Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
1) The figure is made up of a big circle and 2 small circles with radii of 42 cm and 21 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 42 cm. cm cm2 Answer:_______________ |
2) The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 6 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 18 cm, CD = 6 cm cm cm2 Answer:_______________ |
3) The figure is made up of a big circle and 2 small circles with radii of 44 cm and 22 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 44 cm. cm cm2 Answer:_______________ |
4) The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 6 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 26 cm, CD = 6 cm cm cm2 Answer:_______________ |
5) The figure is made up of a big circle and 2 small circles with radii of 24 cm and 12 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 24 cm. cm cm2 Answer:_______________ |
6) The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 10 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 20 cm, CD = 10 cm cm cm2 Answer:_______________ |
7) The figure is made up of a big circle and 2 small circles with radii of 14 cm and 7 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 14 cm. cm cm2 Answer:_______________ |
8) The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 4 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 30 cm, CD = 4 cm cm cm2 Answer:_______________ |
9) The figure is made up of a big circle and 2 small circles with radii of 22 cm and 11 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 22 cm. cm cm2 Answer:_______________ |
10) The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 8 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 18 cm, CD = 8 cm cm cm2 Answer:_______________ |
1) The figure is made up of a big circle and 2 small circles with radii of 42 cm and 21 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 42 cm. Answer: 528 cm Answer: 2771 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 84 cm = 263.928 cm Step 2: Circumference of 2 small circles → 2 x π x 42 cm = 263.928 cm Step 3: Perimeter of shaded part → 263.928 cm + 263.928 cm = 527.856 cm ≈ 528 cm Step 4: Area of big circle → π x 42 cm x 42 cm = 5542.488 cm2 Step 5: Area of 2 small circles →2 x π x 21 cm x 21 cm = 2771.244 cm2 Step 6: Area of shaded part → 5542.488 cm2 - 2771.244 cm2 = 2771.244 cm2 ≈ 2771 cm2 |
2) The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 6 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 18 cm, CD = 6 cm Answer: 151 cm Answer: 170 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 24 cm = 75.408 cm Step 2: Circumference of medium circle → π x 18 cm = 56.556 cm Step 3: Circumference of small circle → π x 6 cm = 18.852 cm Step 4: Perimeter of shaded part → 75.408 cm + 56.556 cm + 18.852 cm = 150.816 cm ≈ 151 cm Step 5: Area of big circle → π x 12 cm x 12 cm = 452.448 cm2 Step 6: Area of medium circle → π x 9 cm x 9 cm = 254.502 cm2 Step 7: Area of small circle → π x 3 cm x 3 cm = 28.278 cm2 Step 8: Area of shaded part → 452.448 cm2 - 254.502 cm2 - 28.278 cm2 = 169.668 cm2 ≈ 170 cm2 |
3) The figure is made up of a big circle and 2 small circles with radii of 44 cm and 22 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 44 cm. Answer: 553 cm Answer: 3041 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 88 cm = 276.496 cm Step 2: Circumference of 2 small circles → 2 x π x 44 cm = 276.496 cm Step 3: Perimeter of shaded part → 276.496 cm + 276.496 cm = 552.992 cm ≈ 553 cm Step 4: Area of big circle → π x 44 cm x 44 cm = 6082.912 cm2 Step 5: Area of 2 small circles →2 x π x 22 cm x 22 cm = 3041.456 cm2 Step 6: Area of shaded part → 6082.912 cm2 - 3041.456 cm2 = 3041.456 cm2 ≈ 3041 cm2 |
4) The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 6 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 26 cm, CD = 6 cm Answer: 201 cm Answer: 245 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 32 cm = 100.544 cm Step 2: Circumference of medium circle → π x 26 cm = 81.692 cm Step 3: Circumference of small circle → π x 6 cm = 18.852 cm Step 4: Perimeter of shaded part → 100.544 cm + 81.692 cm + 18.852 cm = 201.088 cm ≈ 201 cm Step 5: Area of big circle → π x 16 cm x 16 cm = 804.352 cm2 Step 6: Area of medium circle → π x 13 cm x 13 cm = 530.998 cm2 Step 7: Area of small circle → π x 3 cm x 3 cm = 28.278 cm2 Step 8: Area of shaded part → 804.352 cm2 - 530.998 cm2 - 28.278 cm2 = 245.076 cm2 ≈ 245 cm2 |
