Scroll:Measurement >> Area & Circumference of Circle >> ps (1791)

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1)  

The figure is made up of a big circle and 2 small circles with radii of 50 cm and 25 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 50 cm.

cm

cm2



Answer:_______________




2)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 14 cm

cm

cm2



Answer:_______________




3)  

The figure is made up of a big circle and 2 small circles with radii of 10 cm and 5 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 10 cm.

cm

cm2



Answer:_______________




4)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 4 cm

cm

cm2



Answer:_______________




5)  

The figure is made up of a big circle and 2 small circles with radii of 38 cm and 19 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 38 cm.

cm

cm2



Answer:_______________




6)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 4 cm

cm

cm2



Answer:_______________




7)  

The figure is made up of a big circle and 2 small circles with radii of 40 cm and 20 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 40 cm.

cm

cm2



Answer:_______________




8)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 8 cm

cm

cm2



Answer:_______________




9)  

The figure is made up of a big circle and 2 small circles with radii of 60 cm and 30 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 60 cm.

cm

cm2



Answer:_______________




10)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 8 cm

cm

cm2



Answer:_______________




 

1)  

The figure is made up of a big circle and 2 small circles with radii of 50 cm and 25 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 50 cm.

Answer: 628 cm

Answer: 3928 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 100 cm

                                                        = 314.200 cm

Step 2: Circumference of 2 small circles → 2 x π x 50 cm

                                                                 = 314.200 cm

Step 3: Perimeter of shaded part → 314.200 cm + 314.200 cm

                                                     = 628.400 cm

                                                     ≈ 628 cm

Step 4: Area of big circle → π x 50 cm  x 50 cm

                                         = 7855 cm2

Step 5: Area of 2 small circles →2 x π x 25 cm x 25 cm

                                                 = 3927.5 cm2

Step 6: Area of shaded part → 7855 cm2 - 3927.5 cm2

                                             = 3927.500 cm2 

                                             ≈ 3928 cm2



2)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 14 cm

Answer: 264 cm

Answer: 616 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 42 cm

                                                         = 131.964 cm

Step 2: Circumference of medium circle → π x 28 cm

                                                                 = 87.976 cm

Step 3: Circumference of small circle → π x 14 cm

                                                            = 43.988 cm

Step 4: Perimeter of shaded part → 131.964 cm + 87.976 cm + 43.988 cm

                                                      = 263.928 cm

                                                      ≈ 264 cm

Step 5: Area of big circle → π x 21 cm  x 21 cm

                                          = 1385.622 cm2

Step 6: Area of medium circle → π x 14 cm x 14 cm

                                                 = 615.832 cm2

Step 7: Area of small circle → π x 7 cm x 7 cm

                                            = 153.958 cm2

Step 8: Area of shaded part → 1385.622 cm2 - 615.832 cm2  - 153.958 cm2

                                             = 615.832 cm2 

                                             ≈ 616 cm2



3)  

The figure is made up of a big circle and 2 small circles with radii of 10 cm and 5 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 10 cm.

Answer: 126 cm

Answer: 157 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 20 cm

                                                        = 62.840 cm

Step 2: Circumference of 2 small circles → 2 x π x 10 cm

                                                                 = 62.840 cm

Step 3: Perimeter of shaded part → 62.840 cm + 62.840 cm

                                                     = 125.680 cm

                                                     ≈ 126 cm

Step 4: Area of big circle → π x 10 cm  x 10 cm

                                         = 314.2 cm2

Step 5: Area of 2 small circles →2 x π x 5 cm x 5 cm

                                                 = 157.1 cm2

Step 6: Area of shaded part → 314.2 cm2 - 157.1 cm2

                                             = 157.100 cm2 

                                             ≈ 157 cm2



4)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 4 cm

Answer: 138 cm

Answer: 113 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 22 cm

                                                         = 69.124 cm

Step 2: Circumference of medium circle → π x 18 cm

                                                                 = 56.556 cm

Step 3: Circumference of small circle → π x 4 cm

                                                            = 12.568 cm

Step 4: Perimeter of shaded part → 69.124 cm + 56.556 cm + 12.568 cm

                                                      = 138.248 cm

                                                      ≈ 138 cm

Step 5: Area of big circle → π x 11 cm  x 11 cm

                                          = 380.182 cm2

Step 6: Area of medium circle → π x 9 cm x 9 cm

                                                 = 254.502 cm2

Step 7: Area of small circle → π x 2 cm x 2 cm

                                            = 12.568 cm2

Step 8: Area of shaded part → 380.182 cm2 - 254.502 cm2  - 12.568 cm2

                                             = 113.112 cm2 

                                             ≈ 113 cm2



5)  

The figure is made up of a big circle and 2 small circles with radii of 38 cm and 19 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 38 cm.

