Scroll:Measurement >> Area & Circumference of Circle >> ps (1791)

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For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

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1)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 8 cm

cm

cm2



Answer:_______________




2)  

The figure is made up of a big circle and 2 small circles with radii of 22 cm and 11 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 22 cm.

cm

cm2



Answer:_______________




3)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 12 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 12 cm

cm

cm2



Answer:_______________




4)  

The figure is made up of a big circle and 2 small circles with radii of 42 cm and 21 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 42 cm.

cm

cm2



Answer:_______________




5)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 4 cm

cm

cm2



Answer:_______________




6)  

The figure is made up of a big circle and 2 small circles with radii of 46 cm and 23 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 46 cm.

cm

cm2



Answer:_______________




7)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 14 cm

cm

cm2



Answer:_______________




8)  

The figure is made up of a big circle and 2 small circles with radii of 48 cm and 24 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 48 cm.

cm

cm2



Answer:_______________




9)  

The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 20 cm, CD = 6 cm

cm

cm2



Answer:_______________




10)  

The figure is made up of a big circle and 2 small circles with radii of 30 cm and 15 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 30 cm.

cm

cm2



Answer:_______________




 

1)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 8 cm

Answer: 201 cm

Answer: 302 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 32 cm

                                                         = 100.544 cm

Step 2: Circumference of medium circle → π x 24 cm

                                                                 = 75.408 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 100.544 cm + 75.408 cm + 25.136 cm

                                                      = 201.088 cm

                                                      ≈ 201 cm

Step 5: Area of big circle → π x 16 cm  x 16 cm

                                          = 804.352 cm2

Step 6: Area of medium circle → π x 12 cm x 12 cm

                                                 = 452.448 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 804.352 cm2 - 452.448 cm2  - 50.272 cm2

                                             = 301.632 cm2 

                                             ≈ 302 cm2



2)  

The figure is made up of a big circle and 2 small circles with radii of 22 cm and 11 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 22 cm.

Answer: 276 cm

Answer: 760 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 44 cm

                                                        = 138.248 cm

Step 2: Circumference of 2 small circles → 2 x π x 22 cm

                                                                 = 138.248 cm

Step 3: Perimeter of shaded part → 138.248 cm + 138.248 cm

                                                     = 276.496 cm

                                                     ≈ 276 cm

Step 4: Area of big circle → π x 22 cm  x 22 cm

                                         = 1520.728 cm2

Step 5: Area of 2 small circles →2 x π x 11 cm x 11 cm

                                                 = 760.364 cm2

Step 6: Area of shaded part → 1520.728 cm2 - 760.364 cm2

                                             = 760.364 cm2 

                                             ≈ 760 cm2



3)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 12 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 12 cm

Answer: 251 cm

Answer: 528 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 40 cm

                                                         = 125.68 cm

Step 2: Circumference of medium circle → π x 28 cm

                                                                 = 87.976 cm

Step 3: Circumference of small circle → π x 12 cm

                                                            = 37.704 cm

Step 4: Perimeter of shaded part → 125.68 cm + 87.976 cm + 37.704 cm

                                                      = 251.360 cm

                                                      ≈ 251 cm

Step 5: Area of big circle → π x 20 cm  x 20 cm

                                          = 1256.8 cm2

Step 6: Area of medium circle → π x 14 cm x 14 cm

                                                 = 615.832 cm2

Step 7: Area of small circle → π x 6 cm x 6 cm

                                            = 113.112 cm2

Step 8: Area of shaded part → 1256.8 cm2 - 615.832 cm2  - 113.112 cm2

                                             = 527.856 cm2 

                                             ≈ 528 cm2



4)  

The figure is made up of a big circle and 2 small circles with radii of 42 cm and 21 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 42 cm.

Answer: 528 cm

Answer: 2771 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 84 cm

                                                        = 263.928 cm

Step 2: Circumference of 2 small circles → 2 x π x 42 cm

                                                                 = 263.928 cm

Step 3: Perimeter of shaded part → 263.928 cm + 263.928 cm

                                                     = 527.856 cm

                                                     ≈ 528 cm

Step 4: Area of big circle → π x 42 cm  x 42 cm

                                         = 5542.488 cm2

Step 5: Area of 2 small circles →2 x π x 21 cm x 21 cm

                                                 = 2771.244 cm2

Step 6: Area of shaded part → 5542.488 cm2 - 2771.244 cm2

                                             = 2771.244 cm2 

                                             ≈ 2771 cm2



5)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 4 cm

Answer: 163 cm

Answer: 138 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 26 cm

                                                         = 81.692 cm

Step 2: Circumference of medium circle → π x 22 cm

                                                                 = 69.124 cm

Step 3: Circumference of small circle → π x 4 cm

                                                            = 12.568 cm

Step 4: Perimeter of shaded part → 81.692 cm + 69.124 cm + 12.568 cm

                                                      = 163.384 cm

                                                      ≈ 163 cm

Step 5: Area of big circle → π x 13 cm  x 13 cm

                                          = 530.998 cm2

Step 6: Area of medium circle → π x 11 cm x 11 cm

                                                 = 380.182 cm2

Step 7: Area of small circle → π x 2 cm x 2 cm

                                            = 12.568 cm2

Step 8: Area of shaded part → 530.998 cm2 - 380.182 cm2  - 12.568 cm2

                                             = 138.248 cm2 

                                             ≈ 138 cm2



6)  

The figure is made up of a big circle and 2 small circles with radii of 46 cm and 23 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 46 cm.

