Scroll:Measurement >> Area & Circumference of Circle >> ps (1791)

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For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

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1)  

The figure is made up of a big circle and 2 small circles with radii of 32 cm and 16 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 32 cm.

cm

cm2



Answer:_______________




2)  

The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 30 cm, CD = 6 cm

cm

cm2



Answer:_______________




3)  

The figure is made up of a big circle and 2 small circles with radii of 50 cm and 25 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 50 cm.

cm

cm2



Answer:_______________




4)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 10 cm

cm

cm2



Answer:_______________




5)  

The figure is made up of a big circle and 2 small circles with radii of 20 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 20 cm.

cm

cm2



Answer:_______________




6)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 6 cm

cm

cm2



Answer:_______________




7)  

The figure is made up of a big circle and 2 small circles with radii of 58 cm and 29 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 58 cm.

cm

cm2



Answer:_______________




8)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 4 cm

cm

cm2



Answer:_______________




9)  

The figure is made up of a big circle and 2 small circles with radii of 44 cm and 22 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 44 cm.

cm

cm2



Answer:_______________




10)  

The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 20 cm, CD = 14 cm

cm

cm2



Answer:_______________




 

1)  

The figure is made up of a big circle and 2 small circles with radii of 32 cm and 16 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 32 cm.

Answer: 402 cm

Answer: 1609 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 64 cm

                                                        = 201.088 cm

Step 2: Circumference of 2 small circles → 2 x π x 32 cm

                                                                 = 201.088 cm

Step 3: Perimeter of shaded part → 201.088 cm + 201.088 cm

                                                     = 402.176 cm

                                                     ≈ 402 cm

Step 4: Area of big circle → π x 32 cm  x 32 cm

                                         = 3217.408 cm2

Step 5: Area of 2 small circles →2 x π x 16 cm x 16 cm

                                                 = 1608.704 cm2

Step 6: Area of shaded part → 3217.408 cm2 - 1608.704 cm2

                                             = 1608.704 cm2 

                                             ≈ 1609 cm2



2)  

The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 30 cm, CD = 6 cm

Answer: 226 cm

Answer: 283 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 36 cm

                                                         = 113.112 cm

Step 2: Circumference of medium circle → π x 30 cm

                                                                 = 94.26 cm

Step 3: Circumference of small circle → π x 6 cm

                                                            = 18.852 cm

Step 4: Perimeter of shaded part → 113.112 cm + 94.26 cm + 18.852 cm

                                                      = 226.224 cm

                                                      ≈ 226 cm

Step 5: Area of big circle → π x 18 cm  x 18 cm

                                          = 1018.008 cm2

Step 6: Area of medium circle → π x 15 cm x 15 cm

                                                 = 706.95 cm2

Step 7: Area of small circle → π x 3 cm x 3 cm

                                            = 28.278 cm2

Step 8: Area of shaded part → 1018.008 cm2 - 706.95 cm2  - 28.278 cm2

                                             = 282.780 cm2 

                                             ≈ 283 cm2



3)  

The figure is made up of a big circle and 2 small circles with radii of 50 cm and 25 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 50 cm.

Answer: 628 cm

Answer: 3928 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 100 cm

                                                        = 314.200 cm

Step 2: Circumference of 2 small circles → 2 x π x 50 cm

                                                                 = 314.200 cm

Step 3: Perimeter of shaded part → 314.200 cm + 314.200 cm

                                                     = 628.400 cm

                                                     ≈ 628 cm

Step 4: Area of big circle → π x 50 cm  x 50 cm

                                         = 7855 cm2

Step 5: Area of 2 small circles →2 x π x 25 cm x 25 cm

                                                 = 3927.5 cm2

Step 6: Area of shaded part → 7855 cm2 - 3927.5 cm2

                                             = 3927.500 cm2 

                                             ≈ 3928 cm2



4)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 10 cm

Answer: 201 cm

Answer: 346 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 32 cm

                                                         = 100.544 cm

Step 2: Circumference of medium circle → π x 22 cm

                                                                 = 69.124 cm

Step 3: Circumference of small circle → π x 10 cm

                                                            = 31.42 cm

Step 4: Perimeter of shaded part → 100.544 cm + 69.124 cm + 31.42 cm

                                                      = 201.088 cm

                                                      ≈ 201 cm

Step 5: Area of big circle → π x 16 cm  x 16 cm

                                          = 804.352 cm2

Step 6: Area of medium circle → π x 11 cm x 11 cm

                                                 = 380.182 cm2

Step 7: Area of small circle → π x 5 cm x 5 cm

                                            = 78.55 cm2

Step 8: Area of shaded part → 804.352 cm2 - 380.182 cm2  - 78.55 cm2

                                             = 345.620 cm2 

                                             ≈ 346 cm2



5)  

The figure is made up of a big circle and 2 small circles with radii of 20 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 20 cm.

