Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (1770)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Town Lala and Town Yaya are 710 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 28 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 836 km apart. At 1045 h Parveen drove from Town A to Town B. At the same time, Chidambaram drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Parveen and Chidambaram passed each other at 1530 h. If Parveen was travelling 10 $\frac{km}{h}$ slower than Chidambaram, find Chidambaram's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 670 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 16 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 874 km apart. At 1045 h Kumutha drove from Town A to Town B. At the same time, Balaji drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Kumutha and Balaji passed each other at 1530 h. If Kumutha was travelling 12 $\frac{km}{h}$ slower than Balaji, find Balaji's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 710 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 16 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 684 km apart. At 1045 h Poongodi drove from Town A to Town B. At the same time, Raj drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Poongodi and Raj passed each other at 1530 h. If Poongodi was travelling 14 $\frac{km}{h}$ slower than Raj, find Raj's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 670 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 10 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 798 km apart. At 1045 h Poovazhagi drove from Town A to Town B. At the same time, Aravindh drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Poovazhagi and Aravindh passed each other at 1530 h. If Poovazhagi was travelling 22 $\frac{km}{h}$ slower than Aravindh, find Aravindh's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 670 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 18 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

10)

Town A and Town B were 646 km apart. At 1045 h Parveen drove from Town A to Town B. At the same time, Chidambaram drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Parveen and Chidambaram passed each other at 1530 h. If Parveen was travelling 18 $\frac{km}{h}$ slower than Chidambaram, find Chidambaram's speed.

$\frac{km}{h}$

Answer:_______________

Answer: 85 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 710 km

Step 3: 710 km - 140 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Distance travelled by the car	→	285 km + 140 km
		=	425 km

Step 6:	Car's speed	→	425 km ÷ 5h
		=	85 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 710 km

Step 3: 710 km - 140 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Lorry's speed	→	285 km ÷ 5h
		=	57 $\frac{km}{h}$

Step 6:	Car's speed	→	57 $\frac{km}{h}$ + 28 $\frac{km}{h}$
		=	85 $\frac{km}{h}$

Answer: 93 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	10 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 10 km
		=	47.5 km

Parveen travelled 47.5 km less than Chidambaram.

Parveen

Chidambaram

47.5km

Total = 836 km

Step 3: 836 km - 47.5 km = 788.5 km

Step 4:	Distance travelled by Parveen	→	788.5 km ÷ 2
		=	394.25 km

Step 5:	Parveen's speed	→	394.25 km ÷ 4 $\frac{3}{4}$ h
		=	83 $\frac{km}{h}$

Step 6:	Chidambaram's speed	→	83 $\frac{km}{h}$ + 10 $\frac{km}{h}$
		=	93 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	10 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 10 km
		=	47.5 km

Parveen travelled 47.5 km less than Chidambaram.

Parveen

Chidambaram

47.5km

Total = 836 km

Step 3: 836 km - 47.5 km = 788.5 km

Step 4:	Distance travelled by Parveen	→	788.5 km ÷ 2
		=	394.25 km

Step 5:	Distance travelled by Chidambaram	→	394.25 km + 47.5 km
		=	441.75 km

Step 6:	Chidambaram's speed	→	441.75 km ÷ 4 $\frac{3}{4}$ h
		=	93 $\frac{km}{h}$

Answer: 75 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	16 km
	5h	→	5 x 16 km
		=	80 km

The lorry travelled 80 km less than the car.

Lorry

Car

80km

Total = 670 km

Step 3: 670 km - 80 km = 590 km

Step 4:	Distance travelled by the lorry	→	590 km ÷ 2
		=	295 km

Step 5:	Distance travelled by the car	→	295 km + 80 km
		=	375 km

Step 6:	Car's speed	→	375 km ÷ 5h
		=	75 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	16 km
	5h	→	5 x 16 km
		=	80 km

The lorry travelled 80 km less than the car.