Answer: 478 cm

Answer: 2269 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 76 cm

                                                        = 238.792 cm

Step 2: Circumference of 2 small circles → 2 x π x 38 cm

                                                                 = 238.792 cm

Step 3: Perimeter of shaded part → 238.792 cm + 238.792 cm

                                                     = 477.584 cm

                                                     ≈ 478 cm

Step 4: Area of big circle → π x 38 cm  x 38 cm

                                         = 4537.048 cm2

Step 5: Area of 2 small circles →2 x π x 19 cm x 19 cm

                                                 = 2268.524 cm2

Step 6: Area of shaded part → 4537.048 cm2 - 2268.524 cm2

                                             = 2268.524 cm2 

                                             ≈ 2269 cm2



6)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 4 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 4 cm

Answer: 176 cm

Answer: 151 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 28 cm

                                                         = 87.976 cm

Step 2: Circumference of medium circle → π x 24 cm

                                                                 = 75.408 cm

Step 3: Circumference of small circle → π x 4 cm

                                                            = 12.568 cm

Step 4: Perimeter of shaded part → 87.976 cm + 75.408 cm + 12.568 cm

                                                      = 175.952 cm

                                                      ≈ 176 cm

Step 5: Area of big circle → π x 14 cm  x 14 cm

                                          = 615.832 cm2

Step 6: Area of medium circle → π x 12 cm x 12 cm

                                                 = 452.448 cm2

Step 7: Area of small circle → π x 2 cm x 2 cm

                                            = 12.568 cm2

Step 8: Area of shaded part → 615.832 cm2 - 452.448 cm2  - 12.568 cm2

                                             = 150.816 cm2 

                                             ≈ 151 cm2



7)  

The figure is made up of a big circle and 2 small circles with radii of 40 cm and 20 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 40 cm.

Answer: 503 cm

Answer: 2514 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 80 cm

                                                        = 251.360 cm

Step 2: Circumference of 2 small circles → 2 x π x 40 cm

                                                                 = 251.360 cm

Step 3: Perimeter of shaded part → 251.360 cm + 251.360 cm

                                                     = 502.720 cm

                                                     ≈ 503 cm

Step 4: Area of big circle → π x 40 cm  x 40 cm

                                         = 5027.2 cm2

Step 5: Area of 2 small circles →2 x π x 20 cm x 20 cm

                                                 = 2513.6 cm2

Step 6: Area of shaded part → 5027.2 cm2 - 2513.6 cm2

                                             = 2513.600 cm2 

                                             ≈ 2514 cm2



8)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 8 cm

Answer: 189 cm

Answer: 276 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 30 cm

                                                         = 94.26 cm

Step 2: Circumference of medium circle → π x 22 cm

                                                                 = 69.124 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 94.26 cm + 69.124 cm + 25.136 cm

                                                      = 188.520 cm

                                                      ≈ 189 cm

Step 5: Area of big circle → π x 15 cm  x 15 cm

                                          = 706.95 cm2

Step 6: Area of medium circle → π x 11 cm x 11 cm

                                                 = 380.182 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 706.95 cm2 - 380.182 cm2  - 50.272 cm2

                                             = 276.496 cm2 

                                             ≈ 276 cm2



9)  

The figure is made up of a big circle and 2 small circles with radii of 60 cm and 30 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 60 cm.

Answer: 754 cm

Answer: 5656 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 120 cm

                                                        = 377.040 cm

Step 2: Circumference of 2 small circles → 2 x π x 60 cm

                                                                 = 377.040 cm

Step 3: Perimeter of shaded part → 377.040 cm + 377.040 cm

                                                     = 754.080 cm

                                                     ≈ 754 cm

Step 4: Area of big circle → π x 60 cm  x 60 cm

                                         = 11311.2 cm2

Step 5: Area of 2 small circles →2 x π x 30 cm x 30 cm

                                                 = 5655.6 cm2

Step 6: Area of shaded part → 11311.2 cm2 - 5655.6 cm2

                                             = 5655.600 cm2 

                                             ≈ 5656 cm2



10)  

The figure is made up of a big circle and 2 small circles with diameter of 26 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 26 cm, CD = 8 cm

Answer: 214 cm

Answer: 327 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 34 cm

                                                         = 106.828 cm

Step 2: Circumference of medium circle → π x 26 cm

                                                                 = 81.692 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 106.828 cm + 81.692 cm + 25.136 cm

                                                      = 213.656 cm

                                                      ≈ 214 cm

Step 5: Area of big circle → π x 17 cm  x 17 cm

                                          = 908.038 cm2

Step 6: Area of medium circle → π x 13 cm x 13 cm

                                                 = 530.998 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 908.038 cm2 - 530.998 cm2  - 50.272 cm2

                                             = 326.768 cm2 

                                             ≈ 327 cm2