Scroll:Heuristics >> Number X Value >> ps (301)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.


 

1)  

Mithra had a total of 64, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




2)  

Raj had a total of 144, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have


Answer:_______________




3)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 42, how many coins are there together


Answer:_______________




4)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 16, how many coins are there together


Answer:_______________




5)  

Chellamal had a total of 60, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




6)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are thrice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 11, how many coins are there together


Answer:_______________




7)  

Parveen had a total of 224, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




8)  

Anand had a total of 162, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have


Answer:_______________




9)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 84, how many coins are there together


Answer:_______________




10)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 32, how many coins are there together


Answer:_______________




 

1)  

Mithra had a total of 64, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have

Answer: 16


SOLUTION 1 :
  No.of notes x Value Total Value
10 1u x 10 10U
2 3u x 2 6U
  4u     16U

 

Step 1:

16 units = 64

1 unit = 64  ÷ 16

          = 4

Step 2:

3 units (2 notes) + 1 unit (10 notes) = 4 units

4 units = 4 x 4

            = 16 notes


SOLUTION 2 :

Grouping method

Step 1:

10 + 2 + 2 + 2 = 16(1 set)

Step 2:

64 ÷ 16 = 4 sets

*Note: 1 set has 4 notes

Step 3:

4 x 4 = 16 notes



2)  

Raj had a total of 144, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have

Answer: 40


SOLUTION 1 :
  No.of notes x Value Total Units
10 1u x 10 10U
2 4u x 2 8U
  5u     18U

 

Step 1:

18 units = 144

1 unit = 144  ÷ 18

          = 8

Step 2:

4 units (2 notes) + 1 unit (10 notes) = 5 units

5 units = 5 x 8

            = 40 notes


SOLUTION 2 :

Grouping method

Step 1: 10 + 2 + 2 + 2 + 2 = 18(1 set)

Step 2: 144 ÷ 18 = 8 sets

*Note: 1 set has 5 notes

Step 3: 8 x 5 = 40 notes



3)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 42, how many coins are there together

Answer: 350


SOLUTION 1 :
  No. of coins x Value Total Value
10-cent 4u x 0.10 0.40
20-cent 1u x 0.20 0.20
  5u     0.60

Step 1:

42 ÷ 0.60 = 70

Step 2:

4 units (10-cent) + 1 unit (20-cent) = 5 units

5 units = 5 x 70

            =  350


SOLUTION 2 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 + 0.10 = 0.60(1 set)

Step 2:

42 ÷ 0.60 = 70 sets

*Note: 1 set has 5 notes

Step 3:

70 x 5 = 350 notes



4)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 16, how many coins are there together

Answer: 120


SOLUTION 1 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 = 0.40(1 set)

Step 2:

16 ÷ 0.40 = 40 sets

*Note: 1 set has 3 notes

Step 3:

40 x 3 = 120 


SOLUTION 2 :
  No. of coins x Value Total Value
10-cent 2u x 0.10 0.20
20-cent 1u x 0.20 0.20
  3u     0.40

Step 1:

  16 ÷ 0.40 = 40

Step 2:

2 units (10-cent) + 1 unit (20-cent) = 3 units

3 units = 3 x 40

           =  120



5)  

Chellamal had a total of 60, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have

Answer: 18


SOLUTION 1 :

Grouping method

Step 1:

10 + 2 + 2 + 2 + 2 + 2= 20 (1 set)

Step 2:

60 ÷ 20 = 3 sets

*Note: 1 set has 6 notes

Step 3:

3 x 6 = 18 notes


SOLUTION 2 :
  No.of notes x Value Total Units
10 1 x 10 10U
2 5 x 10 10U
  6     20U

 

Step 1:

20 units = 60

1 unit = 60  ÷ 20

          = 3

Step 2:

5 units (2 notes) + 1 unit (10 notes) = 6 units

6 units = 6 x 3

            = 18 notes



6)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are thrice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 11, how many coins are there together

Answer: 88


SOLUTION 1 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 = 0.50(1 set)

Step 2:

11 ÷ 0.50 = 22 sets

*Note: 1 set has 4 notes

Step 3:

22 x 4 = 88 notes


SOLUTION 2 :
  No. of coins x Value Total Value
10-cent 3u x 0.10 0.30
20-cent 1u x 0.20 0.20
  4u     0.50

Step 1:

$11 ÷ 0.50 = 22

Step 2:

3 units (10-cent) + 1 unit (20-cent) = 4 units

4 units = 4 x 22

           =  88



7)  

Parveen had a total of 224, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have

Answer: 56


SOLUTION 1 :
  No.of notes x Value Total Value
10 1u x 10 10U
2 3u x 2 6U
  4u     16U

 

Step 1:

16 units = 224

1 unit = 224  ÷ 16

          = 14

Step 2:

3 units (2 notes) + 1 unit (10 notes) = 4 units

4 units = 4 x 14

            = 56 notes


SOLUTION 2 :

Grouping method

Step 1:

10 + 2 + 2 + 2 = 16(1 set)

Step 2:

224 ÷ 16 = 14 sets

*Note: 1 set has 4 notes

Step 3:

14 x 4 = 56 notes



8)  

Anand had a total of 162, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have

Answer: 45


SOLUTION 1 :
  No.of notes x Value Total Units
10 1u x 10 10U
2 4u x 2 8U
  5u     18U

 

Step 1:

18 units = 162

1 unit = 162  ÷ 18

          = 9

Step 2:

4 units (2 notes) + 1 unit (10 notes) = 5 units

5 units = 5 x 9

            = 45 notes


SOLUTION 2 :

Grouping method

Step 1: 10 + 2 + 2 + 2 + 2 = 18(1 set)

Step 2: 162 ÷ 18 = 9 sets

*Note: 1 set has 5 notes

Step 3: 9 x 5 = 45 notes



9)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 84, how many coins are there together

Answer: 700


SOLUTION 1 :
  No. of coins x Value Total Value
10-cent 4u x 0.10 0.40
20-cent 1u x 0.20 0.20
  5u     0.60

Step 1:

84 ÷ 0.60 = 140

Step 2:

4 units (10-cent) + 1 unit (20-cent) = 5 units

5 units = 5 x 140

            =  700


SOLUTION 2 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 + 0.10 = 0.60(1 set)

Step 2:

84 ÷ 0.60 = 140 sets

*Note: 1 set has 5 notes

Step 3:

140 x 5 = 700 notes



10)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 32, how many coins are there together

Answer: 240


SOLUTION 1 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 = 0.40(1 set)

Step 2:

32 ÷ 0.40 = 80 sets

*Note: 1 set has 3 notes

Step 3:

80 x 3 = 240 


SOLUTION 2 :
  No. of coins x Value Total Value
10-cent 2u x 0.10 0.20
20-cent 1u x 0.20 0.20
  3u     0.40

Step 1:

  32 ÷ 0.40 = 80

Step 2:

2 units (10-cent) + 1 unit (20-cent) = 3 units

3 units = 3 x 80

           =  240