Lorry

Car

80km

Total = 670 km

Step 3: 670 km - 80 km = 590 km

Step 4:	Distance travelled by the lorry	→	590 km ÷ 2
		=	295 km

Step 5:	Lorry's speed	→	295 km ÷ 5h
		=	59 $\frac{km}{h}$

Step 6:	Car's speed	→	59 $\frac{km}{h}$ + 16 $\frac{km}{h}$
		=	75 $\frac{km}{h}$

Answer: 98 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Kumutha travelled 57 km less than Balaji.

Kumutha

Balaji

57km

Total = 874 km

Step 3: 874 km - 57 km = 817 km

Step 4:	Distance travelled by Kumutha	→	817 km ÷ 2
		=	408.5 km

Step 5:	Kumutha's speed	→	408.5 km ÷ 4 $\frac{3}{4}$ h
		=	86 $\frac{km}{h}$

Step 6:	Balaji's speed	→	86 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	98 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Kumutha travelled 57 km less than Balaji.

Kumutha

Balaji

57km

Total = 874 km

Step 3: 874 km - 57 km = 817 km

Step 4:	Distance travelled by Kumutha	→	817 km ÷ 2
		=	408.5 km

Step 5:	Distance travelled by Balaji	→	408.5 km + 57 km
		=	465.5 km

Step 6:	Balaji's speed	→	465.5 km ÷ 4 $\frac{3}{4}$ h
		=	98 $\frac{km}{h}$

Town Lala and Town Yaya are 710 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 16 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 79 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	16 km
	5h	→	5 x 16 km
		=	80 km

The lorry travelled 80 km less than the car.

Lorry

Car

80km

Total = 710 km

Step 3: 710 km - 80 km = 630 km

Step 4:	Distance travelled by the lorry	→	630 km ÷ 2
		=	315 km

Step 5:	Distance travelled by the car	→	315 km + 80 km
		=	395 km

Step 6:	Car's speed	→	395 km ÷ 5h
		=	79 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	16 km
	5h	→	5 x 16 km
		=	80 km

The lorry travelled 80 km less than the car.

Lorry

Car

80km

Total = 710 km

Step 3: 710 km - 80 km = 630 km

Step 4:	Distance travelled by the lorry	→	630 km ÷ 2
		=	315 km

Step 5:	Lorry's speed	→	315 km ÷ 5h
		=	63 $\frac{km}{h}$

Step 6:	Car's speed	→	63 $\frac{km}{h}$ + 16 $\frac{km}{h}$
		=	79 $\frac{km}{h}$

Answer: 79 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	14 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 14 km
		=	66.5 km

Poongodi travelled 66.5 km less than Raj.

Poongodi

Raj

66.5km

Total = 684 km

Step 3: 684 km - 66.5 km = 617.5 km

Step 4:	Distance travelled by Poongodi	→	617.5 km ÷ 2
		=	308.75 km

Step 5:	Poongodi's speed	→	308.75 km ÷ 4 $\frac{3}{4}$ h
		=	65 $\frac{km}{h}$

Step 6:	Raj's speed	→	65 $\frac{km}{h}$ + 14 $\frac{km}{h}$
		=	79 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	14 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 14 km
		=	66.5 km

Poongodi travelled 66.5 km less than Raj.

Poongodi

Raj

66.5km

Total = 684 km

Step 3: 684 km - 66.5 km = 617.5 km

Step 4:	Distance travelled by Poongodi	→	617.5 km ÷ 2
		=	308.75 km

Step 5:	Distance travelled by Raj	→	308.75 km + 66.5 km
		=	375.25 km

Step 6:	Raj's speed	→	375.25 km ÷ 4 $\frac{3}{4}$ h
		=	79 $\frac{km}{h}$

Town Lala and Town Yaya are 670 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 10 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 72 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	10 km
	5h	→	5 x 10 km
		=	50 km

The lorry travelled 50 km less than the car.

Lorry

Car

50km

Total = 670 km

Step 3: 670 km - 50 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Distance travelled by the car	→	310 km + 50 km
		=	360 km

Step 6:	Car's speed	→	360 km ÷ 5h
		=	72 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	10 km
	5h	→	5 x 10 km
		=	50 km

The lorry travelled 50 km less than the car.