Answer: 578 cm

Answer: 3324 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 92 cm

                                                        = 289.064 cm

Step 2: Circumference of 2 small circles → 2 x π x 46 cm

                                                                 = 289.064 cm

Step 3: Perimeter of shaded part → 289.064 cm + 289.064 cm

                                                     = 578.128 cm

                                                     ≈ 578 cm

Step 4: Area of big circle → π x 46 cm  x 46 cm

                                         = 6648.472 cm2

Step 5: Area of 2 small circles →2 x π x 23 cm x 23 cm

                                                 = 3324.236 cm2

Step 6: Area of shaded part → 6648.472 cm2 - 3324.236 cm2

                                             = 3324.236 cm2 

                                             ≈ 3324 cm2



7)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 14 cm

Answer: 251 cm

Answer: 572 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 40 cm

                                                         = 125.68 cm

Step 2: Circumference of medium circle → π x 26 cm

                                                                 = 81.692 cm

Step 3: Circumference of small circle → π x 14 cm

                                                            = 43.988 cm

Step 4: Perimeter of shaded part → 125.68 cm + 81.692 cm + 43.988 cm

                                                      = 251.360 cm

                                                      ≈ 251 cm

Step 5: Area of big circle → π x 20 cm  x 20 cm

                                          = 1256.8 cm2

Step 6: Area of medium circle → π x 13 cm x 13 cm

                                                 = 530.998 cm2

Step 7: Area of small circle → π x 7 cm x 7 cm

                                            = 153.958 cm2

Step 8: Area of shaded part → 1256.8 cm2 - 530.998 cm2  - 153.958 cm2

                                             = 571.844 cm2 

                                             ≈ 572 cm2



8)  

The figure is made up of a big circle and 2 small circles with radii of 48 cm and 24 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 48 cm.

Answer: 603 cm

Answer: 3620 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 96 cm

                                                        = 301.632 cm

Step 2: Circumference of 2 small circles → 2 x π x 48 cm

                                                                 = 301.632 cm

Step 3: Perimeter of shaded part → 301.632 cm + 301.632 cm

                                                     = 603.264 cm

                                                     ≈ 603 cm

Step 4: Area of big circle → π x 48 cm  x 48 cm

                                         = 7239.168 cm2

Step 5: Area of 2 small circles →2 x π x 24 cm x 24 cm

                                                 = 3619.584 cm2

Step 6: Area of shaded part → 7239.168 cm2 - 3619.584 cm2

                                             = 3619.584 cm2 

                                             ≈ 3620 cm2



9)  

The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 20 cm, CD = 6 cm

Answer: 163 cm

Answer: 189 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 26 cm

                                                         = 81.692 cm

Step 2: Circumference of medium circle → π x 20 cm

                                                                 = 62.84 cm

Step 3: Circumference of small circle → π x 6 cm

                                                            = 18.852 cm

Step 4: Perimeter of shaded part → 81.692 cm + 62.84 cm + 18.852 cm

                                                      = 163.384 cm

                                                      ≈ 163 cm

Step 5: Area of big circle → π x 13 cm  x 13 cm

                                          = 530.998 cm2

Step 6: Area of medium circle → π x 10 cm x 10 cm

                                                 = 314.2 cm2

Step 7: Area of small circle → π x 3 cm x 3 cm

                                            = 28.278 cm2

Step 8: Area of shaded part → 530.998 cm2 - 314.2 cm2  - 28.278 cm2

                                             = 188.520 cm2 

                                             ≈ 189 cm2



10)  

The figure is made up of a big circle and 2 small circles with radii of 30 cm and 15 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 30 cm.

Answer: 377 cm

Answer: 1414 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 60 cm

                                                        = 188.520 cm

Step 2: Circumference of 2 small circles → 2 x π x 30 cm

                                                                 = 188.520 cm

Step 3: Perimeter of shaded part → 188.520 cm + 188.520 cm

                                                     = 377.040 cm

                                                     ≈ 377 cm

Step 4: Area of big circle → π x 30 cm  x 30 cm

                                         = 2827.8 cm2

Step 5: Area of 2 small circles →2 x π x 15 cm x 15 cm

                                                 = 1413.9 cm2

Step 6: Area of shaded part → 2827.8 cm2 - 1413.9 cm2

                                             = 1413.900 cm2 

                                             ≈ 1414 cm2