Sasi Math (Revised for 1024)

Scroll:Fractions >> Subtraction >> mcq (2505)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Subtract $\frac{1}{3}$ from the sum of $\frac{2}{9}$ and $\frac{4}{9}$ .

1) 69' title="

\frac{6}{9}

"/>

\frac{6}{9}

2) 13' title="

\frac{1}{3}

"/>

\frac{1}{3}

3) 39' title="

\frac{3}{9}

"/>

\frac{3}{9}

4) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

( )

Subtract $\frac{3}{10}$ from the sum of $\frac{1}{10}$ and $\frac{1}{2}$ .

1) 310' title="

\frac{3}{10}

"/>

\frac{3}{10}

2) 710' title="

\frac{7}{10}

"/>

\frac{7}{10}

3) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

4) 25' title="

\frac{2}{5}

"/>

\frac{2}{5}

( )

Subtract $\frac{1}{5}$ from the sum of $\frac{2}{5}$ and $\frac{2}{5}$ .

1) 15' title="

\frac{1}{5}

"/>

\frac{1}{5}

2) 35' title="

\frac{3}{5}

"/>

\frac{3}{5}

3) 25' title="

\frac{2}{5}

"/>

\frac{2}{5}

4) 410' title="

\frac{4}{10}

"/>

\frac{4}{10}

( )

Subtract $\frac{3}{8}$ from the sum of $\frac{3}{4}$ and $\frac{1}{2}$ .

1) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

2) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

3) 78' title="

\frac{7}{8}

"/>

\frac{7}{8}

4) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

( )

Subtract $\frac{1}{8}$ from the sum of $\frac{1}{8}$ and $\frac{1}{2}$ .

1) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

2) 18' title="

\frac{1}{8}

"/>

\frac{1}{8}

3) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

4) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

( )

Subtract $\frac{1}{4}$ from the sum of $\frac{5}{12}$ and $\frac{1}{3}$ .

1) 34' title="

\frac{3}{4}

"/>

\frac{3}{4}

2) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

3) 512' title="

\frac{5}{12}

"/>

\frac{5}{12}

4) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

( )

Subtract $\frac{1}{4}$ from the sum of $\frac{3}{8}$ and $\frac{3}{8}$ .

1) 34' title="

\frac{3}{4}

"/>

\frac{3}{4}

2) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

3) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

4) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

( )

Subtract $\frac{1}{4}$ from the sum of $\frac{1}{3}$ and $\frac{1}{12}$ .

1) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

2) 812' title="

\frac{8}{12}

"/>

\frac{8}{12}

3) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

4) 16' title="

\frac{1}{6}

"/>

\frac{1}{6}

( )

Subtract $\frac{1}{5}$ from the sum of $\frac{1}{10}$ and $\frac{1}{2}$ .

1) 710' title="

\frac{7}{10}

"/>

\frac{7}{10}

2) 35' title="

\frac{3}{5}

"/>

\frac{3}{5}

3) 25' title="

\frac{2}{5}

"/>

\frac{2}{5}

4) 410' title="

\frac{4}{10}

"/>

\frac{4}{10}

( )

10)

Subtract $\frac{1}{3}$ from the sum of $\frac{7}{12}$ and $\frac{1}{4}$ .

1) 56' title="

\frac{5}{6}

"/>

\frac{5}{6}

2) 512' title="

\frac{5}{12}

"/>

\frac{5}{12}

3) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

4) 16' title="

\frac{1}{6}

"/>

\frac{1}{6}

( )

Subtract $\frac{1}{3}$ from the sum of $\frac{2}{9}$ and $\frac{4}{9}$ .

1) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

2) 13' title="

\frac{1}{3}

"/>

\frac{1}{3}

3) 69' title="

\frac{6}{9}

"/>

\frac{6}{9}

4) 39' title="

\frac{3}{9}

"/>

\frac{3}{9}

Answer: 2

SOLUTION 1 :

Step 1:	$\frac{2}{9}$ + $\frac{4}{9}$	= $\frac{6}{9}$
		= $\frac{2}{3}$
Step 2:	$\frac{2}{3}$ - $\frac{1}{3}$	= $\frac{1}{3}$

Subtract $\frac{3}{10}$ from the sum of $\frac{1}{10}$ and $\frac{1}{2}$ .

1) 710' title="

\frac{7}{10}

"/>

\frac{7}{10}

2) 25' title="

\frac{2}{5}

"/>

\frac{2}{5}

3) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

4) 310' title="

\frac{3}{10}

"/>

\frac{3}{10}

Answer: 4

SOLUTION 1 :

Step 1:	$\frac{1}{10}$ + $\frac{1 x 5}{2 x 5}$	= $\frac{1}{10}$ + $\frac{5}{10}$
		= $\frac{6}{10}$
		= $\frac{3}{5}$
Step 2:	$\frac{3 x 2}{5 x 2}$ - $\frac{3}{10}$	= $\frac{6}{10}$ - $\frac{3}{10}$
		= $\frac{3}{10}$

Subtract $\frac{1}{5}$ from the sum of $\frac{2}{5}$ and $\frac{2}{5}$ .