Lorry

Car

50km

Total = 670 km

Step 3: 670 km - 50 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Lorry's speed	→	310 km ÷ 5h
		=	62 $\frac{km}{h}$

Step 6:	Car's speed	→	62 $\frac{km}{h}$ + 10 $\frac{km}{h}$
		=	72 $\frac{km}{h}$

Answer: 95 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Poovazhagi travelled 104.5 km less than Aravindh.

Poovazhagi

Aravindh

104.5km

Total = 798 km

Step 3: 798 km - 104.5 km = 693.5 km

Step 4:	Distance travelled by Poovazhagi	→	693.5 km ÷ 2
		=	346.75 km

Step 5:	Poovazhagi's speed	→	346.75 km ÷ 4 $\frac{3}{4}$ h
		=	73 $\frac{km}{h}$

Step 6:	Aravindh's speed	→	73 $\frac{km}{h}$ + 22 $\frac{km}{h}$
		=	95 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Poovazhagi travelled 104.5 km less than Aravindh.

Poovazhagi

Aravindh

104.5km

Total = 798 km

Step 3: 798 km - 104.5 km = 693.5 km

Step 4:	Distance travelled by Poovazhagi	→	693.5 km ÷ 2
		=	346.75 km

Step 5:	Distance travelled by Aravindh	→	346.75 km + 104.5 km
		=	451.25 km

Step 6:	Aravindh's speed	→	451.25 km ÷ 4 $\frac{3}{4}$ h
		=	95 $\frac{km}{h}$

Town Lala and Town Yaya are 670 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 18 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 76 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	18 km
	5h	→	5 x 18 km
		=	90 km

The lorry travelled 90 km less than the car.

Lorry

Car

90km

Total = 670 km

Step 3: 670 km - 90 km = 580 km

Step 4:	Distance travelled by the lorry	→	580 km ÷ 2
		=	290 km

Step 5:	Distance travelled by the car	→	290 km + 90 km
		=	380 km

Step 6:	Car's speed	→	380 km ÷ 5h
		=	76 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	18 km
	5h	→	5 x 18 km
		=	90 km

The lorry travelled 90 km less than the car.

Lorry

Car

90km

Total = 670 km

Step 3: 670 km - 90 km = 580 km

Step 4:	Distance travelled by the lorry	→	580 km ÷ 2
		=	290 km

Step 5:	Lorry's speed	→	290 km ÷ 5h
		=	58 $\frac{km}{h}$

Step 6:	Car's speed	→	58 $\frac{km}{h}$ + 18 $\frac{km}{h}$
		=	76 $\frac{km}{h}$

10)

Answer: 77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	18 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 18 km
		=	85.5 km

Parveen travelled 85.5 km less than Chidambaram.

Parveen

Chidambaram

85.5km

Total = 646 km

Step 3: 646 km - 85.5 km = 560.5 km

Step 4:	Distance travelled by Parveen	→	560.5 km ÷ 2
		=	280.25 km

Step 5:	Parveen's speed	→	280.25 km ÷ 4 $\frac{3}{4}$ h
		=	59 $\frac{km}{h}$

Step 6:	Chidambaram's speed	→	59 $\frac{km}{h}$ + 18 $\frac{km}{h}$
		=	77 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	18 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 18 km
		=	85.5 km

Parveen travelled 85.5 km less than Chidambaram.

Parveen

Chidambaram

85.5km

Total = 646 km

Step 3: 646 km - 85.5 km = 560.5 km

Step 4:	Distance travelled by Parveen	→	560.5 km ÷ 2
		=	280.25 km

Step 5:	Distance travelled by Chidambaram	→	280.25 km + 85.5 km
		=	365.75 km

Step 6:	Chidambaram's speed	→	365.75 km ÷ 4 $\frac{3}{4}$ h
		=	77 $\frac{km}{h}$