Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (2164)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 60 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 220 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 240 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 140 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 90 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 180 km at an average speed of 50 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 180 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 210 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 200 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

10)

A motorist left Town A for Town B at 1.40 p.m. He travelled $\frac{1}{4}$ of his journey in 20 minutes and the remaining 120 km at an average speed of 40 $\frac{km}{h.}$ At what time will the motorist reach Town B

p.m.

Answer:_______________

Answer: 3.30 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	60 km ÷ 40 $\frac{km}{h}$
		=	1.5 h
		=	1 h 30 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 1 h 30 min
		=	3.30 p.m.

Answer: 7.30 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	220 km ÷ 40 $\frac{km}{h}$
		=	5.5 h
		=	5 h 30 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 5 h 30 min
		=	7.30 p.m.

Answer: 8.00 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	240 km ÷ 40 $\frac{km}{h}$
		=	6 h
		=	6 h 0 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 6 h 0 min
		=	8.00 p.m.

Answer: 5.30 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	140 km ÷ 40 $\frac{km}{h}$
		=	3.5 h
		=	3 h 30 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 3 h 30 min
		=	5.30 p.m.

Answer: 4.15 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	90 km ÷ 40 $\frac{km}{h}$
		=	2.25 h
		=	2 h 15 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 2 h 15 min
		=	4.15 p.m.

Answer: 5.36 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	180 km ÷ 50 $\frac{km}{h}$
		=	3.6 h
		=	3 h 36 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 3 h 36 min
		=	5.36 p.m.

Answer: 6.30 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	180 km ÷ 40 $\frac{km}{h}$
		=	4.5 h
		=	4 h 30 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 4 h 30 min
		=	6.30 p.m.

Answer: 7.15 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	210 km ÷ 40 $\frac{km}{h}$
		=	5.25 h
		=	5 h 15 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 5 h 15 min
		=	7.15 p.m.

Answer: 7.00 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	200 km ÷ 40 $\frac{km}{h}$
		=	5 h
		=	5 h 0 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 5 h 0 min
		=	7.00 p.m.

10)

Answer: 5.00 p.m.

SOLUTION 1 :

Step 1:	Time after the motorist finished the first $\frac{1}{4}$ of the journey	→	1.40 p.m. + 20 min
		=	2.00 p.m.

Step 2:	Time used to travel the last $\frac{3}{4}$ of the journey	→	120 km ÷ 40 $\frac{km}{h}$
		=	3 h
		=	3 h 0 min

Step 3:	Time when the motorist finished the journey	→	2.00 p.m. + 3 h 0 min
		=	5.00 p.m.