Scroll:Whole Numbers >> Other Heuristics >> ps (134)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.


 

1)  

Ramani has some 5-gram and 10-gram weights. The weights add up to 160 g. There are 2 more 5-gram weights than 10-gram weights.

How many 5-gram weights and 10-gram weights does Ramani have

ten-gram weights

five-gram weights



Answer:_______________




2)  

Ovini has some 20-cent coins and 50-cent coins. The coins add up to $144.20. There are 21 more 20-cent coins than 50-cent coins.

How many 20-cent coins and 50-cent coins Ovini has 

twenty-cent coins

fifty-cent coins




Answer:_______________




3)  

Thamarai has some 5-cent and 10-cent coins. The coins add up to 140 cents. There are 7 more 5-cent coins than 10-cent coins. How many 5-cent coins than 10-cent coins.

How many 5-cent coins and 10-cent coins has Thamarai got

five-cent coins

ten-cent coins


Answer:_______________




4)  

Panimalar has some 5-gram and 10-gram weights. The weights add up to 160 g. There are 5 more 5-gram weights than 10-gram weights.

How many 5-gram weights and 10-gram weights does Panimalar have

ten-gram weights

five-gram weights



Answer:_______________




5)  

Haritha has some 20-cent coins and 50-cent coins. The coins add up to $145.60. There are 28 more 20-cent coins than 50-cent coins.

How many 20-cent coins and 50-cent coins Haritha has 

twenty-cent coins

fifty-cent coins




Answer:_______________




6)  

Selvanayaki has some 5-cent and 10-cent coins. The coins add up to 155 cents. There are 4 more 5-cent coins than 10-cent coins. How many 5-cent coins than 10-cent coins.

How many 5-cent coins and 10-cent coins has Selvanayaki got

five-cent coins

ten-cent coins


Answer:_______________




7)  

Keerthi has some 5-gram and 10-gram weights. The weights add up to 130 g. There are 2 more 5-gram weights than 10-gram weights.

How many 5-gram weights and 10-gram weights does Keerthi have

ten-gram weights

five-gram weights



Answer:_______________




8)  

Poongodi has some 20-cent coins and 50-cent coins. The coins add up to $147.80. There are 4 more 20-cent coins than 50-cent coins.

How many 20-cent coins and 50-cent coins Poongodi has 

twenty-cent coins

fifty-cent coins




Answer:_______________




9)  

Poongodi has some 5-cent and 10-cent coins. The coins add up to 210 cents. There are 3 more 5-cent coins than 10-cent coins. How many 5-cent coins than 10-cent coins.

How many 5-cent coins and 10-cent coins has Poongodi got

five-cent coins

ten-cent coins


Answer:_______________




10)  

Selvanayaki has some 5-gram and 10-gram weights. The weights add up to 165 g. There are 3 more 5-gram weights than 10-gram weights.

How many 5-gram weights and 10-gram weights does Selvanayaki have

ten-gram weights

five-gram weights



Answer:_______________




 

1)  

Ramani has some 5-gram and 10-gram weights. The weights add up to 160 g. There are 2 more 5-gram weights than 10-gram weights.

How many 5-gram weights and 10-gram weights does Ramani have

Answer: 10 ten-gram weights

Answer: 12 five-gram weights



SOLUTION 1 :

There are 2 more 5-gram weights than 10-gram weights.

 Step 1: The value of the 2 (5-gram weights) → 2 x 5 g
     = 10 g
 Step 2: 160 g - 10 g  = 150 g
 Step 3: 5 g + 10 g  = 15 g (1 set)
 Step 4: 150 g ÷ 15 g = 10 (10-gram weights)
 Step 5: 10 + 2  = 12 (5-gram weights)

 

 

 

Ramani has 12 five-gram weights and 10 ten-gram weights



2)  

Ovini has some 20-cent coins and 50-cent coins. The coins add up to $144.20. There are 21 more 20-cent coins than 50-cent coins.