Answer: 251 cm

Answer: 628 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 40 cm

                                                        = 125.680 cm

Step 2: Circumference of 2 small circles → 2 x π x 20 cm

                                                                 = 125.680 cm

Step 3: Perimeter of shaded part → 125.680 cm + 125.680 cm

                                                     = 251.360 cm

                                                     ≈ 251 cm

Step 4: Area of big circle → π x 20 cm  x 20 cm

                                         = 1256.8 cm2

Step 5: Area of 2 small circles →2 x π x 10 cm x 10 cm

                                                 = 628.4 cm2

Step 6: Area of shaded part → 1256.8 cm2 - 628.4 cm2

                                             = 628.400 cm2 

                                             ≈ 628 cm2



6)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 6 cm

Answer: 214 cm

Answer: 264 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 34 cm

                                                         = 106.828 cm

Step 2: Circumference of medium circle → π x 28 cm

                                                                 = 87.976 cm

Step 3: Circumference of small circle → π x 6 cm

                                                            = 18.852 cm

Step 4: Perimeter of shaded part → 106.828 cm + 87.976 cm + 18.852 cm

                                                      = 213.656 cm

                                                      ≈ 214 cm

Step 5: Area of big circle → π x 17 cm  x 17 cm

                                          = 908.038 cm2

Step 6: Area of medium circle → π x 14 cm x 14 cm

                                                 = 615.832 cm2

Step 7: Area of small circle → π x 3 cm x 3 cm

                                            = 28.278 cm2

Step 8: Area of shaded part → 908.038 cm2 - 615.832 cm2  - 28.278 cm2

                                             = 263.928 cm2 

                                             ≈ 264 cm2



7)  

The figure is made up of a big circle and 2 small circles with radii of 58 cm and 29 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 58 cm.

Answer: 729 cm

Answer: 5285 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 116 cm

                                                        = 364.472 cm

Step 2: Circumference of 2 small circles → 2 x π x 58 cm

                                                                 = 364.472 cm

Step 3: Perimeter of shaded part → 364.472 cm + 364.472 cm

                                                     = 728.944 cm

                                                     ≈ 729 cm

Step 4: Area of big circle → π x 58 cm  x 58 cm

                                         = 10569.688 cm2

Step 5: Area of 2 small circles →2 x π x 29 cm x 29 cm

                                                 = 5284.844 cm2

Step 6: Area of shaded part → 10569.688 cm2 - 5284.844 cm2

                                             = 5284.844 cm2 

                                             ≈ 5285 cm2



8)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 4 cm

Answer: 189 cm

Answer: 163 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 30 cm

                                                         = 94.26 cm

Step 2: Circumference of medium circle → π x 26 cm

                                                                 = 81.692 cm

Step 3: Circumference of small circle → π x 4 cm

                                                            = 12.568 cm

Step 4: Perimeter of shaded part → 94.26 cm + 81.692 cm + 12.568 cm

                                                      = 188.520 cm

                                                      ≈ 189 cm

Step 5: Area of big circle → π x 15 cm  x 15 cm

                                          = 706.95 cm2

Step 6: Area of medium circle → π x 13 cm x 13 cm

                                                 = 530.998 cm2

Step 7: Area of small circle → π x 2 cm x 2 cm

                                            = 12.568 cm2

Step 8: Area of shaded part → 706.95 cm2 - 530.998 cm2  - 12.568 cm2

                                             = 163.384 cm2 

                                             ≈ 163 cm2



9)  

The figure is made up of a big circle and 2 small circles with radii of 44 cm and 22 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 44 cm.

Answer: 553 cm

Answer: 3041 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 88 cm

                                                        = 276.496 cm

Step 2: Circumference of 2 small circles → 2 x π x 44 cm

                                                                 = 276.496 cm

Step 3: Perimeter of shaded part → 276.496 cm + 276.496 cm

                                                     = 552.992 cm

                                                     ≈ 553 cm

Step 4: Area of big circle → π x 44 cm  x 44 cm

                                         = 6082.912 cm2

Step 5: Area of 2 small circles →2 x π x 22 cm x 22 cm

                                                 = 3041.456 cm2

Step 6: Area of shaded part → 6082.912 cm2 - 3041.456 cm2

                                             = 3041.456 cm2 

                                             ≈ 3041 cm2



10)  

The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 20 cm, CD = 14 cm

Answer: 214 cm

Answer: 440 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 34 cm

                                                         = 106.828 cm

Step 2: Circumference of medium circle → π x 20 cm

                                                                 = 62.84 cm

Step 3: Circumference of small circle → π x 14 cm

                                                            = 43.988 cm

Step 4: Perimeter of shaded part → 106.828 cm + 62.84 cm + 43.988 cm

                                                      = 213.656 cm

                                                      ≈ 214 cm

Step 5: Area of big circle → π x 17 cm  x 17 cm

                                          = 908.038 cm2

Step 6: Area of medium circle → π x 10 cm x 10 cm

                                                 = 314.2 cm2

Step 7: Area of small circle → π x 7 cm x 7 cm

                                            = 153.958 cm2

Step 8: Area of shaded part → 908.038 cm2 - 314.2 cm2  - 153.958 cm2

                                             = 439.880 cm2 

                                             ≈ 440 cm2