Sasi Math (Revised for 1024)

Scroll:geometry >> Angles >> saq (1560)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

1)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

74°

^o

Answer:_______________

2)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

50°

^o

Answer:_______________

3)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

44°

^o

Answer:_______________

4)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

64°

^o

Answer:_______________

5)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

70°

^o

Answer:_______________

6)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

48°

^o

Answer:_______________

7)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

56°

^o

Answer:_______________

8)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

72°

^o

Answer:_______________

9)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

76°

^o

Answer:_______________

10)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

46°

^o

Answer:_______________

1)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

74°

Answer: 127 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 74 ^o) ÷ 2 = 53^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 53 ^o = 127^o (sum of angles on a straight line)

2)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

50°

Answer: 115 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 50 ^o) ÷ 2 = 65^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 65 ^o = 115^o (sum of angles on a straight line)

3)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

44°

Answer: 112 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 44 ^o) ÷ 2 = 68^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 68 ^o = 112^o (sum of angles on a straight line)

4)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

64°

Answer: 122 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 64 ^o) ÷ 2 = 58^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 58 ^o = 122^o (sum of angles on a straight line)

5)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

70°

Answer: 125 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 70 ^o) ÷ 2 = 55^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 55 ^o = 125^o (sum of angles on a straight line)

6)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

48°

Answer: 114 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 48 ^o) ÷ 2 = 66^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 66 ^o = 114^o (sum of angles on a straight line)

7)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

56°

Answer: 118 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 56 ^o) ÷ 2 = 62^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 62 ^o = 118^o (sum of angles on a straight line)

8)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

72°

Answer: 126 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 72 ^o) ÷ 2 = 54^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 54 ^o = 126^o (sum of angles on a straight line)

9)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

76°

Answer: 128 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 76 ^o) ÷ 2 = 52^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 52 ^o = 128^o (sum of angles on a straight line)

10)

In triangle PQR, PQ = PR.
PS is a straight line.
Find ∠ RQS.

46°

Answer: 113 ^o

SOLUTION 1 :

Step 1: ∠ PQR = (180 ^o - 46 ^o) ÷ 2 = 67^o (isosceles triangle)

Step 2: ∠ RQS = 180 ^o - 67 ^o = 113^o (sum of angles on a straight line)