Scroll:Measurement >> Area & Circumference of Circle >> ps (1791)

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1)  

The figure is made up of a big circle and 2 small circles with radii of 8 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 8 cm.

cm

cm2



Answer:_______________




2)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 6 cm

cm

cm2



Answer:_______________




3)  

The figure is made up of a big circle and 2 small circles with radii of 28 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 28 cm.

cm

cm2



Answer:_______________




4)  

The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 30 cm, CD = 14 cm

cm

cm2



Answer:_______________




5)  

The figure is made up of a big circle and 2 small circles with radii of 10 cm and 5 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 10 cm.

cm

cm2



Answer:_______________




6)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 8 cm

cm

cm2



Answer:_______________




7)  

The figure is made up of a big circle and 2 small circles with radii of 40 cm and 20 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 40 cm.

cm

cm2



Answer:_______________




8)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 10 cm

cm

cm2



Answer:_______________




9)  

The figure is made up of a big circle and 2 small circles with radii of 22 cm and 11 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 22 cm.

cm

cm2



Answer:_______________




10)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 8 cm

cm

cm2



Answer:_______________




 

1)  

The figure is made up of a big circle and 2 small circles with radii of 8 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 8 cm.

Answer: 101 cm

Answer: 101 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 16 cm

                                                        = 50.272 cm

Step 2: Circumference of 2 small circles → 2 x π x 8 cm

                                                                 = 50.272 cm

Step 3: Perimeter of shaded part → 50.272 cm + 50.272 cm

                                                     = 100.544 cm

                                                     ≈ 101 cm

Step 4: Area of big circle → π x 8 cm  x 8 cm

                                         = 201.088 cm2

Step 5: Area of 2 small circles →2 x π x 4 cm x 4 cm

                                                 = 100.544 cm2

Step 6: Area of shaded part → 201.088 cm2 - 100.544 cm2

                                             = 100.544 cm2 

                                             ≈ 101 cm2



2)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 6 cm

Answer: 151 cm

Answer: 170 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 24 cm

                                                         = 75.408 cm

Step 2: Circumference of medium circle → π x 18 cm

                                                                 = 56.556 cm

Step 3: Circumference of small circle → π x 6 cm

                                                            = 18.852 cm

Step 4: Perimeter of shaded part → 75.408 cm + 56.556 cm + 18.852 cm

                                                      = 150.816 cm

                                                      ≈ 151 cm

Step 5: Area of big circle → π x 12 cm  x 12 cm

                                          = 452.448 cm2

Step 6: Area of medium circle → π x 9 cm x 9 cm

                                                 = 254.502 cm2

Step 7: Area of small circle → π x 3 cm x 3 cm

                                            = 28.278 cm2

Step 8: Area of shaded part → 452.448 cm2 - 254.502 cm2  - 28.278 cm2

                                             = 169.668 cm2 

                                             ≈ 170 cm2



3)  

The figure is made up of a big circle and 2 small circles with radii of 28 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 28 cm.

Answer: 352 cm

Answer: 1232 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 56 cm

                                                        = 175.952 cm

Step 2: Circumference of 2 small circles → 2 x π x 28 cm

                                                                 = 175.952 cm

Step 3: Perimeter of shaded part → 175.952 cm + 175.952 cm

                                                     = 351.904 cm

                                                     ≈ 352 cm

Step 4: Area of big circle → π x 28 cm  x 28 cm

                                         = 2463.328 cm2

Step 5: Area of 2 small circles →2 x π x 14 cm x 14 cm

                                                 = 1231.664 cm2

Step 6: Area of shaded part → 2463.328 cm2 - 1231.664 cm2

                                             = 1231.664 cm2 

                                             ≈ 1232 cm2



4)  

The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 30 cm, CD = 14 cm

Answer: 276 cm

Answer: 660 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 44 cm

                                                         = 138.248 cm

Step 2: Circumference of medium circle → π x 30 cm

                                                                 = 94.26 cm

Step 3: Circumference of small circle → π x 14 cm

                                                            = 43.988 cm

Step 4: Perimeter of shaded part → 138.248 cm + 94.26 cm + 43.988 cm

                                                      = 276.496 cm

                                                      ≈ 276 cm

Step 5: Area of big circle → π x 22 cm  x 22 cm

                                          = 1520.728 cm2

Step 6: Area of medium circle → π x 15 cm x 15 cm

                                                 = 706.95 cm2

Step 7: Area of small circle → π x 7 cm x 7 cm

                                            = 153.958 cm2

Step 8: Area of shaded part → 1520.728 cm2 - 706.95 cm2  - 153.958 cm2

                                             = 659.820 cm2 

                                             ≈ 660 cm2



5)  

The figure is made up of a big circle and 2 small circles with radii of 10 cm and 5 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 10 cm.

