Sasi Math (Revised for 1024)

Scroll:Percentage >> Percentage >> saq (2896)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 120 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 55% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 450 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 285 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 60% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 720 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 375 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 90 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 55% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 675 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 135 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 60% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 200 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

10)

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 250 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

Answer: $256

SOLUTION 1 :

Step 1:	20-cent coins	→ 70%
	50-cent coins	→ 100%
	Difference	→ 100% - 70%
		= 30%
Step 2:	30%	→ 120	(difference)
	1%	→ $\frac{120}{30%}$
	70%	→ $\frac{120}{30%}$ x $\frac{70%}{1}$	(number of 20-cent coins)
		= 280
	100%	→ $\frac{120}{30%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 400
Step 3:	Amount of money in the bag	→ (280 x $0.20) + (400 x $0.50)
		= $256

Answer: $610

SOLUTION 1 :

Step 1:	20-cent coins	→ 55%
	50-cent coins	→ 100%
	Difference	→ 100% - 55%
		= 45%
Step 2:	45%	→ 450	(difference)
	1%	→ $\frac{450}{45%}$
	55%	→ $\frac{450}{45%}$ x $\frac{55%}{1}$	(number of 20-cent coins)
		= 550
	100%	→ $\frac{450}{45%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1000
Step 3:	Amount of money in the bag	→ (550 x $0.20) + (1000 x $0.50)
		= $610

Answer: $1273

SOLUTION 1 :

Step 1:	20-cent coins	→ 85%
	50-cent coins	→ 100%
	Difference	→ 100% - 85%
		= 15%
Step 2:	15%	→ 285	(difference)
	1%	→ $\frac{285}{15%}$
	85%	→ $\frac{285}{15%}$ x $\frac{85%}{1}$	(number of 20-cent coins)
		= 1615
	100%	→ $\frac{285}{15%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1900
Step 3:	Amount of money in the bag	→ (1615 x $0.20) + (1900 x $0.50)
		= $1273

Answer: $1116

SOLUTION 1 :

Step 1:	20-cent coins	→ 60%
	50-cent coins	→ 100%
	Difference	→ 100% - 60%
		= 40%
Step 2:	40%	→ 720	(difference)
	1%	→ $\frac{720}{40%}$
	60%	→ $\frac{720}{40%}$ x $\frac{60%}{1}$	(number of 20-cent coins)
		= 1080
	100%	→ $\frac{720}{40%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1800
Step 3:	Amount of money in the bag	→ (1080 x $0.20) + (1800 x $0.50)
		= $1116

Answer: $975

SOLUTION 1 :

Step 1:	20-cent coins	→ 75%
	50-cent coins	→ 100%
	Difference	→ 100% - 75%
		= 25%
Step 2:	25%	→ 375	(difference)
	1%	→ $\frac{375}{25%}$
	75%	→ $\frac{375}{25%}$ x $\frac{75%}{1}$	(number of 20-cent coins)
		= 1125
	100%	→ $\frac{375}{25%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1500
Step 3:	Amount of money in the bag	→ (1125 x $0.20) + (1500 x $0.50)
		= $975

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 90 more 50-cent coins than 20-cent coins

Answer: $192

SOLUTION 1 :

Step 1:	20-cent coins	→ 70%
	50-cent coins	→ 100%
	Difference	→ 100% - 70%
		= 30%
Step 2:	30%	→ 90	(difference)
	1%	→ $\frac{90}{30%}$
	70%	→ $\frac{90}{30%}$ x $\frac{70%}{1}$	(number of 20-cent coins)
		= 210
	100%	→ $\frac{90}{30%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 300
Step 3:	Amount of money in the bag	→ (210 x $0.20) + (300 x $0.50)
		= $192

Answer: $915

SOLUTION 1 :

Step 1:	20-cent coins	→ 55%
	50-cent coins	→ 100%
	Difference	→ 100% - 55%
		= 45%
Step 2:	45%	→ 675	(difference)
	1%	→ $\frac{675}{45%}$
	55%	→ $\frac{675}{45%}$ x $\frac{55%}{1}$	(number of 20-cent coins)
		= 825
	100%	→ $\frac{675}{45%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1500
Step 3:	Amount of money in the bag	→ (825 x $0.20) + (1500 x $0.50)
		= $915

Answer: $603

SOLUTION 1 :

Step 1:	20-cent coins	→ 85%
	50-cent coins	→ 100%
	Difference	→ 100% - 85%
		= 15%
Step 2:	15%	→ 135	(difference)
	1%	→ $\frac{135}{15%}$
	85%	→ $\frac{135}{15%}$ x $\frac{85%}{1}$	(number of 20-cent coins)
		= 765
	100%	→ $\frac{135}{15%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 900
Step 3:	Amount of money in the bag	→ (765 x $0.20) + (900 x $0.50)
		= $603

Answer: $310

SOLUTION 1 :

Step 1:	20-cent coins	→ 60%
	50-cent coins	→ 100%
	Difference	→ 100% - 60%
		= 40%
Step 2:	40%	→ 200	(difference)
	1%	→ $\frac{200}{40%}$
	60%	→ $\frac{200}{40%}$ x $\frac{60%}{1}$	(number of 20-cent coins)
		= 300
	100%	→ $\frac{200}{40%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 500
Step 3:	Amount of money in the bag	→ (300 x $0.20) + (500 x $0.50)
		= $310

10)

Answer: $650

SOLUTION 1 :

Step 1:	20-cent coins	→ 75%
	50-cent coins	→ 100%
	Difference	→ 100% - 75%
		= 25%
Step 2:	25%	→ 250	(difference)
	1%	→ $\frac{250}{25%}$
	75%	→ $\frac{250}{25%}$ x $\frac{75%}{1}$	(number of 20-cent coins)
		= 750
	100%	→ $\frac{250}{25%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1000
Step 3:	Amount of money in the bag	→ (750 x $0.20) + (1000 x $0.50)
		= $650