Sasi Math (Revised for 1024)

Scroll:Measurement >> Area of Triangle >> ps (1314)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

ABCD is a square of area 64cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a rectangle of area 156cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a square of area 100cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a rectangle of area 160cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a square of area 36cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a rectangle of area 192cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a square of area 16cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a rectangle of area 260cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a square of area 64cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

10)

ABCD is a rectangle of area 132cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

cm²

Answer:_______________

ABCD is a square of area 64cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

Answer: 24 cm²

SOLUTION 1 :

4 cm

8 cm

Step 1: Area of square ABCD → 8 cm x 8 cm = 64 cm²

Step 2: Length of AF → 8 cm ÷ 2 = 4 cm

Step 3: Area of triangle AFE → $\frac{1}{2}$ x 4 cm x 4 cm = 8 cm²

Step 4: Area of triangle CDE → $\frac{1}{2}$ x 4 cm x 8 cm = 16 cm²

Step 5: Area of triangle CBF → $\frac{1}{2}$ x 4 cm x 8 cm = 16 cm²

Step 6: 8 cm² + 16 cm² + 16 cm² = 40cm²

Step 7: 64 cm² - 40 cm² = 24 cm²

ABCD is a rectangle of area 156cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

Answer: 58.5 cm²

SOLUTION 1 :

3 cm

26 cm

Step 1: Area of rectangle ACDE → 26 cm x 6 cm = 156 cm²

Step 2: Length of AB → 26 cm ÷ 2 = 13 cm

Step 3: Lenght of AF → 6 cm ÷ 2 = 3 cm

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 13 cm x 3 cm = 19.5 cm²

Step 5: Area of triangle CDB → $\frac{1}{2}$ x 13 cm x 6 cm = 39 cm²

Step 6: Area of triangle DEF → $\frac{1}{2}$ x 26 cm x 3 cm = 39 cm²

Step 7: 19.5 cm² + 39 cm² + 39 cm² = 97.5cm²

Step 8: Area of shaded triangle → 156 cm² - 97.5 cm² = 58.5 cm²

ABCD is a square of area 100cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

Answer: 37.5 cm²

SOLUTION 1 :

5 cm

10 cm

Step 1: Area of square ABCD → 10 cm x 10 cm = 100 cm²

Step 2: Length of AF → 10 cm ÷ 2 = 5 cm

Step 3: Area of triangle AFE → $\frac{1}{2}$ x 5 cm x 5 cm = 12.5 cm²

Step 4: Area of triangle CDE → $\frac{1}{2}$ x 5 cm x 10 cm = 25 cm²

Step 5: Area of triangle CBF → $\frac{1}{2}$ x 5 cm x 10 cm = 25 cm²

Step 6: 12.5 cm² + 25 cm² + 25 cm² = 62.5cm²

Step 7: 100 cm² - 62.5 cm² = 37.5 cm²

ABCD is a rectangle of area 160cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

Answer: 60 cm²

SOLUTION 1 :

4 cm

20 cm

Step 1: Area of rectangle ACDE → 20 cm x 8 cm = 160 cm²

Step 2: Length of AB → 20 cm ÷ 2 = 10 cm

Step 3: Lenght of AF → 8 cm ÷ 2 = 4 cm

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 10 cm x 4 cm = 20 cm²

Step 5: Area of triangle CDB → $\frac{1}{2}$ x 10 cm x 8 cm = 40 cm²

Step 6: Area of triangle DEF → $\frac{1}{2}$ x 20 cm x 4 cm = 40 cm²

Step 7: 20 cm² + 40 cm² + 40 cm² = 100cm²

Step 8: Area of shaded triangle → 160 cm² - 100 cm² = 60 cm²

ABCD is a square of area 36cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

Answer: 13.5 cm²

SOLUTION 1 :

3 cm

6 cm

Step 1: Area of square ABCD → 6 cm x 6 cm = 36 cm²

Step 2: Length of AF → 6 cm ÷ 2 = 3 cm

Step 3: Area of triangle AFE → $\frac{1}{2}$ x 3 cm x 3 cm = 4.5 cm²

Step 4: Area of triangle CDE → $\frac{1}{2}$ x 3 cm x 6 cm = 9 cm²

Step 5: Area of triangle CBF → $\frac{1}{2}$ x 3 cm x 6 cm = 9 cm²

Step 6: 4.5 cm² + 9 cm² + 9 cm² = 22.5cm²

Step 7: 36 cm² - 22.5 cm² = 13.5 cm²

ABCD is a rectangle of area 192cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

