Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (1770)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Town A and Town B were 874 km apart. At 1045 h Ovini drove from Town A to Town B. At the same time, Sriram drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Ovini and Sriram passed each other at 1530 h. If Ovini was travelling 22 $\frac{km}{h}$ slower than Sriram, find Sriram's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 740 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 20 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 950 km apart. At 1045 h Amutha drove from Town A to Town B. At the same time, Kumar drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Amutha and Kumar passed each other at 1530 h. If Amutha was travelling 22 $\frac{km}{h}$ slower than Kumar, find Kumar's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 10 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 836 km apart. At 1045 h Jeevini drove from Town A to Town B. At the same time, Prem drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Jeevini and Prem passed each other at 1530 h. If Jeevini was travelling 20 $\frac{km}{h}$ slower than Prem, find Prem's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 650 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 28 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 836 km apart. At 1045 h Thamarai drove from Town A to Town B. At the same time, Balaji drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Thamarai and Balaji passed each other at 1530 h. If Thamarai was travelling 18 $\frac{km}{h}$ slower than Balaji, find Balaji's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 18 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 608 km apart. At 1045 h Ovini drove from Town A to Town B. At the same time, Moorthi drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Ovini and Moorthi passed each other at 1530 h. If Ovini was travelling 12 $\frac{km}{h}$ slower than Moorthi, find Moorthi's speed.

$\frac{km}{h}$

Answer:_______________

10)

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 16 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Answer: 103 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Ovini travelled 104.5 km less than Sriram.

Ovini

Sriram

104.5km

Total = 874 km

Step 3: 874 km - 104.5 km = 769.5 km

Step 4:	Distance travelled by Ovini	→	769.5 km ÷ 2
		=	384.75 km

Step 5:	Ovini's speed	→	384.75 km ÷ 4 $\frac{3}{4}$ h
		=	81 $\frac{km}{h}$

Step 6:	Sriram's speed	→	81 $\frac{km}{h}$ + 22 $\frac{km}{h}$
		=	103 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Ovini travelled 104.5 km less than Sriram.

Ovini

Sriram

104.5km

Total = 874 km

Step 3: 874 km - 104.5 km = 769.5 km

Step 4:	Distance travelled by Ovini	→	769.5 km ÷ 2
		=	384.75 km

Step 5:	Distance travelled by Sriram	→	384.75 km + 104.5 km
		=	489.25 km

Step 6:	Sriram's speed	→	489.25 km ÷ 4 $\frac{3}{4}$ h
		=	103 $\frac{km}{h}$

Answer: 84 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	20 km
	5h	→	5 x 20 km
		=	100 km

The lorry travelled 100 km less than the car.

Lorry

Car

100km

Total = 740 km

Step 3: 740 km - 100 km = 640 km

Step 4:	Distance travelled by the lorry	→	640 km ÷ 2
		=	320 km

Step 5:	Distance travelled by the car	→	320 km + 100 km
		=	420 km

Step 6:	Car's speed	→	420 km ÷ 5h
		=	84 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	20 km
	5h	→	5 x 20 km
		=	100 km

The lorry travelled 100 km less than the car.

Lorry

Car

100km

Total = 740 km

Step 3: 740 km - 100 km = 640 km

Step 4:	Distance travelled by the lorry	→	640 km ÷ 2
		=	320 km

Step 5:	Lorry's speed	→	320 km ÷ 5h
		=	64 $\frac{km}{h}$

Step 6:	Car's speed	→	64 $\frac{km}{h}$ + 20 $\frac{km}{h}$
		=	84 $\frac{km}{h}$

Answer: 111 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Amutha travelled 104.5 km less than Kumar.

Amutha

Kumar

104.5km

Total = 950 km

Step 3: 950 km - 104.5 km = 845.5 km

Step 4:	Distance travelled by Amutha	→	845.5 km ÷ 2
		=	422.75 km

Step 5:	Amutha's speed	→	422.75 km ÷ 4 $\frac{3}{4}$ h
		=	89 $\frac{km}{h}$

Step 6:	Kumar's speed	→	89 $\frac{km}{h}$ + 22 $\frac{km}{h}$
		=	111 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Amutha travelled 104.5 km less than Kumar.

