1}$	(number of 20-cent coins)
		= 425
	100%	→ $\frac{75}{15%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 500
Step 3:	Amount of money in the bag	→ (425 x $0.20) + (500 x $0.50)
		= $335