Scroll:Whole Numbers >> Other Heuristics >> ps (301)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.


 

1)  

Raj had a total of 144, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have


Answer:_______________




2)  

Savithri had a total of 320, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




3)  

Jeevini had a total of 272, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




4)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 36, how many coins are there together


Answer:_______________




5)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are thrice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 40, how many coins are there together


Answer:_______________




6)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 36, how many coins are there together


Answer:_______________




7)  

Kumar had a total of 162, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have


Answer:_______________




8)  

Haritha had a total of 140, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




9)  

Haritha had a total of 48, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have


Answer:_______________




10)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 66, how many coins are there together


Answer:_______________




 

1)  

Raj had a total of 144, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have

Answer: 40


SOLUTION 1 :
  No.of notes x Value Total Units
10 1u x 10 10U
2 4u x 2 8U
  5u     18U

 

Step 1:

18 units = 144

1 unit = 144  ÷ 18

          = 8

Step 2:

4 units (2 notes) + 1 unit (10 notes) = 5 units

5 units = 5 x 8

            = 40 notes


SOLUTION 2 :

Grouping method

Step 1: 10 + 2 + 2 + 2 + 2 = 18(1 set)

Step 2: 144 ÷ 18 = 8 sets

*Note: 1 set has 5 notes

Step 3: 8 x 5 = 40 notes



2)  

Savithri had a total of 320, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have

Answer: 96


SOLUTION 1 :

Grouping method

Step 1:

10 + 2 + 2 + 2 + 2 + 2= 20 (1 set)

Step 2:

320 ÷ 20 = 16 sets

*Note: 1 set has 6 notes

Step 3:

16 x 6 = 96 notes


SOLUTION 2 :
  No.of notes x Value Total Units
10 1 x 10 10U
2 5 x 10 10U
  6     20U

 

Step 1:

20 units = 320

1 unit = 320  ÷ 20

          = 16

Step 2:

5 units (2 notes) + 1 unit (10 notes) = 6 units

6 units = 6 x 16

            = 96 notes



3)  

Jeevini had a total of 272, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have

Answer: 68


SOLUTION 1 :
  No.of notes x Value Total Value
10 1u x 10 10U
2 3u x 2 6U
  4u     16U

 

Step 1:

16 units = 272

1 unit = 272  ÷ 16

          = 17

Step 2:

3 units (2 notes) + 1 unit (10 notes) = 4 units

4 units = 4 x 17

            = 68 notes


SOLUTION 2 :

Grouping method

Step 1:

10 + 2 + 2 + 2 = 16(1 set)

Step 2:

272 ÷ 16 = 17 sets

*Note: 1 set has 4 notes

Step 3:

17 x 4 = 68 notes



4)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 36, how many coins are there together

Answer: 300


SOLUTION 1 :
  No. of coins x Value Total Value
10-cent 4u x 0.10 0.40
20-cent 1u x 0.20 0.20
  5u     0.60

Step 1:

36 ÷ 0.60 = 60

Step 2:

4 units (10-cent) + 1 unit (20-cent) = 5 units

5 units = 5 x 60

            =  300


SOLUTION 2 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 + 0.10 = 0.60(1 set)

Step 2:

36 ÷ 0.60 = 60 sets

*Note: 1 set has 5 notes

Step 3:

60 x 5 = 300 notes



5)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are thrice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 40, how many coins are there together

Answer: 320


SOLUTION 1 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 = 0.50(1 set)

Step 2:

40 ÷ 0.50 = 80 sets

*Note: 1 set has 4 notes

Step 3:

80 x 4 = 320 notes


SOLUTION 2 :
  No. of coins x Value Total Value
10-cent 3u x 0.10 0.30
20-cent 1u x 0.20 0.20
  4u     0.50

Step 1:

$40 ÷ 0.50 = 80

Step 2:

3 units (10-cent) + 1 unit (20-cent) = 4 units

4 units = 4 x 80

           =  320



6)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are twice as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 36, how many coins are there together

Answer: 270


SOLUTION 1 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 = 0.40(1 set)

Step 2:

36 ÷ 0.40 = 90 sets

*Note: 1 set has 3 notes

Step 3:

90 x 3 = 270 


SOLUTION 2 :
  No. of coins x Value Total Value
10-cent 2u x 0.10 0.20
20-cent 1u x 0.20 0.20
  3u     0.40

Step 1:

  36 ÷ 0.40 = 90

Step 2:

2 units (10-cent) + 1 unit (20-cent) = 3 units

3 units = 3 x 90

           =  270



7)  

Kumar had a total of 162, consisting of 10 and 2 notes. Given that he had four times as many 2 notes as 10 notes, how many notes did he have

Answer: 45


SOLUTION 1 :
  No.of notes x Value Total Units
10 1u x 10 10U
2 4u x 2 8U
  5u     18U

 

Step 1:

18 units = 162

1 unit = 162  ÷ 18

          = 9

Step 2:

4 units (2 notes) + 1 unit (10 notes) = 5 units

5 units = 5 x 9

            = 45 notes


SOLUTION 2 :

Grouping method

Step 1: 10 + 2 + 2 + 2 + 2 = 18(1 set)

Step 2: 162 ÷ 18 = 9 sets

*Note: 1 set has 5 notes

Step 3: 9 x 5 = 45 notes



8)  

Haritha had a total of 140, consisting of 10 and 2 notes. Given that she had five times as many 2 notes as 10 notes, how many notes did she have

Answer: 42


SOLUTION 1 :

Grouping method

Step 1:

10 + 2 + 2 + 2 + 2 + 2= 20 (1 set)

Step 2:

140 ÷ 20 = 7 sets

*Note: 1 set has 6 notes

Step 3:

7 x 6 = 42 notes


SOLUTION 2 :
  No.of notes x Value Total Units
10 1 x 10 10U
2 5 x 10 10U
  6     20U

 

Step 1:

20 units = 140

1 unit = 140  ÷ 20

          = 7

Step 2:

5 units (2 notes) + 1 unit (10 notes) = 6 units

6 units = 6 x 7

            = 42 notes



9)  

Haritha had a total of 48, consisting of 10 and 2 notes. Given that she had three times as many 2 notes as 10 notes, how many notes did she have

Answer: 12


SOLUTION 1 :
  No.of notes x Value Total Value
10 1u x 10 10U
2 3u x 2 6U
  4u     16U

 

Step 1:

16 units = 48

1 unit = 48  ÷ 16

          = 3

Step 2:

3 units (2 notes) + 1 unit (10 notes) = 4 units

4 units = 4 x 3

            = 12 notes


SOLUTION 2 :

Grouping method

Step 1:

10 + 2 + 2 + 2 = 16(1 set)

Step 2:

48 ÷ 16 = 3 sets

*Note: 1 set has 4 notes

Step 3:

3 x 4 = 12 notes



10)  

There are some coins in a box. The coins consist of 10-cent and 20-cent coins. There are four times as many 10-cent coins as 20-cent coins. If the total amount of money in the box is 66, how many coins are there together

Answer: 550


SOLUTION 1 :
  No. of coins x Value Total Value
10-cent 4u x 0.10 0.40
20-cent 1u x 0.20 0.20
  5u     0.60

Step 1:

66 ÷ 0.60 = 110

Step 2:

4 units (10-cent) + 1 unit (20-cent) = 5 units

5 units = 5 x 110

            =  550


SOLUTION 2 :

Grouping method

Step 1:

0.20 + 0.10 + 0.10 + 0.10 + 0.10 = 0.60(1 set)

Step 2:

66 ÷ 0.60 = 110 sets

*Note: 1 set has 5 notes

Step 3:

110 x 5 = 550 notes