Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (645)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Selvanayaki drove the first 4h of her journey at 60 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 75 $\frac{km}{h}$ for 1h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Haritha drove the first 3h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 65 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 69 $\frac{km}{h}$ for 3h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Thamarai drove the first 3h of her journey at 60 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 73 $\frac{km}{h}$ for 2h and then slowed down to 56 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Nandini drove the first 4h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 77 $\frac{km}{h}$ for 1h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Haritha drove the first 3h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

10)

Mr Goh drove at 85 $\frac{km}{h}$ for 1h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

SOLUTION 1 :

Step 1:	Distance covered at a speed of 60 $\frac{km}{h}$	→	60 $\frac{km}{h}$ x 4 h
		=	240 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 7 h
		=	560 km

Step 3:	Total distance	→	240 km + 560 km
		=	800 km

Step 4:	Total time	→	4 h + 7 h
		=	11 h

Step 5:	Average speed	→	800 km ÷ 11 h
		=	72.72727 $\frac{km}{h}$
		≈	72.73 $\frac{km}{h}$

Answer: 68.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 1 h
		=	75 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	75 km + 10 km
		=	85 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	85 km ÷ 1 $\frac{1}{4}$ h
		=	68 $\frac{km}{h}$
		≈	68.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 3 h
		=	165 km

Step 2:	Distance covered at a speed of 65 $\frac{km}{h}$	→	65 $\frac{km}{h}$ x 5 h
		=	325 km

Step 3:	Total distance	→	165 km + 325 km
		=	490 km

Step 4:	Total time	→	3 h + 5 h
		=	8 h

Step 5:	Average speed	→	490 km ÷ 8 h
		=	61.25 $\frac{km}{h}$
		≈	61.25 $\frac{km}{h}$

Answer: 66.77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 69 $\frac{km}{h}$	→	69 $\frac{km}{h}$ x 3 h
		=	207 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	207 km + 10 km
		=	217 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	217 km ÷ 3 $\frac{1}{4}$ h
		=	66.76923 $\frac{km}{h}$
		≈	66.77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 60 $\frac{km}{h}$	→	60 $\frac{km}{h}$ x 3 h
		=	180 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 5 h
		=	400 km

Step 3:	Total distance	→	180 km + 400 km
		=	580 km

Step 4:	Total time	→	3 h + 5 h
		=	8 h

Step 5:	Average speed	→	580 km ÷ 8 h
		=	72.5 $\frac{km}{h}$
		≈	72.50 $\frac{km}{h}$

Answer: 71.11 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 73 $\frac{km}{h}$	→	73 $\frac{km}{h}$ x 2 h
		=	146 km

Step 2:	Distance covered at a speed of 56 $\frac{km}{h}$	→	56 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	56 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	14 km

Step 3:	Total distance	→	146 km + 14 km
		=	160 km

Step 4:	Total time	→	2 h + $\frac{1}{4}$ h
		=	2 $\frac{1}{4}$ h

Step 5:	Average speed	→	160 km ÷ 2 $\frac{1}{4}$ h
		=	71.11111 $\frac{km}{h}$
		≈	71.11 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 4 h
		=	200 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 7 h
		=	525 km

Step 3:	Total distance	→	200 km + 525 km
		=	725 km

Step 4:	Total time	→	4 h + 7 h
		=	11 h

Step 5:	Average speed	→	725 km ÷ 11 h
		=	65.90909 $\frac{km}{h}$
		≈	65.91 $\frac{km}{h}$

Answer: 69.60 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 77 $\frac{km}{h}$	→	77 $\frac{km}{h}$ x 1 h
		=	77 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	77 km + 10 km
		=	87 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	87 km ÷ 1 $\frac{1}{4}$ h
		=	69.6 $\frac{km}{h}$
		≈	69.60 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 3 h
		=	135 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 5 h
		=	400 km

Step 3:	Total distance	→	135 km + 400 km
		=	535 km

Step 4:	Total time	→	3 h + 5 h
		=	8 h

Step 5:	Average speed	→	535 km ÷ 8 h
		=	66.875 $\frac{km}{h}$
		≈	66.88 $\frac{km}{h}$

10)

Answer: 78.40 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 85 $\frac{km}{h}$	→	85 $\frac{km}{h}$ x 1 h
		=	85 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	85 km + 13 km
		=	98 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	98 km ÷ 1 $\frac{1}{4}$ h
		=	78.4 $\frac{km}{h}$
		≈	78.40 $\frac{km}{h}$