Amutha

Kumar

104.5km

Total = 950 km

Step 3: 950 km - 104.5 km = 845.5 km

Step 4:	Distance travelled by Amutha	→	845.5 km ÷ 2
		=	422.75 km

Step 5:	Distance travelled by Kumar	→	422.75 km + 104.5 km
		=	527.25 km

Step 6:	Kumar's speed	→	527.25 km ÷ 4 $\frac{3}{4}$ h
		=	111 $\frac{km}{h}$

Answer: 73 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	10 km
	5h	→	5 x 10 km
		=	50 km

The lorry travelled 50 km less than the car.

Lorry

Car

50km

Total = 680 km

Step 3: 680 km - 50 km = 630 km

Step 4:	Distance travelled by the lorry	→	630 km ÷ 2
		=	315 km

Step 5:	Distance travelled by the car	→	315 km + 50 km
		=	365 km

Step 6:	Car's speed	→	365 km ÷ 5h
		=	73 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	10 km
	5h	→	5 x 10 km
		=	50 km

The lorry travelled 50 km less than the car.

Lorry

Car

50km

Total = 680 km

Step 3: 680 km - 50 km = 630 km

Step 4:	Distance travelled by the lorry	→	630 km ÷ 2
		=	315 km

Step 5:	Lorry's speed	→	315 km ÷ 5h
		=	63 $\frac{km}{h}$

Step 6:	Car's speed	→	63 $\frac{km}{h}$ + 10 $\frac{km}{h}$
		=	73 $\frac{km}{h}$

Answer: 98 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	20 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 20 km
		=	95 km

Jeevini travelled 95 km less than Prem.

Jeevini

Prem

95km

Total = 836 km

Step 3: 836 km - 95 km = 741 km

Step 4:	Distance travelled by Jeevini	→	741 km ÷ 2
		=	370.5 km

Step 5:	Jeevini's speed	→	370.5 km ÷ 4 $\frac{3}{4}$ h
		=	78 $\frac{km}{h}$

Step 6:	Prem's speed	→	78 $\frac{km}{h}$ + 20 $\frac{km}{h}$
		=	98 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	20 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 20 km
		=	95 km

Jeevini travelled 95 km less than Prem.

Jeevini

Prem

95km

Total = 836 km

Step 3: 836 km - 95 km = 741 km

Step 4:	Distance travelled by Jeevini	→	741 km ÷ 2
		=	370.5 km

Step 5:	Distance travelled by Prem	→	370.5 km + 95 km
		=	465.5 km

Step 6:	Prem's speed	→	465.5 km ÷ 4 $\frac{3}{4}$ h
		=	98 $\frac{km}{h}$

Answer: 79 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 650 km

Step 3: 650 km - 140 km = 510 km

Step 4:	Distance travelled by the lorry	→	510 km ÷ 2
		=	255 km

Step 5:	Distance travelled by the car	→	255 km + 140 km
		=	395 km

Step 6:	Car's speed	→	395 km ÷ 5h
		=	79 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 650 km

Step 3: 650 km - 140 km = 510 km

Step 4:	Distance travelled by the lorry	→	510 km ÷ 2
		=	255 km

Step 5:	Lorry's speed	→	255 km ÷ 5h
		=	51 $\frac{km}{h}$

Step 6:	Car's speed	→	51 $\frac{km}{h}$ + 28 $\frac{km}{h}$
		=	79 $\frac{km}{h}$

Answer: 97 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	18 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 18 km
		=	85.5 km

Thamarai travelled 85.5 km less than Balaji.