How many 20-cent coins and 50-cent coins Ovini has 

Answer: 221 twenty-cent coins

Answer: 200 fifty-cent coins




SOLUTION 1 :

There are 21 more 20-cent coins than 50-cent coins.

 Step 1: The value of the 21 (20-cent coins) → 21 x 20
     = 420 cents
     = $4.20
 Step 2: $144.20 - $4.20  = $140.00
 Step 3: The value of each set of one 20-cent and one 50-cent coins is  = 20 + 50
     = 70 cents (1 set)
     = $0.70
 Step 4: $140.00 ÷ $0.70 = 200 (50-cent coins)
 Step 5: 200 + 21  = 221 (20-cent coins)

 

 Ovini has 221 twenty-cent coins and 200 fifty-cent coins.



3)  

Thamarai has some 5-cent and 10-cent coins. The coins add up to 140 cents. There are 7 more 5-cent coins than 10-cent coins. How many 5-cent coins than 10-cent coins.

How many 5-cent coins and 10-cent coins has Thamarai got

Answer: 14 five-cent coins

Answer: 7 ten-cent coins


SOLUTION 1 :

There are 7 more 5-cent coins then 10-cent coins.

 Step 1: The value of the 7 five-cent coins → 7 x 5
     = 35 cents
 Step 2: 140 cents - 35 cents  = 105 cents
 Step 3: The value of 1 set of 1 five-cent coin and 1 ten-cent coin → 5 cents + 10 cents
     = 15 cents
 Step 4: 105 ÷ 15 cents  = 7 (10-cent coins)
  7 + 7  = 14 (5-cent coins)

 

 Thamarai has 14 five-cent coins and 7 ten-cent coins.



4)  

Panimalar has some 5-gram and 10-gram weights. The weights add up to 160 g. There are 5 more 5-gram weights than 10-gram weights.

How many 5-gram weights and 10-gram weights does Panimalar have

Answer: 9 ten-gram weights

Answer: 14 five-gram weights



SOLUTION 1 :

There are 5 more 5-gram weights than 10-gram weights.

 Step 1: The value of the 5 (5-gram weights) → 5 x 5 g
     = 25 g
 Step 2: 160 g - 25 g  = 135 g
 Step 3: 5 g + 10 g  = 15 g (1 set)
 Step 4: 135 g ÷ 15 g = 9 (10-gram weights)
 Step 5: 9 + 5  = 14 (5-gram weights)

 

 

 

Panimalar has 14 five-gram weights and 9 ten-gram weights



5)  

Haritha has some 20-cent coins and 50-cent coins. The coins add up to $145.60. There are 28 more 20-cent coins than 50-cent coins.

How many 20-cent coins and 50-cent coins Haritha has 

Answer: 228 twenty-cent coins

Answer: 200 fifty-cent coins




SOLUTION 1 :

There are 28 more 20-cent coins than 50-cent coins.

 Step 1: The value of the 28 (20-cent coins) → 28 x 20
     = 560 cents
     = $5.60
 Step 2: $145.60 - $5.60  = $140.00
 Step 3: The value of each set of one 20-cent and one 50-cent coins is  = 20 + 50
     = 70 cents (1 set)
     = $0.70
 Step 4: $140.00 ÷ $0.70 = 200 (50-cent coins)
 Step 5: 200 + 28  = 228 (20-cent coins)

 

 Haritha has 228 twenty-cent coins and 200 fifty-cent coins.



6)  

Selvanayaki has some 5-cent and 10-cent coins. The coins add up to 155 cents. There are 4 more 5-cent coins than 10-cent coins. How many 5-cent coins than 10-cent coins.

How many 5-cent coins and 10-cent coins has Selvanayaki got

Answer: 13 five-cent coins

Answer: 9 ten-cent coins


SOLUTION 1 :

There are 4 more 5-cent coins then 10-cent coins.

