Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (1770)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Town A and Town B were 684 km apart. At 1045 h Poongodi drove from Town A to Town B. At the same time, Prem drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Poongodi and Prem passed each other at 1530 h. If Poongodi was travelling 10 $\frac{km}{h}$ slower than Prem, find Prem's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 710 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 28 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 760 km apart. At 1045 h Amutha drove from Town A to Town B. At the same time, Moorthi drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Amutha and Moorthi passed each other at 1530 h. If Amutha was travelling 30 $\frac{km}{h}$ slower than Moorthi, find Moorthi's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 730 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 22 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 646 km apart. At 1045 h Mithra drove from Town A to Town B. At the same time, Pugal drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Mithra and Pugal passed each other at 1530 h. If Mithra was travelling 24 $\frac{km}{h}$ slower than Pugal, find Pugal's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 700 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 26 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 684 km apart. At 1045 h Chellamal drove from Town A to Town B. At the same time, Sriram drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Chellamal and Sriram passed each other at 1530 h. If Chellamal was travelling 10 $\frac{km}{h}$ slower than Sriram, find Sriram's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 670 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 20 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 950 km apart. At 1045 h Nandini drove from Town A to Town B. At the same time, Barathan drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Nandini and Barathan passed each other at 1530 h. If Nandini was travelling 12 $\frac{km}{h}$ slower than Barathan, find Barathan's speed.

$\frac{km}{h}$

Answer:_______________

10)

Town Lala and Town Yaya are 730 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 24 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Answer: 77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	10 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 10 km
		=	47.5 km

Poongodi travelled 47.5 km less than Prem.

Poongodi

Prem

47.5km

Total = 684 km

Step 3: 684 km - 47.5 km = 636.5 km

Step 4:	Distance travelled by Poongodi	→	636.5 km ÷ 2
		=	318.25 km

Step 5:	Poongodi's speed	→	318.25 km ÷ 4 $\frac{3}{4}$ h
		=	67 $\frac{km}{h}$

Step 6:	Prem's speed	→	67 $\frac{km}{h}$ + 10 $\frac{km}{h}$
		=	77 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	10 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 10 km
		=	47.5 km

Poongodi travelled 47.5 km less than Prem.

Poongodi

Prem

47.5km

Total = 684 km

Step 3: 684 km - 47.5 km = 636.5 km

Step 4:	Distance travelled by Poongodi	→	636.5 km ÷ 2
		=	318.25 km

Step 5:	Distance travelled by Prem	→	318.25 km + 47.5 km
		=	365.75 km

Step 6:	Prem's speed	→	365.75 km ÷ 4 $\frac{3}{4}$ h
		=	77 $\frac{km}{h}$

Answer: 85 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 710 km

Step 3: 710 km - 140 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Distance travelled by the car	→	285 km + 140 km
		=	425 km

Step 6:	Car's speed	→	425 km ÷ 5h
		=	85 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 710 km

Step 3: 710 km - 140 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Lorry's speed	→	285 km ÷ 5h
		=	57 $\frac{km}{h}$

Step 6:	Car's speed	→	57 $\frac{km}{h}$ + 28 $\frac{km}{h}$
		=	85 $\frac{km}{h}$

Answer: 95 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	30 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 30 km
		=	142.5 km

Amutha travelled 142.5 km less than Moorthi.

Amutha

Moorthi

142.5km

Total = 760 km

Step 3: 760 km - 142.5 km = 617.5 km

Step 4:	Distance travelled by Amutha	→	617.5 km ÷ 2
		=	308.75 km

Step 5:	Amutha's speed	→	308.75 km ÷ 4 $\frac{3}{4}$ h
		=	65 $\frac{km}{h}$

Step 6:	Moorthi's speed	→	65 $\frac{km}{h}$ + 30 $\frac{km}{h}$
		=	95 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	30 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 30 km
		=	142.5 km

Amutha travelled 142.5 km less than Moorthi.

Amutha

Moorthi

142.5km

Total = 760 km

Step 3: 760 km - 142.5 km = 617.5 km

Step 4:	Distance travelled by Amutha	→	617.5 km ÷ 2
		=	308.75 km

Step 5:	Distance travelled by Moorthi	→	308.75 km + 142.5 km
		=	451.25 km

Step 6:	Moorthi's speed	→	451.25 km ÷ 4 $\frac{3}{4}$ h
		=	95 $\frac{km}{h}$

Answer: 84 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	22 km
	5h	→	5 x 22 km
		=	110 km

The lorry travelled 110 km less than the car.

Lorry

Car

110km

Total = 730 km

Step 3: 730 km - 110 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Distance travelled by the car	→	310 km + 110 km
		=	420 km

Step 6:	Car's speed	→	420 km ÷ 5h
		=	84 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	22 km
	5h	→	5 x 22 km
		=	110 km

The lorry travelled 110 km less than the car.

Lorry

Car

110km

Total = 730 km

Step 3: 730 km - 110 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Lorry's speed	→	310 km ÷ 5h
		=	62 $\frac{km}{h}$

Step 6:	Car's speed	→	62 $\frac{km}{h}$ + 22 $\frac{km}{h}$
		=	84 $\frac{km}{h}$

Answer: 80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	24 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 24 km
		=	114 km

Mithra travelled 114 km less than Pugal.

