Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (645)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Mr Goh drove at 82 $\frac{km}{h}$ for 2h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Jeevini drove the first 3h of her journey at 60 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 83 $\frac{km}{h}$ for 1h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Ramani drove the first 3h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 82 $\frac{km}{h}$ for 1h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Haritha drove the first 4h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 71 $\frac{km}{h}$ for 3h and then slowed down to 48 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Amutha drove the first 2h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 75 $\frac{km}{h}$ for 4h and then slowed down to 56 $\frac{km}{h}$ for the next 45 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

10)

Panimalar drove the first 2h of her journey at 60 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Answer: 78.67 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 82 $\frac{km}{h}$	→	82 $\frac{km}{h}$ x 2 h
		=	164 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	164 km + 13 km
		=	177 km

Step 4:	Total time	→	2 h + $\frac{1}{4}$ h
		=	2 $\frac{1}{4}$ h

Step 5:	Average speed	→	177 km ÷ 2 $\frac{1}{4}$ h
		=	78.66667 $\frac{km}{h}$
		≈	78.67 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 60 $\frac{km}{h}$	→	60 $\frac{km}{h}$ x 3 h
		=	180 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 7 h
		=	560 km

Step 3:	Total distance	→	180 km + 560 km
		=	740 km

Step 4:	Total time	→	3 h + 7 h
		=	10 h

Step 5:	Average speed	→	740 km ÷ 10 h
		=	74 $\frac{km}{h}$
		≈	74.00 $\frac{km}{h}$

Answer: 74.40 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 83 $\frac{km}{h}$	→	83 $\frac{km}{h}$ x 1 h
		=	83 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	83 km + 10 km
		=	93 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	93 km ÷ 1 $\frac{1}{4}$ h
		=	74.4 $\frac{km}{h}$
		≈	74.40 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 3 h
		=	150 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 6 h
		=	420 km

Step 3:	Total distance	→	150 km + 420 km
		=	570 km

Step 4:	Total time	→	3 h + 6 h
		=	9 h

Step 5:	Average speed	→	570 km ÷ 9 h
		=	63.33333 $\frac{km}{h}$
		≈	63.33 $\frac{km}{h}$

Answer: 76.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 82 $\frac{km}{h}$	→	82 $\frac{km}{h}$ x 1 h
		=	82 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	82 km + 13 km
		=	95 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	95 km ÷ 1 $\frac{1}{4}$ h
		=	76 $\frac{km}{h}$
		≈	76.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 4 h
		=	180 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 6 h
		=	450 km

Step 3:	Total distance	→	180 km + 450 km
		=	630 km

Step 4:	Total time	→	4 h + 6 h
		=	10 h

Step 5:	Average speed	→	630 km ÷ 10 h
		=	63 $\frac{km}{h}$
		≈	63.00 $\frac{km}{h}$

Answer: 69.23 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 71 $\frac{km}{h}$	→	71 $\frac{km}{h}$ x 3 h
		=	213 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	12 km

Step 3:	Total distance	→	213 km + 12 km
		=	225 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	225 km ÷ 3 $\frac{1}{4}$ h
		=	69.23077 $\frac{km}{h}$
		≈	69.23 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 2 h
		=	90 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 6 h
		=	420 km

Step 3:	Total distance	→	90 km + 420 km
		=	510 km

Step 4:	Total time	→	2 h + 6 h
		=	8 h

Step 5:	Average speed	→	510 km ÷ 8 h
		=	63.75 $\frac{km}{h}$
		≈	63.75 $\frac{km}{h}$

Answer: 72.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 4 h
		=	300 km

Step 2:	Distance covered at a speed of 56 $\frac{km}{h}$	→	56 $\frac{km}{h}$ x $\frac{45}{60}$ h
		=	56 $\frac{km}{h}$ x $\frac{3}{4}$ h
		=	42 km

Step 3:	Total distance	→	300 km + 42 km
		=	342 km

Step 4:	Total time	→	4 h + $\frac{3}{4}$ h
		=	4 $\frac{3}{4}$ h

Step 5:	Average speed	→	342 km ÷ 4 $\frac{3}{4}$ h
		=	72 $\frac{km}{h}$
		≈	72.00 $\frac{km}{h}$

10)

SOLUTION 1 :

Step 1:	Distance covered at a speed of 60 $\frac{km}{h}$	→	60 $\frac{km}{h}$ x 2 h
		=	120 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 6 h
		=	480 km

Step 3:	Total distance	→	120 km + 480 km
		=	600 km

Step 4:	Total time	→	2 h + 6 h
		=	8 h

Step 5:	Average speed	→	600 km ÷ 8 h
		=	75 $\frac{km}{h}$
		≈	75.00 $\frac{km}{h}$