Scroll:Measurement >> Area & Circumference of Circle >> ps (1791)

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1)  

The figure is made up of a big circle and 2 small circles with radii of 30 cm and 15 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 30 cm.

cm

cm2



Answer:_______________




2)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 8 cm

cm

cm2



Answer:_______________




3)  

The figure is made up of a big circle and 2 small circles with radii of 28 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 28 cm.

cm

cm2



Answer:_______________




4)  

The figure is made up of a big circle and 2 small circles with diameter of 16 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 16 cm, CD = 10 cm

cm

cm2



Answer:_______________




5)  

The figure is made up of a big circle and 2 small circles with radii of 14 cm and 7 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 14 cm.

cm

cm2



Answer:_______________




6)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 10 cm

cm

cm2



Answer:_______________




7)  

The figure is made up of a big circle and 2 small circles with radii of 10 cm and 5 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 10 cm.

cm

cm2



Answer:_______________




8)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 6 cm

cm

cm2



Answer:_______________




9)  

The figure is made up of a big circle and 2 small circles with radii of 42 cm and 21 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 42 cm.

cm

cm2



Answer:_______________




10)  

The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 20 cm, CD = 10 cm

cm

cm2



Answer:_______________




 

1)  

The figure is made up of a big circle and 2 small circles with radii of 30 cm and 15 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 30 cm.

Answer: 377 cm

Answer: 1414 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 60 cm

                                                        = 188.520 cm

Step 2: Circumference of 2 small circles → 2 x π x 30 cm

                                                                 = 188.520 cm

Step 3: Perimeter of shaded part → 188.520 cm + 188.520 cm

                                                     = 377.040 cm

                                                     ≈ 377 cm

Step 4: Area of big circle → π x 30 cm  x 30 cm

                                         = 2827.8 cm2

Step 5: Area of 2 small circles →2 x π x 15 cm x 15 cm

                                                 = 1413.9 cm2

Step 6: Area of shaded part → 2827.8 cm2 - 1413.9 cm2

                                             = 1413.900 cm2 

                                             ≈ 1414 cm2



2)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 8 cm

Answer: 214 cm

Answer: 327 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 34 cm

                                                         = 106.828 cm

Step 2: Circumference of medium circle → π x 26 cm

                                                                 = 81.692 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 106.828 cm + 81.692 cm + 25.136 cm

                                                      = 213.656 cm

                                                      ≈ 214 cm

Step 5: Area of big circle → π x 17 cm  x 17 cm

                                          = 908.038 cm2

Step 6: Area of medium circle → π x 13 cm x 13 cm

                                                 = 530.998 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 908.038 cm2 - 530.998 cm2  - 50.272 cm2

                                             = 326.768 cm2 

                                             ≈ 327 cm2



3)  

The figure is made up of a big circle and 2 small circles with radii of 28 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 28 cm.

Answer: 352 cm

Answer: 1232 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 56 cm

                                                        = 175.952 cm

Step 2: Circumference of 2 small circles → 2 x π x 28 cm

                                                                 = 175.952 cm

Step 3: Perimeter of shaded part → 175.952 cm + 175.952 cm

                                                     = 351.904 cm

                                                     ≈ 352 cm

Step 4: Area of big circle → π x 28 cm  x 28 cm

                                         = 2463.328 cm2

Step 5: Area of 2 small circles →2 x π x 14 cm x 14 cm

                                                 = 1231.664 cm2

Step 6: Area of shaded part → 2463.328 cm2 - 1231.664 cm2

                                             = 1231.664 cm2 

                                             ≈ 1232 cm2



4)  

The figure is made up of a big circle and 2 small circles with diameter of 16 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 16 cm, CD = 10 cm

Answer: 163 cm

Answer: 251 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 26 cm

                                                         = 81.692 cm

Step 2: Circumference of medium circle → π x 16 cm

                                                                 = 50.272 cm

Step 3: Circumference of small circle → π x 10 cm

                                                            = 31.42 cm

Step 4: Perimeter of shaded part → 81.692 cm + 50.272 cm + 31.42 cm

                                                      = 163.384 cm

                                                      ≈ 163 cm

Step 5: Area of big circle → π x 13 cm  x 13 cm

                                          = 530.998 cm2

Step 6: Area of medium circle → π x 8 cm x 8 cm

                                                 = 201.088 cm2

Step 7: Area of small circle → π x 5 cm x 5 cm

                                            = 78.55 cm2

Step 8: Area of shaded part → 530.998 cm2 - 201.088 cm2  - 78.55 cm2

                                             = 251.360 cm2 

                                             ≈ 251 cm2



5)  

The figure is made up of a big circle and 2 small circles with radii of 14 cm and 7 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 14 cm.