Mithra

Pugal

114km

Total = 646 km

Step 3: 646 km - 114 km = 532 km

Step 4:	Distance travelled by Mithra	→	532 km ÷ 2
		=	266 km

Step 5:	Mithra's speed	→	266 km ÷ 4 $\frac{3}{4}$ h
		=	56 $\frac{km}{h}$

Step 6:	Pugal's speed	→	56 $\frac{km}{h}$ + 24 $\frac{km}{h}$
		=	80 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	24 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 24 km
		=	114 km

Mithra travelled 114 km less than Pugal.

Mithra

Pugal

114km

Total = 646 km

Step 3: 646 km - 114 km = 532 km

Step 4:	Distance travelled by Mithra	→	532 km ÷ 2
		=	266 km

Step 5:	Distance travelled by Pugal	→	266 km + 114 km
		=	380 km

Step 6:	Pugal's speed	→	380 km ÷ 4 $\frac{3}{4}$ h
		=	80 $\frac{km}{h}$

Answer: 83 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	26 km
	5h	→	5 x 26 km
		=	130 km

The lorry travelled 130 km less than the car.

Lorry

Car

130km

Total = 700 km

Step 3: 700 km - 130 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Distance travelled by the car	→	285 km + 130 km
		=	415 km

Step 6:	Car's speed	→	415 km ÷ 5h
		=	83 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	26 km
	5h	→	5 x 26 km
		=	130 km

The lorry travelled 130 km less than the car.

Lorry

Car

130km

Total = 700 km

Step 3: 700 km - 130 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Lorry's speed	→	285 km ÷ 5h
		=	57 $\frac{km}{h}$

Step 6:	Car's speed	→	57 $\frac{km}{h}$ + 26 $\frac{km}{h}$
		=	83 $\frac{km}{h}$

Answer: 77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	10 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 10 km
		=	47.5 km

Chellamal travelled 47.5 km less than Sriram.

Chellamal

Sriram

47.5km

Total = 684 km

Step 3: 684 km - 47.5 km = 636.5 km

Step 4:	Distance travelled by Chellamal	→	636.5 km ÷ 2
		=	318.25 km

Step 5:	Chellamal's speed	→	318.25 km ÷ 4 $\frac{3}{4}$ h
		=	67 $\frac{km}{h}$

Step 6:	Sriram's speed	→	67 $\frac{km}{h}$ + 10 $\frac{km}{h}$
		=	77 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	10 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 10 km
		=	47.5 km

Chellamal travelled 47.5 km less than Sriram.

Chellamal

Sriram

47.5km

Total = 684 km

Step 3: 684 km - 47.5 km = 636.5 km

Step 4:	Distance travelled by Chellamal	→	636.5 km ÷ 2
		=	318.25 km

Step 5:	Distance travelled by Sriram	→	318.25 km + 47.5 km
		=	365.75 km

Step 6:	Sriram's speed	→	365.75 km ÷ 4 $\frac{3}{4}$ h
		=	77 $\frac{km}{h}$

Answer: 77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	20 km
	5h	→	5 x 20 km
		=	100 km

The lorry travelled 100 km less than the car.

Lorry

Car

100km

Total = 670 km

Step 3: 670 km - 100 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Distance travelled by the car	→	285 km + 100 km
		=	385 km

Step 6:	Car's speed	→	385 km ÷ 5h
		=	77 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	20 km
	5h	→	5 x 20 km
		=	100 km

The lorry travelled 100 km less than the car.

Lorry

Car

100km

Total = 670 km

Step 3: 670 km - 100 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Lorry's speed	→	285 km ÷ 5h
		=	57 $\frac{km}{h}$

Step 6:	Car's speed	→	57 $\frac{km}{h}$ + 20 $\frac{km}{h}$
		=	77 $\frac{km}{h}$

Answer: 106 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Nandini travelled 57 km less than Barathan.

Nandini

Barathan

57km

Total = 950 km

Step 3: 950 km - 57 km = 893 km

Step 4:	Distance travelled by Nandini	→	893 km ÷ 2
		=	446.5 km

Step 5:	Nandini's speed	→	446.5 km ÷ 4 $\frac{3}{4}$ h
		=	94 $\frac{km}{h}$

Step 6:	Barathan's speed	→	94 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	106 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Nandini travelled 57 km less than Barathan.

Nandini

Barathan

57km

Total = 950 km

Step 3: 950 km - 57 km = 893 km

Step 4:	Distance travelled by Nandini	→	893 km ÷ 2
		=	446.5 km

Step 5:	Distance travelled by Barathan	→	446.5 km + 57 km
		=	503.5 km

Step 6:	Barathan's speed	→	503.5 km ÷ 4 $\frac{3}{4}$ h
		=	106 $\frac{km}{h}$

10)

Town Lala and Town Yaya are 730 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 24 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 85 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	24 km
	5h	→	5 x 24 km
		=	120 km

The lorry travelled 120 km less than the car.

Lorry

Car

120km

Total = 730 km

Step 3: 730 km - 120 km = 610 km

Step 4:	Distance travelled by the lorry	→	610 km ÷ 2
		=	305 km

Step 5:	Distance travelled by the car	→	305 km + 120 km
		=	425 km

Step 6:	Car's speed	→	425 km ÷ 5h
		=	85 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	24 km
	5h	→	5 x 24 km
		=	120 km

The lorry travelled 120 km less than the car.

Lorry

Car

120km

Total = 730 km

Step 3: 730 km - 120 km = 610 km

Step 4:	Distance travelled by the lorry	→	610 km ÷ 2
		=	305 km

Step 5:	Lorry's speed	→	305 km ÷ 5h
		=	61 $\frac{km}{h}$

Step 6:	Car's speed	→	61 $\frac{km}{h}$ + 24 $\frac{km}{h}$
		=	85 $\frac{km}{h}$