 Step 1: The value of the 4 five-cent coins → 4 x 5
     = 20 cents
 Step 2: 155 cents - 20 cents  = 135 cents
 Step 3: The value of 1 set of 1 five-cent coin and 1 ten-cent coin → 5 cents + 10 cents
     = 15 cents
 Step 4: 135 ÷ 15 cents  = 9 (10-cent coins)
  9 + 4  = 13 (5-cent coins)

 

 Selvanayaki has 13 five-cent coins and 9 ten-cent coins.



7)  

Keerthi has some 5-gram and 10-gram weights. The weights add up to 130 g. There are 2 more 5-gram weights than 10-gram weights.

How many 5-gram weights and 10-gram weights does Keerthi have

Answer: 8 ten-gram weights

Answer: 10 five-gram weights



SOLUTION 1 :

There are 2 more 5-gram weights than 10-gram weights.

 Step 1: The value of the 2 (5-gram weights) → 2 x 5 g
     = 10 g
 Step 2: 130 g - 10 g  = 120 g
 Step 3: 5 g + 10 g  = 15 g (1 set)
 Step 4: 120 g ÷ 15 g = 8 (10-gram weights)
 Step 5: 8 + 2  = 10 (5-gram weights)

 

 

 

Keerthi has 10 five-gram weights and 8 ten-gram weights



8)  

Poongodi has some 20-cent coins and 50-cent coins. The coins add up to $147.80. There are 4 more 20-cent coins than 50-cent coins.

How many 20-cent coins and 50-cent coins Poongodi has 

Answer: 214 twenty-cent coins

Answer: 210 fifty-cent coins




SOLUTION 1 :

There are 4 more 20-cent coins than 50-cent coins.

 Step 1: The value of the 4 (20-cent coins) → 4 x 20
     = 80 cents
     = $0.80
 Step 2: $147.80 - $0.80  = $147.00
 Step 3: The value of each set of one 20-cent and one 50-cent coins is  = 20 + 50
     = 70 cents (1 set)
     = $0.70
 Step 4: $147.00 ÷ $0.70 = 210 (50-cent coins)
 Step 5: 210 + 4  = 214 (20-cent coins)

 

 Poongodi has 214 twenty-cent coins and 210 fifty-cent coins.



9)  

Poongodi has some 5-cent and 10-cent coins. The coins add up to 210 cents. There are 3 more 5-cent coins than 10-cent coins. How many 5-cent coins than 10-cent coins.

How many 5-cent coins and 10-cent coins has Poongodi got

Answer: 16 five-cent coins

Answer: 13 ten-cent coins


SOLUTION 1 :

There are 3 more 5-cent coins then 10-cent coins.

 Step 1: The value of the 3 five-cent coins → 3 x 5
     = 15 cents
 Step 2: 210 cents - 15 cents  = 195 cents
 Step 3: The value of 1 set of 1 five-cent coin and 1 ten-cent coin → 5 cents + 10 cents
     = 15 cents
 Step 4: 195 ÷ 15 cents  = 13 (10-cent coins)
  13 + 3  = 16 (5-cent coins)

 

 Poongodi has 16 five-cent coins and 13 ten-cent coins.



10)  

Selvanayaki has some 5-gram and 10-gram weights. The weights add up to 165 g. There are 3 more 5-gram weights than 10-gram weights.

How many 5-gram weights and 10-gram weights does Selvanayaki have

Answer: 10 ten-gram weights

Answer: 13 five-gram weights



SOLUTION 1 :

There are 3 more 5-gram weights than 10-gram weights.

 Step 1: The value of the 3 (5-gram weights) → 3 x 5 g
     = 15 g
 Step 2: 165 g - 15 g  = 150 g
 Step 3: 5 g + 10 g  = 15 g (1 set)
 Step 4: 150 g ÷ 15 g = 10 (10-gram weights)
 Step 5: 10 + 3  = 13 (5-gram weights)

 

 

 

Selvanayaki has 13 five-gram weights and 10 ten-gram weights