Answer: 176 cm

Answer: 308 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 28 cm

                                                        = 87.976 cm

Step 2: Circumference of 2 small circles → 2 x π x 14 cm

                                                                 = 87.976 cm

Step 3: Perimeter of shaded part → 87.976 cm + 87.976 cm

                                                     = 175.952 cm

                                                     ≈ 176 cm

Step 4: Area of big circle → π x 14 cm  x 14 cm

                                         = 615.832 cm2

Step 5: Area of 2 small circles →2 x π x 7 cm x 7 cm

                                                 = 307.916 cm2

Step 6: Area of shaded part → 615.832 cm2 - 307.916 cm2

                                             = 307.916 cm2 

                                             ≈ 308 cm2



6)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 10 cm

Answer: 214 cm

Answer: 377 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 34 cm

                                                         = 106.828 cm

Step 2: Circumference of medium circle → π x 24 cm

                                                                 = 75.408 cm

Step 3: Circumference of small circle → π x 10 cm

                                                            = 31.42 cm

Step 4: Perimeter of shaded part → 106.828 cm + 75.408 cm + 31.42 cm

                                                      = 213.656 cm

                                                      ≈ 214 cm

Step 5: Area of big circle → π x 17 cm  x 17 cm

                                          = 908.038 cm2

Step 6: Area of medium circle → π x 12 cm x 12 cm

                                                 = 452.448 cm2

Step 7: Area of small circle → π x 5 cm x 5 cm

                                            = 78.55 cm2

Step 8: Area of shaded part → 908.038 cm2 - 452.448 cm2  - 78.55 cm2

                                             = 377.040 cm2 

                                             ≈ 377 cm2



7)  

The figure is made up of a big circle and 2 small circles with radii of 10 cm and 5 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 10 cm.

Answer: 126 cm

Answer: 157 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 20 cm

                                                        = 62.840 cm

Step 2: Circumference of 2 small circles → 2 x π x 10 cm

                                                                 = 62.840 cm

Step 3: Perimeter of shaded part → 62.840 cm + 62.840 cm

                                                     = 125.680 cm

                                                     ≈ 126 cm

Step 4: Area of big circle → π x 10 cm  x 10 cm

                                         = 314.2 cm2

Step 5: Area of 2 small circles →2 x π x 5 cm x 5 cm

                                                 = 157.1 cm2

Step 6: Area of shaded part → 314.2 cm2 - 157.1 cm2

                                             = 157.100 cm2 

                                             ≈ 157 cm2



8)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 6 cm

Answer: 176 cm

Answer: 207 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 28 cm

                                                         = 87.976 cm

Step 2: Circumference of medium circle → π x 22 cm

                                                                 = 69.124 cm

Step 3: Circumference of small circle → π x 6 cm

                                                            = 18.852 cm

Step 4: Perimeter of shaded part → 87.976 cm + 69.124 cm + 18.852 cm

                                                      = 175.952 cm

                                                      ≈ 176 cm

Step 5: Area of big circle → π x 14 cm  x 14 cm

                                          = 615.832 cm2

Step 6: Area of medium circle → π x 11 cm x 11 cm

                                                 = 380.182 cm2

Step 7: Area of small circle → π x 3 cm x 3 cm

                                            = 28.278 cm2

Step 8: Area of shaded part → 615.832 cm2 - 380.182 cm2  - 28.278 cm2

                                             = 207.372 cm2 

                                             ≈ 207 cm2



9)  

The figure is made up of a big circle and 2 small circles with radii of 42 cm and 21 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 42 cm.

Answer: 528 cm

Answer: 2771 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 84 cm

                                                        = 263.928 cm

Step 2: Circumference of 2 small circles → 2 x π x 42 cm

                                                                 = 263.928 cm

Step 3: Perimeter of shaded part → 263.928 cm + 263.928 cm

                                                     = 527.856 cm

                                                     ≈ 528 cm

Step 4: Area of big circle → π x 42 cm  x 42 cm

                                         = 5542.488 cm2

Step 5: Area of 2 small circles →2 x π x 21 cm x 21 cm

                                                 = 2771.244 cm2

Step 6: Area of shaded part → 5542.488 cm2 - 2771.244 cm2

                                             = 2771.244 cm2 

                                             ≈ 2771 cm2



10)  

The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 20 cm, CD = 10 cm

Answer: 189 cm

Answer: 314 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 30 cm

                                                         = 94.26 cm

Step 2: Circumference of medium circle → π x 20 cm

                                                                 = 62.84 cm

Step 3: Circumference of small circle → π x 10 cm

                                                            = 31.42 cm

Step 4: Perimeter of shaded part → 94.26 cm + 62.84 cm + 31.42 cm

                                                      = 188.520 cm

                                                      ≈ 189 cm

Step 5: Area of big circle → π x 15 cm  x 15 cm

                                          = 706.95 cm2

Step 6: Area of medium circle → π x 10 cm x 10 cm

                                                 = 314.2 cm2

Step 7: Area of small circle → π x 5 cm x 5 cm

                                            = 78.55 cm2

Step 8: Area of shaded part → 706.95 cm2 - 314.2 cm2  - 78.55 cm2

                                             = 314.200 cm2 

                                             ≈ 314 cm2