Answer: 72 cm²

SOLUTION 1 :

4 cm

24 cm

Step 1: Area of rectangle ACDE → 24 cm x 8 cm = 192 cm²

Step 2: Length of AB → 24 cm ÷ 2 = 12 cm

Step 3: Lenght of AF → 8 cm ÷ 2 = 4 cm

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 12 cm x 4 cm = 24 cm²

Step 5: Area of triangle CDB → $\frac{1}{2}$ x 12 cm x 8 cm = 48 cm²

Step 6: Area of triangle DEF → $\frac{1}{2}$ x 24 cm x 4 cm = 48 cm²

Step 7: 24 cm² + 48 cm² + 48 cm² = 120cm²

Step 8: Area of shaded triangle → 192 cm² - 120 cm² = 72 cm²

ABCD is a square of area 16cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

Answer: 6 cm²

SOLUTION 1 :

2 cm

4 cm

Step 1: Area of square ABCD → 4 cm x 4 cm = 16 cm²

Step 2: Length of AF → 4 cm ÷ 2 = 2 cm

Step 3: Area of triangle AFE → $\frac{1}{2}$ x 2 cm x 2 cm = 2 cm²

Step 4: Area of triangle CDE → $\frac{1}{2}$ x 2 cm x 4 cm = 4 cm²

Step 5: Area of triangle CBF → $\frac{1}{2}$ x 2 cm x 4 cm = 4 cm²

Step 6: 2 cm² + 4 cm² + 4 cm² = 10cm²

Step 7: 16 cm² - 10 cm² = 6 cm²

ABCD is a rectangle of area 260cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

Answer: 97.5 cm²

SOLUTION 1 :

5 cm

26 cm

Step 1: Area of rectangle ACDE → 26 cm x 10 cm = 260 cm²

Step 2: Length of AB → 26 cm ÷ 2 = 13 cm

Step 3: Lenght of AF → 10 cm ÷ 2 = 5 cm

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 13 cm x 5 cm = 32.5 cm²

Step 5: Area of triangle CDB → $\frac{1}{2}$ x 13 cm x 10 cm = 65 cm²

Step 6: Area of triangle DEF → $\frac{1}{2}$ x 26 cm x 5 cm = 65 cm²

Step 7: 32.5 cm² + 65 cm² + 65 cm² = 162.5cm²

Step 8: Area of shaded triangle → 260 cm² - 162.5 cm² = 97.5 cm²

ABCD is a square of area 64cm² . E and F are midpoints of AD and AB respectively.

Find the area of the shaded triangle.

Answer: 24 cm²

SOLUTION 1 :

4 cm

8 cm

Step 1: Area of square ABCD → 8 cm x 8 cm = 64 cm²

Step 2: Length of AF → 8 cm ÷ 2 = 4 cm

Step 3: Area of triangle AFE → $\frac{1}{2}$ x 4 cm x 4 cm = 8 cm²

Step 4: Area of triangle CDE → $\frac{1}{2}$ x 4 cm x 8 cm = 16 cm²

Step 5: Area of triangle CBF → $\frac{1}{2}$ x 4 cm x 8 cm = 16 cm²

Step 6: 8 cm² + 16 cm² + 16 cm² = 40cm²

Step 7: 64 cm² - 40 cm² = 24 cm²

10)

ABCD is a rectangle of area 132cm² . B and F are midpoints of AC and AE respectively.

Find the area of the shaded triangle.

Answer: 49.5 cm²

SOLUTION 1 :

3 cm

22 cm

Step 1: Area of rectangle ACDE → 22 cm x 6 cm = 132 cm²

Step 2: Length of AB → 22 cm ÷ 2 = 11 cm

Step 3: Lenght of AF → 6 cm ÷ 2 = 3 cm

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 11 cm x 3 cm = 16.5 cm²

Step 5: Area of triangle CDB → $\frac{1}{2}$ x 11 cm x 6 cm = 33 cm²

Step 6: Area of triangle DEF → $\frac{1}{2}$ x 22 cm x 3 cm = 33 cm²

Step 7: 16.5 cm² + 33 cm² + 33 cm² = 82.5cm²

Step 8: Area of shaded triangle → 132 cm² - 82.5 cm² = 49.5 cm²