Sasi Math (Revised for 1024)

Scroll:Measurement >> Area & Perimeter of Composite Figure >> ps (1746)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

14cm 6cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

20cm 6cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

18cm 2cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

22cm 2cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

16cm 6cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

20cm 4cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

16cm 8cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

14cm 4cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

16cm 2cm

___cm²

Answer:_______________

10)

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

14cm 2cm

___cm²

Answer:_______________

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

14cm 6cm

Answer: 132cm²

SOLUTION 1 :

14cm 6cm

Region A = square - quadrant

= (6 cm x 6 cm) - ( $\frac{1}{4}$ x π x 6 cm x 6 cm)

= 36 cm²- 28.278 cm²

= 7.722 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 7.722

= ( $\frac{1}{2}$ x 20 cm x 6 cm) - 7.722 cm²

= 140 cm² - 7.722 cm²

= 132.278 cm²

≈ 132cm²

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

20cm 6cm

Answer: 252cm²

SOLUTION 1 :

20cm 6cm

Region A = square - quadrant

= (6 cm x 6 cm) - ( $\frac{1}{4}$ x π x 6 cm x 6 cm)

= 36 cm²- 28.278 cm²

= 7.722 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 7.722

= ( $\frac{1}{2}$ x 26 cm x 6 cm) - 7.722 cm²

= 260 cm² - 7.722 cm²

= 252.278 cm²

≈ 252cm²

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

18cm 2cm

Answer: 179cm²

SOLUTION 1 :

18cm 2cm

Region A = square - quadrant

= (2 cm x 2 cm) - ( $\frac{1}{4}$ x π x 2 cm x 2 cm)

= 4 cm²- 3.142 cm²

= 0.858 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 0.858

= ( $\frac{1}{2}$ x 20 cm x 2 cm) - 0.858 cm²

= 180 cm² - 0.858 cm²

= 179.142 cm²

≈ 179cm²

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

22cm 2cm

Answer: 263cm²

SOLUTION 1 :

22cm 2cm

Region A = square - quadrant

= (2 cm x 2 cm) - ( $\frac{1}{4}$ x π x 2 cm x 2 cm)

= 4 cm²- 3.142 cm²

= 0.858 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 0.858

= ( $\frac{1}{2}$ x 24 cm x 2 cm) - 0.858 cm²

= 264 cm² - 0.858 cm²

= 263.142 cm²

≈ 263cm²

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

16cm 6cm

Answer: 168cm²

SOLUTION 1 :

16cm 6cm

Region A = square - quadrant

= (6 cm x 6 cm) - ( $\frac{1}{4}$ x π x 6 cm x 6 cm)

= 36 cm²- 28.278 cm²

= 7.722 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 7.722

= ( $\frac{1}{2}$ x 22 cm x 6 cm) - 7.722 cm²

= 176 cm² - 7.722 cm²

= 168.278 cm²

≈ 168cm²

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

20cm 4cm

Answer: 237cm²

SOLUTION 1 :

20cm 4cm

Region A = square - quadrant

= (4 cm x 4 cm) - ( $\frac{1}{4}$ x π x 4 cm x 4 cm)

= 16 cm²- 12.568 cm²

= 3.432 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 3.432

= ( $\frac{1}{2}$ x 24 cm x 4 cm) - 3.432 cm²

= 240 cm² - 3.432 cm²

= 236.568 cm²

≈ 237cm²

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

16cm 8cm

Answer: 178cm²

SOLUTION 1 :

16cm 8cm

Region A = square - quadrant

= (8 cm x 8 cm) - ( $\frac{1}{4}$ x π x 8 cm x 8 cm)

= 64 cm²- 50.272 cm²

= 13.728 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 13.728

= ( $\frac{1}{2}$ x 24 cm x 8 cm) - 13.728 cm²

= 192 cm² - 13.728 cm²

= 178.272 cm²

≈ 178cm²

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

14cm 4cm

Answer: 123cm²

SOLUTION 1 :

14cm 4cm

Region A = square - quadrant

= (4 cm x 4 cm) - ( $\frac{1}{4}$ x π x 4 cm x 4 cm)

= 16 cm²- 12.568 cm²

= 3.432 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 3.432

= ( $\frac{1}{2}$ x 18 cm x 4 cm) - 3.432 cm²

= 126 cm² - 3.432 cm²

= 122.568 cm²

≈ 123cm²

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

16cm 2cm

Answer: 143cm²

SOLUTION 1 :

16cm 2cm

Region A = square - quadrant

= (2 cm x 2 cm) - ( $\frac{1}{4}$ x π x 2 cm x 2 cm)

= 4 cm²- 3.142 cm²

= 0.858 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 0.858

= ( $\frac{1}{2}$ x 18 cm x 2 cm) - 0.858 cm²

= 144 cm² - 0.858 cm²

= 143.142 cm²

≈ 143cm²

10)

The figure is made up of a rectangle, a square and a quadrant. Find the area of the shaded part, rounding off your answer to the nearest whole number.

Π = 3.142

14cm 2cm

Answer: 111cm²

SOLUTION 1 :

14cm 2cm

Region A = square - quadrant

= (2 cm x 2 cm) - ( $\frac{1}{4}$ x π x 2 cm x 2 cm)

= 4 cm²- 3.142 cm²

= 0.858 cm²

Shaded area = triangle - region A

= ( $\frac{1}{2}$ x b x h) - 0.858

= ( $\frac{1}{2}$ x 16 cm x 2 cm) - 0.858 cm²

= 112 cm² - 0.858 cm²

= 111.142 cm²

≈ 111cm²