5) The figure is made up of a big circle and 2 small circles with radii of 24 cm and 12 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 24 cm. Answer: 302 cm Answer: 905 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 48 cm = 150.816 cm Step 2: Circumference of 2 small circles → 2 x π x 24 cm = 150.816 cm Step 3: Perimeter of shaded part → 150.816 cm + 150.816 cm = 301.632 cm ≈ 302 cm Step 4: Area of big circle → π x 24 cm x 24 cm = 1809.792 cm2 Step 5: Area of 2 small circles →2 x π x 12 cm x 12 cm = 904.896 cm2 Step 6: Area of shaded part → 1809.792 cm2 - 904.896 cm2 = 904.896 cm2 ≈ 905 cm2 |
6) The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 10 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 20 cm, CD = 10 cm Answer: 189 cm Answer: 314 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 30 cm = 94.26 cm Step 2: Circumference of medium circle → π x 20 cm = 62.84 cm Step 3: Circumference of small circle → π x 10 cm = 31.42 cm Step 4: Perimeter of shaded part → 94.26 cm + 62.84 cm + 31.42 cm = 188.520 cm ≈ 189 cm Step 5: Area of big circle → π x 15 cm x 15 cm = 706.95 cm2 Step 6: Area of medium circle → π x 10 cm x 10 cm = 314.2 cm2 Step 7: Area of small circle → π x 5 cm x 5 cm = 78.55 cm2 Step 8: Area of shaded part → 706.95 cm2 - 314.2 cm2 - 78.55 cm2 = 314.200 cm2 ≈ 314 cm2 |
7) The figure is made up of a big circle and 2 small circles with radii of 14 cm and 7 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 14 cm. Answer: 176 cm Answer: 308 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 28 cm = 87.976 cm Step 2: Circumference of 2 small circles → 2 x π x 14 cm = 87.976 cm Step 3: Perimeter of shaded part → 87.976 cm + 87.976 cm = 175.952 cm ≈ 176 cm Step 4: Area of big circle → π x 14 cm x 14 cm = 615.832 cm2 Step 5: Area of 2 small circles →2 x π x 7 cm x 7 cm = 307.916 cm2 Step 6: Area of shaded part → 615.832 cm2 - 307.916 cm2 = 307.916 cm2 ≈ 308 cm2 |
8) The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 4 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 30 cm, CD = 4 cm Answer: 214 cm Answer: 189 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 34 cm = 106.828 cm Step 2: Circumference of medium circle → π x 30 cm = 94.26 cm Step 3: Circumference of small circle → π x 4 cm = 12.568 cm Step 4: Perimeter of shaded part → 106.828 cm + 94.26 cm + 12.568 cm = 213.656 cm ≈ 214 cm Step 5: Area of big circle → π x 17 cm x 17 cm = 908.038 cm2 Step 6: Area of medium circle → π x 15 cm x 15 cm = 706.95 cm2 Step 7: Area of small circle → π x 2 cm x 2 cm = 12.568 cm2 Step 8: Area of shaded part → 908.038 cm2 - 706.95 cm2 - 12.568 cm2 = 188.520 cm2 ≈ 189 cm2 |
9) The figure is made up of a big circle and 2 small circles with radii of 22 cm and 11 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 22 cm. Answer: 276 cm Answer: 760 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 44 cm = 138.248 cm Step 2: Circumference of 2 small circles → 2 x π x 22 cm = 138.248 cm Step 3: Perimeter of shaded part → 138.248 cm + 138.248 cm = 276.496 cm ≈ 276 cm Step 4: Area of big circle → π x 22 cm x 22 cm = 1520.728 cm2 Step 5: Area of 2 small circles →2 x π x 11 cm x 11 cm = 760.364 cm2 Step 6: Area of shaded part → 1520.728 cm2 - 760.364 cm2 = 760.364 cm2 ≈ 760 cm2 |
10) The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 8 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 18 cm, CD = 8 cm Answer: 163 cm Answer: 226 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 26 cm = 81.692 cm Step 2: Circumference of medium circle → π x 18 cm = 56.556 cm Step 3: Circumference of small circle → π x 8 cm = 25.136 cm Step 4: Perimeter of shaded part → 81.692 cm + 56.556 cm + 25.136 cm = 163.384 cm ≈ 163 cm Step 5: Area of big circle → π x 13 cm x 13 cm = 530.998 cm2 Step 6: Area of medium circle → π x 9 cm x 9 cm = 254.502 cm2 Step 7: Area of small circle → π x 4 cm x 4 cm = 50.272 cm2 Step 8: Area of shaded part → 530.998 cm2 - 254.502 cm2 - 50.272 cm2 = 226.224 cm2 ≈ 226 cm2 |