Answer: 126 cm

Answer: 157 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 20 cm

                                                        = 62.840 cm

Step 2: Circumference of 2 small circles → 2 x π x 10 cm

                                                                 = 62.840 cm

Step 3: Perimeter of shaded part → 62.840 cm + 62.840 cm

                                                     = 125.680 cm

                                                     ≈ 126 cm

Step 4: Area of big circle → π x 10 cm  x 10 cm

                                         = 314.2 cm2

Step 5: Area of 2 small circles →2 x π x 5 cm x 5 cm

                                                 = 157.1 cm2

Step 6: Area of shaded part → 314.2 cm2 - 157.1 cm2

                                             = 157.100 cm2 

                                             ≈ 157 cm2



6)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 8 cm

Answer: 214 cm

Answer: 327 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 34 cm

                                                         = 106.828 cm

Step 2: Circumference of medium circle → π x 26 cm

                                                                 = 81.692 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 106.828 cm + 81.692 cm + 25.136 cm

                                                      = 213.656 cm

                                                      ≈ 214 cm

Step 5: Area of big circle → π x 17 cm  x 17 cm

                                          = 908.038 cm2

Step 6: Area of medium circle → π x 13 cm x 13 cm

                                                 = 530.998 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 908.038 cm2 - 530.998 cm2  - 50.272 cm2

                                             = 326.768 cm2 

                                             ≈ 327 cm2



7)  

The figure is made up of a big circle and 2 small circles with radii of 40 cm and 20 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 40 cm.

Answer: 503 cm

Answer: 2514 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 80 cm

                                                        = 251.360 cm

Step 2: Circumference of 2 small circles → 2 x π x 40 cm

                                                                 = 251.360 cm

Step 3: Perimeter of shaded part → 251.360 cm + 251.360 cm

                                                     = 502.720 cm

                                                     ≈ 503 cm

Step 4: Area of big circle → π x 40 cm  x 40 cm

                                         = 5027.2 cm2

Step 5: Area of 2 small circles →2 x π x 20 cm x 20 cm

                                                 = 2513.6 cm2

Step 6: Area of shaded part → 5027.2 cm2 - 2513.6 cm2

                                             = 2513.600 cm2 

                                             ≈ 2514 cm2



8)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 10 cm

Answer: 176 cm

Answer: 283 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 28 cm

                                                         = 87.976 cm

Step 2: Circumference of medium circle → π x 18 cm

                                                                 = 56.556 cm

Step 3: Circumference of small circle → π x 10 cm

                                                            = 31.42 cm

Step 4: Perimeter of shaded part → 87.976 cm + 56.556 cm + 31.42 cm

                                                      = 175.952 cm

                                                      ≈ 176 cm

Step 5: Area of big circle → π x 14 cm  x 14 cm

                                          = 615.832 cm2

Step 6: Area of medium circle → π x 9 cm x 9 cm

                                                 = 254.502 cm2

Step 7: Area of small circle → π x 5 cm x 5 cm

                                            = 78.55 cm2

Step 8: Area of shaded part → 615.832 cm2 - 254.502 cm2  - 78.55 cm2

                                             = 282.780 cm2 

                                             ≈ 283 cm2



9)  

The figure is made up of a big circle and 2 small circles with radii of 22 cm and 11 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 22 cm.

Answer: 276 cm

Answer: 760 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 44 cm

                                                        = 138.248 cm

Step 2: Circumference of 2 small circles → 2 x π x 22 cm

                                                                 = 138.248 cm

Step 3: Perimeter of shaded part → 138.248 cm + 138.248 cm

                                                     = 276.496 cm

                                                     ≈ 276 cm

Step 4: Area of big circle → π x 22 cm  x 22 cm

                                         = 1520.728 cm2

Step 5: Area of 2 small circles →2 x π x 11 cm x 11 cm

                                                 = 760.364 cm2

Step 6: Area of shaded part → 1520.728 cm2 - 760.364 cm2

                                             = 760.364 cm2 

                                             ≈ 760 cm2



10)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 8 cm

Answer: 163 cm

Answer: 226 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 26 cm

                                                         = 81.692 cm

Step 2: Circumference of medium circle → π x 18 cm

                                                                 = 56.556 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 81.692 cm + 56.556 cm + 25.136 cm

                                                      = 163.384 cm

                                                      ≈ 163 cm

Step 5: Area of big circle → π x 13 cm  x 13 cm

                                          = 530.998 cm2

Step 6: Area of medium circle → π x 9 cm x 9 cm

                                                 = 254.502 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 530.998 cm2 - 254.502 cm2  - 50.272 cm2

                                             = 226.224 cm2 

                                             ≈ 226 cm2