Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (645)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Mr Goh drove at 81 $\frac{km}{h}$ for 1h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Jeevini drove the first 4h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 79 $\frac{km}{h}$ for 2h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Tamilselvi drove the first 4h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 77 $\frac{km}{h}$ for 4h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Keerthi drove the first 4h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 78 $\frac{km}{h}$ for 3h and then slowed down to 56 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Jeevini drove the first 4h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 80 $\frac{km}{h}$ for 1h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

10)

Thamarai drove the first 4h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Answer: 72.80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 81 $\frac{km}{h}$	→	81 $\frac{km}{h}$ x 1 h
		=	81 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	81 km + 10 km
		=	91 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	91 km ÷ 1 $\frac{1}{4}$ h
		=	72.8 $\frac{km}{h}$
		≈	72.80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 4 h
		=	220 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 7 h
		=	525 km

Step 3:	Total distance	→	220 km + 525 km
		=	745 km

Step 4:	Total time	→	4 h + 7 h
		=	11 h

Step 5:	Average speed	→	745 km ÷ 11 h
		=	67.72727 $\frac{km}{h}$
		≈	67.73 $\frac{km}{h}$

Answer: 74.67 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 79 $\frac{km}{h}$	→	79 $\frac{km}{h}$ x 2 h
		=	158 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	158 km + 10 km
		=	168 km

Step 4:	Total time	→	2 h + $\frac{1}{4}$ h
		=	2 $\frac{1}{4}$ h

Step 5:	Average speed	→	168 km ÷ 2 $\frac{1}{4}$ h
		=	74.66667 $\frac{km}{h}$
		≈	74.67 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 4 h
		=	220 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 5 h
		=	400 km

Step 3:	Total distance	→	220 km + 400 km
		=	620 km

Step 4:	Total time	→	4 h + 5 h
		=	9 h

Step 5:	Average speed	→	620 km ÷ 9 h
		=	68.88889 $\frac{km}{h}$
		≈	68.89 $\frac{km}{h}$

Answer: 75.53 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 77 $\frac{km}{h}$	→	77 $\frac{km}{h}$ x 4 h
		=	308 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	308 km + 13 km
		=	321 km

Step 4:	Total time	→	4 h + $\frac{1}{4}$ h
		=	4 $\frac{1}{4}$ h

Step 5:	Average speed	→	321 km ÷ 4 $\frac{1}{4}$ h
		=	75.52941 $\frac{km}{h}$
		≈	75.53 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 4 h
		=	220 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 6 h
		=	450 km

Step 3:	Total distance	→	220 km + 450 km
		=	670 km

Step 4:	Total time	→	4 h + 6 h
		=	10 h

Step 5:	Average speed	→	670 km ÷ 10 h
		=	67 $\frac{km}{h}$
		≈	67.00 $\frac{km}{h}$

Answer: 76.31 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 78 $\frac{km}{h}$	→	78 $\frac{km}{h}$ x 3 h
		=	234 km

Step 2:	Distance covered at a speed of 56 $\frac{km}{h}$	→	56 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	56 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	14 km

Step 3:	Total distance	→	234 km + 14 km
		=	248 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	248 km ÷ 3 $\frac{1}{4}$ h
		=	76.30769 $\frac{km}{h}$
		≈	76.31 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 4 h
		=	220 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 7 h
		=	560 km

Step 3:	Total distance	→	220 km + 560 km
		=	780 km

Step 4:	Total time	→	4 h + 7 h
		=	11 h

Step 5:	Average speed	→	780 km ÷ 11 h
		=	70.90909 $\frac{km}{h}$
		≈	70.91 $\frac{km}{h}$

Answer: 74.40 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 1 h
		=	80 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	80 km + 13 km
		=	93 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	93 km ÷ 1 $\frac{1}{4}$ h
		=	74.4 $\frac{km}{h}$
		≈	74.40 $\frac{km}{h}$

10)

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 4 h
		=	180 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 5 h
		=	375 km

Step 3:	Total distance	→	180 km + 375 km
		=	555 km

Step 4:	Total time	→	4 h + 5 h
		=	9 h

Step 5:	Average speed	→	555 km ÷ 9 h
		=	61.66667 $\frac{km}{h}$
		≈	61.67 $\frac{km}{h}$