1) 35' title="

\frac{3}{5}

"/>

\frac{3}{5}

2) 15' title="

\frac{1}{5}

"/>

\frac{1}{5}

3) 410' title="

\frac{4}{10}

"/>

\frac{4}{10}

4) 25' title="

\frac{2}{5}

"/>

\frac{2}{5}

Answer: 1

SOLUTION 1 :

Step 1: $\frac{2}{5}$ + $\frac{2}{5}$ = $\frac{4}{5}$

Step 2: $\frac{4}{5}$ - $\frac{1}{5}$ = $\frac{3}{5}$

Subtract $\frac{3}{8}$ from the sum of $\frac{3}{4}$ and $\frac{1}{2}$ .

1) 78' title="

\frac{7}{8}

"/>

\frac{7}{8}

2) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

3) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

4) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

Answer: 1

SOLUTION 1 :

Step 1:	$\frac{3}{4}$ + $\frac{1 x 2}{2 x 2}$	= $\frac{3}{4}$ + $\frac{2}{4}$
		= $\frac{5}{4}$
Step 2:	$\frac{5 x 2}{4 x 2}$ - $\frac{3}{8}$	= $\frac{10}{8}$ - $\frac{3}{8}$
		= $\frac{7}{8}$

Subtract $\frac{1}{8}$ from the sum of $\frac{1}{8}$ and $\frac{1}{2}$ .

1) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

2) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

3) 18' title="

\frac{1}{8}

"/>

\frac{1}{8}

4) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

Answer: 4

SOLUTION 1 :

Step 1:	$\frac{1}{8}$ + $\frac{1 x 4}{2 x 4}$	= $\frac{1}{8}$ + $\frac{4}{8}$
		= $\frac{5}{8}$
Step 2:	$\frac{5}{8}$ - $\frac{1}{8}$	= $\frac{4}{8}$
		= $\frac{1}{2}$

Subtract $\frac{1}{4}$ from the sum of $\frac{5}{12}$ and $\frac{1}{3}$ .

1) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

2) 34' title="

\frac{3}{4}

"/>

\frac{3}{4}

3) 512' title="

\frac{5}{12}

"/>

\frac{5}{12}

4) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

Answer: 4

SOLUTION 1 :

Step 1:	$\frac{5}{12}$ + $\frac{1 x 4}{3 x 4}$	= $\frac{5}{12}$ + $\frac{4}{12}$
		= $\frac{9}{12}$
		= $\frac{3}{4}$
Step 2:	$\frac{3}{4}$ - $\frac{1}{4}$	= $\frac{2}{4}$
		= $\frac{1}{2}$

Subtract $\frac{1}{4}$ from the sum of $\frac{3}{8}$ and $\frac{3}{8}$ .

1) 34' title="

\frac{3}{4}

"/>

\frac{3}{4}

2) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

3) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

4) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

Answer: 4

SOLUTION 1 :

Step 1:	$\frac{3}{8}$ + $\frac{3}{8}$	= $\frac{6}{8}$
		= $\frac{3}{4}$
Step 2:	$\frac{3}{4}$ - $\frac{1}{4}$	= $\frac{2}{4}$
		= $\frac{1}{2}$

Subtract $\frac{1}{4}$ from the sum of $\frac{1}{3}$ and $\frac{1}{12}$ .

1) 812' title="

\frac{8}{12}

"/>

\frac{8}{12}

2) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

3) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

4) 16' title="

\frac{1}{6}

"/>

\frac{1}{6}

Answer: 4

SOLUTION 1 :

Step 1:	$\frac{1 x 4}{3 x 4}$ + $\frac{1}{12}$	= $\frac{4}{12}$ + $\frac{1}{12}$
		= $\frac{5}{12}$
Step 2:	$\frac{5}{12}$ - $\frac{1 x 3}{4 x 3}$	= $\frac{5}{12}$ - $\frac{3}{12}$
		= $\frac{2}{12}$

Subtract $\frac{1}{5}$ from the sum of $\frac{1}{10}$ and $\frac{1}{2}$ .

1) 710' title="

\frac{7}{10}

"/>

\frac{7}{10}

2) 35' title="

\frac{3}{5}

"/>

\frac{3}{5}

3) 25' title="

\frac{2}{5}

"/>

\frac{2}{5}

4) 410' title="

\frac{4}{10}

"/>

\frac{4}{10}

Answer: 3

SOLUTION 1 :

Step 1:	$\frac{1}{10}$ + $\frac{1 x 5}{2 x 5}$	= $\frac{1}{10}$ + $\frac{5}{10}$
		= $\frac{6}{10}$
		= $\frac{3}{5}$
Step 2:	$\frac{3}{5}$ - $\frac{1}{5}$	= $\frac{2}{5}$

10)

Subtract $\frac{1}{3}$ from the sum of $\frac{7}{12}$ and $\frac{1}{4}$ .

1) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

2) 56' title="

\frac{5}{6}

"/>

\frac{5}{6}

3) 512' title="

\frac{5}{12}

"/>

\frac{5}{12}

4) 16' title="

\frac{1}{6}

"/>

\frac{1}{6}

Answer: 1

SOLUTION 1 :

Step 1:	$\frac{7}{12}$ + $\frac{1 x 3}{4 x 3}$	= $\frac{7}{12}$ + $\frac{3}{12}$
		= $\frac{10}{12}$
		= $\frac{5}{6}$
Step 2:	$\frac{5}{6}$ - $\frac{1 x 2}{3 x 2}$	= $\frac{5}{6}$ - $\frac{2}{6}$
		= $\frac{3}{6}$
		= $\frac{1}{2}$