Scroll:Operations >> Numbers >> ps (301)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.


 

1)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 18, how many coins are there together


Answer:_______________




2)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 16, how many coins are there together


Answer:_______________




3)  

Indra had a total of 220, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




4)  

Raj had a total of 144, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have


Answer:_______________




5)  

Chithra had a total of 240, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




6)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are thrice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 29, how many coins are there together


Answer:_______________




7)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 72, how many coins are there together


Answer:_______________




8)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 12, how many coins are there together


Answer:_______________




9)  

Poongodi had a total of 380, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




10)  

Pugal had a total of 126, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have


Answer:_______________




 

1)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 18, how many coins are there together

Answer: 150


SOLUTION 1 :
  No. of coins x Value Total Value
10-cent 4u x 0.10 0.40
20-cent 1u x 0.20 0.20
  5u     0.60

Step 1:

18 ÷ 0.60 = 30

Step 2:

4 units (10-cent) + 1 unit (20-cent) = 5 units

5 units = 5 x 30

            =  150


SOLUTION 2 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 + 0.10 = 0.60(1 set)

Step 2:

18 ÷ 0.60 = 30 sets

*Note: 1 set has 5 notes

Step 3:

30 x 5 = 150 notes



2)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 16, how many coins are there together

Answer: 120


SOLUTION 1 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 = 0.40(1 set)

Step 2:

16 ÷ 0.40 = 40 sets

*Note: 1 set has 3 notes

Step 3:

40 x 3 = 120 


SOLUTION 2 :
  No. of coins x Value Total Value
10-cent 2u x 0.10 0.20
20-cent 1u x 0.20 0.20
  3u     0.40

Step 1:

  16 ÷ 0.40 = 40

Step 2:

2 units (10-cent) + 1 unit (20-cent) = 3 units

3 units = 3 x 40

           =  120



3)  

Indra had a total of 220, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have

Answer: 66


SOLUTION 1 :

Grouping method

Step 1:

10 + 2 + 2 + 2 + 2 + 2= 20 (1 set)

Step 2:

220 ÷ 20 = 11 sets

*Note: 1 set has 6 notes

Step 3:

11 x 6 = 66 notes


SOLUTION 2 :
  No.of notes x Value Total Units
10 1 x 10 10U
2 5 x 10 10U
  6     20U

 

Step 1:

20 units = 220

1 unit = 220  ÷ 20

          = 11

Step 2:

5 units (2 notes) + 1 unit (10 notes) = 6 units

6 units = 6 x 11

            = 66 notes



4)  

Raj had a total of 144, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have

Answer: 40


SOLUTION 1 :
  No.of notes x Value Total Units
10 1u x 10 10U
2 4u x 2 8U
  5u     18U

 

Step 1:

18 units = 144

1 unit = 144  ÷ 18

          = 8

Step 2:

4 units (2 notes) + 1 unit (10 notes) = 5 units

5 units = 5 x 8

            = 40 notes


SOLUTION 2 :

Grouping method

Step 1: 10 + 2 + 2 + 2 + 2 = 18(1 set)

Step 2: 144 ÷ 18 = 8 sets

*Note: 1 set has 5 notes

Step 3: 8 x 5 = 40 notes



5)  

Chithra had a total of 240, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have

Answer: 60


SOLUTION 1 :
  No.of notes x Value Total Value
10 1u x 10 10U
2 3u x 2 6U
  4u     16U

 

Step 1:

16 units = 240

1 unit = 240  ÷ 16

          = 15

Step 2:

3 units (2 notes) + 1 unit (10 notes) = 4 units

4 units = 4 x 15

            = 60 notes


SOLUTION 2 :

Grouping method

Step 1:

10 + 2 + 2 + 2 = 16(1 set)

Step 2:

240 ÷ 16 = 15 sets

*Note: 1 set has 4 notes

Step 3:

15 x 4 = 60 notes



6)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are thrice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 29, how many coins are there together

Answer: 232


SOLUTION 1 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 = 0.50(1 set)

Step 2:

29 ÷ 0.50 = 58 sets

*Note: 1 set has 4 notes

Step 3:

58 x 4 = 232 notes


SOLUTION 2 :
  No. of coins x Value Total Value
10-cent 3u x 0.10 0.30
20-cent 1u x 0.20 0.20
  4u     0.50

Step 1:

$29 ÷ 0.50 = 58

Step 2:

3 units (10-cent) + 1 unit (20-cent) = 4 units

4 units = 4 x 58

           =  232



7)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 72, how many coins are there together

Answer: 600


SOLUTION 1 :
  No. of coins x Value Total Value
10-cent 4u x 0.10 0.40
20-cent 1u x 0.20 0.20
  5u     0.60

Step 1:

72 ÷ 0.60 = 120

Step 2:

4 units (10-cent) + 1 unit (20-cent) = 5 units

5 units = 5 x 120

            =  600


SOLUTION 2 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 + 0.10 = 0.60(1 set)

Step 2:

72 ÷ 0.60 = 120 sets

*Note: 1 set has 5 notes

Step 3:

120 x 5 = 600 notes



8)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 12, how many coins are there together

Answer: 90


SOLUTION 1 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 = 0.40(1 set)

Step 2:

12 ÷ 0.40 = 30 sets

*Note: 1 set has 3 notes

Step 3:

30 x 3 = 90 


SOLUTION 2 :
  No. of coins x Value Total Value
10-cent 2u x 0.10 0.20
20-cent 1u x 0.20 0.20
  3u     0.40

Step 1:

  12 ÷ 0.40 = 30

Step 2:

2 units (10-cent) + 1 unit (20-cent) = 3 units

3 units = 3 x 30

           =  90



9)  

Poongodi had a total of 380, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have

Answer: 114


SOLUTION 1 :

Grouping method

Step 1:

10 + 2 + 2 + 2 + 2 + 2= 20 (1 set)

Step 2:

380 ÷ 20 = 19 sets

*Note: 1 set has 6 notes

Step 3:

19 x 6 = 114 notes


SOLUTION 2 :
  No.of notes x Value Total Units
10 1 x 10 10U
2 5 x 10 10U
  6     20U

 

Step 1:

20 units = 380

1 unit = 380  ÷ 20

          = 19

Step 2:

5 units (2 notes) + 1 unit (10 notes) = 6 units

6 units = 6 x 19

            = 114 notes



10)  

Pugal had a total of 126, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have

Answer: 35


SOLUTION 1 :
  No.of notes x Value Total Units
10 1u x 10 10U
2 4u x 2 8U
  5u     18U

 

Step 1:

18 units = 126

1 unit = 126  ÷ 18

          = 7

Step 2:

4 units (2 notes) + 1 unit (10 notes) = 5 units

5 units = 5 x 7

            = 35 notes


SOLUTION 2 :

Grouping method

Step 1: 10 + 2 + 2 + 2 + 2 = 18(1 set)

Step 2: 126 ÷ 18 = 7 sets

*Note: 1 set has 5 notes

Step 3: 7 x 5 = 35 notes