Thamarai

Balaji

85.5km

Total = 836 km

Step 3: 836 km - 85.5 km = 750.5 km

Step 4:	Distance travelled by Thamarai	→	750.5 km ÷ 2
		=	375.25 km

Step 5:	Thamarai's speed	→	375.25 km ÷ 4 $\frac{3}{4}$ h
		=	79 $\frac{km}{h}$

Step 6:	Balaji's speed	→	79 $\frac{km}{h}$ + 18 $\frac{km}{h}$
		=	97 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	18 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 18 km
		=	85.5 km

Thamarai travelled 85.5 km less than Balaji.

Thamarai

Balaji

85.5km

Total = 836 km

Step 3: 836 km - 85.5 km = 750.5 km

Step 4:	Distance travelled by Thamarai	→	750.5 km ÷ 2
		=	375.25 km

Step 5:	Distance travelled by Balaji	→	375.25 km + 85.5 km
		=	460.75 km

Step 6:	Balaji's speed	→	460.75 km ÷ 4 $\frac{3}{4}$ h
		=	97 $\frac{km}{h}$

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 18 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	18 km
	5h	→	5 x 18 km
		=	90 km

The lorry travelled 90 km less than the car.

Lorry

Car

90km

Total = 680 km

Step 3: 680 km - 90 km = 590 km

Step 4:	Distance travelled by the lorry	→	590 km ÷ 2
		=	295 km

Step 5:	Distance travelled by the car	→	295 km + 90 km
		=	385 km

Step 6:	Car's speed	→	385 km ÷ 5h
		=	77 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	18 km
	5h	→	5 x 18 km
		=	90 km

The lorry travelled 90 km less than the car.

Lorry

Car

90km

Total = 680 km

Step 3: 680 km - 90 km = 590 km

Step 4:	Distance travelled by the lorry	→	590 km ÷ 2
		=	295 km

Step 5:	Lorry's speed	→	295 km ÷ 5h
		=	59 $\frac{km}{h}$

Step 6:	Car's speed	→	59 $\frac{km}{h}$ + 18 $\frac{km}{h}$
		=	77 $\frac{km}{h}$

Answer: 70 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Ovini travelled 57 km less than Moorthi.

Ovini

Moorthi

57km

Total = 608 km

Step 3: 608 km - 57 km = 551 km

Step 4:	Distance travelled by Ovini	→	551 km ÷ 2
		=	275.5 km

Step 5:	Ovini's speed	→	275.5 km ÷ 4 $\frac{3}{4}$ h
		=	58 $\frac{km}{h}$

Step 6:	Moorthi's speed	→	58 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	70 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Ovini travelled 57 km less than Moorthi.

Ovini

Moorthi

57km

Total = 608 km

Step 3: 608 km - 57 km = 551 km

Step 4:	Distance travelled by Ovini	→	551 km ÷ 2
		=	275.5 km

Step 5:	Distance travelled by Moorthi	→	275.5 km + 57 km
		=	332.5 km

Step 6:	Moorthi's speed	→	332.5 km ÷ 4 $\frac{3}{4}$ h
		=	70 $\frac{km}{h}$

10)

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 16 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 76 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	16 km
	5h	→	5 x 16 km
		=	80 km

The lorry travelled 80 km less than the car.

Lorry

Car

80km

Total = 680 km

Step 3: 680 km - 80 km = 600 km

Step 4:	Distance travelled by the lorry	→	600 km ÷ 2
		=	300 km

Step 5:	Distance travelled by the car	→	300 km + 80 km
		=	380 km

Step 6:	Car's speed	→	380 km ÷ 5h
		=	76 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	16 km
	5h	→	5 x 16 km
		=	80 km

The lorry travelled 80 km less than the car.

Lorry

Car

80km

Total = 680 km

Step 3: 680 km - 80 km = 600 km

Step 4:	Distance travelled by the lorry	→	600 km ÷ 2
		=	300 km

Step 5:	Lorry's speed	→	300 km ÷ 5h
		=	60 $\frac{km}{h}$

Step 6:	Car's speed	→	60 $\frac{km}{h}$ + 16 $\frac{km}{h}$
		=	76 $\frac{km}{h}$